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The sun radiates electromagnetic energy at the rate of \(3.9 \times 10^{26} \mathrm{~W}\). Its radius is \(6.96 \times 10^{8} \mathrm{~m}\). The intensity of sun light at the solar surface will be (A) \(1.4 \times 10^{4}\) (B) \(2.8 \times 10^{5}\) (C) \(4.2 \times 10^{6}\) (D) \(5.6 \times 10^{7}\)

Short Answer

Expert verified
The intensity of sunlight at the solar surface is approximately 6.33 × 10^7 W/m², which is closest to option (D) 5.6 × 10^7.

Step by step solution

01

Compute the surface area of the sun

To calculate the surface area of the sun, we will be using the formula for the surface area of a sphere, which is given by: Surface Area (A) = 4πR² where R is the radius of the sphere (the sun). The radius of the sun, R, is given as 6.96 × 10^8 meters. We can now calculate the surface area of the sun: A = 4π(6.96 × 10^8)²
02

Calculate the intensity of sunlight at the solar surface

Now that we have computed the surface area of the sun, we can use the formula for intensity mentioned earlier: Intensity (I) = Power/Area The power radiated by the sun is given as 3.9 × 10^26 W and the surface area of the sun has been calculated in Step 1. So, the intensity of sunlight at the solar surface is: I = (3.9 × 10^26)/(4π(6.96 × 10^8)²)
03

Solve the expression and find the correct option

After solving the expression, we obtain the intensity I to be approximately 6.33 × 10^7 W/m². We can now compare this to the given options to find the answer: (A) 1.4 × 10^4 (too low) (B) 2.8 × 10^5 ( too low) (C) 4.2 × 10^6 (too low) (D) 5.6 × 10^7 (closest value) The correct option is (D) 5.6 × 10^7.

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