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Chapter 17: Problem 31

The nature of electromagnetic wave is (A) Longitudinal (B) Longitudinal stationary (C) Transverse (D) Transverse stationary

Short Answer

Expert verified
The nature of an electromagnetic wave is (C) Transverse.

Step by step solution

01

1. Recall the basic properties of electromagnetic waves

Electromagnetic waves are a type of wave that can travel through a vacuum, like space, or through a medium, like air or glass. They consist of oscillating electric fields and magnetic fields that are perpendicular to each other and to the direction of propagation.
02

2. Compare the properties of electromagnetic waves with the given options

We have 4 options for the nature of an electromagnetic wave: (A) Longitudinal: In longitudinal waves, the oscillations are along the direction of propagation. Since the electric and magnetic fields of an electromagnetic wave are perpendicular to the direction of propagation, electromagnetic waves are not longitudinal. So, this option is incorrect. (B) Longitudinal stationary: As we already discussed, electromagnetic waves are not longitudinal, so this option is also incorrect. (C) Transverse: In transverse waves, the oscillations are perpendicular to the direction of propagation. Since the electric and magnetic fields of an electromagnetic wave are perpendicular to the direction of propagation, they can be classified as transverse. So, this option is correct. (D) Transverse stationary: Electromagnetic waves are transverse but not stationary as they can propagate through space and medium. So, this option is incorrect.
03

3. Select the correct answer

Based on the comparisons made in step 2, we can conclude that the nature of an electromagnetic wave is (C) Transverse.

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Most popular questions from this chapter

The Maxwell's four equations are written as (i) \(\oint \vec{E} \cdot \overrightarrow{d s}=\frac{q_{0}}{\varepsilon_{0}}\) (ii) \(\oint \vec{B} \cdot \overrightarrow{d s}=0\) (iii) \(\oint \vec{E} \cdot \overrightarrow{d l}=\frac{d}{d t} \oint \vec{B} \cdot \overrightarrow{d s}\) (iv) \(\oint \vec{B} \cdot \overrightarrow{d s}=\mu_{0} \varepsilon_{0} \frac{d}{d t} \oint \vec{E} \cdot \overrightarrow{d s}\) The equations which have sources of \(\vec{E}\) and \(\vec{B}\) (A) (i), (ii) and (iii) (B) (i) and (ii) (C) (i) and (iii) (D) (i) and (iv)

In an electromagnetic wave the average energy density associated with magnetic field will be (A) \(\frac{1}{2} L I^{2}\) (B) \(\frac{B^{2}}{2 \mu_{0}}\) (C) \(\frac{1}{2} \mu_{0} B^{2}\) (D) \(\frac{1}{2} \frac{q}{B^{2}}\)

An electromagnetic wave of frequency \(v=3.0 \mathrm{MHz}\) passes from vacuum into a dielectric medium with permittivity \(\varepsilon=4.0 .\) Then (A) wavelength is doubled and the frequency remains unchanged. (B) wavelength is doubled and frequency becomes half. (C) wavelength is halved and frequency remains unchanged. (D) wavelength and frequency both remain unchanged.

A radar has power of \(1 \mathrm{~kW}\) and is operating at a frequency of \(10 \mathrm{GHz}\). It is located on a mountain top of height \(500 \mathrm{~m}\). The maximum distance up to which it can detect object located on the surface of the earth (Radius of earth \(=6.4 \times 10^{6} \mathrm{~m}\) ) is (A) \(16 \mathrm{~km}\) (B) \(40 \mathrm{~km}\) (C) \(64 \mathrm{~km}\) (D) \(80 \mathrm{~km}\)

Kenneley's Heaviside layer lies between (A) \(50 \mathrm{~km}\) to \(80 \mathrm{~km}\) (B) \(80 \mathrm{~km}\) to \(400 \mathrm{~km}\) (C) beyond \(110 \mathrm{~km}\) (D) beyond \(250 \mathrm{~km}\)
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