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Chapter 18: Problem 33

Rays are converging towards a convex mirror, final image will be (A) Real (B) Virtual (C) May be real or virtual (D) Image will not form

Short Answer

Expert verified
(B) Virtual

Step by step solution

01

Recall the properties of a convex mirror

A convex mirror has a reflecting surface that curves outward, away from the viewer. Because of this, when parallel light rays strike the surface, they diverge 鈥� light rays spread out 鈥� upon reflection. A simple way to remember this is that convex mirrors cause light rays to "bend away" from the mirror's surface.
02

Analyze the given scenario

In our given scenario, rays are converging toward the convex mirror. In this case, the light rays aren't parallel when striking the surface, so it's essential to analyze how they will reflect off the convex mirror.
03

Determine the path of reflected light rays

Regardless of whether the light rays are parallel or converging, they will still diverge after reflecting off a convex mirror. In other words, after striking the convex mirror, the light rays will spread out (reflect away from each other).
04

Determine the nature of the final image

Since the light rays diverge after reflecting off the convex mirror, they never reconverge again to form a real image. A real image is formed when reflected rays meet or reconverge at a point in space. However, when we trace the diverging light rays backward (as if they were reflected from a different point behind the mirror), they appear to originate from a single point 鈥� this forms a virtual image.
05

Step \helpers.capitalize(ord('5')): Choose the correct answer

By analyzing the properties of a convex mirror and how light rays reflect off its surface, we can conclude that the final image will be a virtual image. Therefore, the correct answer is: (B) Virtual

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Most popular questions from this chapter

If two mirrors are kept at \(60^{\circ}\) to each other, then the number of images formed by them is \([\mathbf{2 0 0 2}]\) (A) 5 (B) 6 (C) 7 (D) 8

A plane mirror is placed at the bottom of a tank containing a liquid of refractive index \(\mu, P\) is a small object at a height \(h\) above the plane mirror. An observer \(O\), vertically above \(P\), outside the liquid, observers \(P\) and its image in the mirror. The apparent distance between object and its image will be Plane mi (A) \(2 \mu h\) (B) \(\frac{2 h}{\mu}\) (C) \(\frac{2 h}{\mu-1}\) (D) \(h\left(\frac{1}{\mu}\right)\)

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