/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 154 The magnetic lines of force insi... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 15: Problem 154

The magnetic lines of force inside a bar magnet [2003] (A) are from north pole to south pole of the magnet. (B) does not exist. (C) depend upon the area of cross-pole of the magnet. (D) are from south pole to north pole of the magnet.

Short Answer

Expert verified
The magnetic lines of force inside a bar magnet are from the north pole to the south pole of the magnet (Option A).

Step by step solution

01

Understanding the concept of magnetic lines of force

Magnetic lines of force, or magnetic field lines, are imaginary lines that indicate the direction of the magnetic field around a magnet. The magnetic field lines always form closed loops, and they emerge from the north pole of a magnet and enter its south pole.
02

Evaluating Option A

Option A states that the magnetic lines of force inside a bar magnet are from the north pole to the south pole. This statement is consistent with the concept of magnetic lines of force, which always point from the north pole to the south pole inside the magnet.
03

Evaluating Option B

Option B states that the magnetic lines of force inside a bar magnet do not exist. This statement is incorrect, as magnetic field lines do exist inside a magnet as they are a representation of the direction of the magnetic field.
04

Evaluating Option C

Option C states that the magnetic lines of force inside a bar magnet depend upon the area of cross-pole of the magnet. The direction of magnetic lines of force is not dependent on the area of the cross-pole of the magnet. Instead, they always run from the north pole to the south pole inside the magnet, as previously discussed.
05

Evaluating Option D

Option D states that the magnetic lines of force inside a bar magnet are from the south pole to the north pole. This statement is incorrect, as magnetic lines of force inside a magnet run from the north pole to the south pole. #Conclusion# Based on our understanding of magnetic lines of force and the evaluation of each option, the correct answer is #Answer#(A)#Answer#, which states that the magnetic lines of force inside a bar magnet are from the north pole to the south pole of the magnet.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The magnetic susceptibility of a material of a rod is 499. Permeability of vacuum is \(4 \pi \times 10^{-7} \mathrm{H} / \mathrm{m}\). Absolute permeability of the material of the rod in henry per metre is (A) \(\pi \times 10^{-4}\) (B) \(2 \pi \times 10^{-4}\) (C) \(3 \pi \times 10^{-4}\) (D) \(4 \pi \times 10^{-4}\)

Two long parallel wires \(P\) and \(Q\) are held perpendicular to the plane of the paper at a separation of \(5 \mathrm{~m}\). If \(P\) and \(Q\) carry currents of \(2.5 \mathrm{~A}\) and \(5 \mathrm{~A}\), respectively, in the same direction, then the magnetic field at a point midway between \(P\) and \(Q\) is (A) \(\frac{\mu_{0}}{\pi}\) (B) \(\frac{\sqrt{3} \mu_{0}}{\pi}\) (C) \(\frac{\mu_{0}}{2 \pi}\) (d) \(\frac{3 \mu_{0}}{2 \pi}\)

Two long parallel wires carrying equal currents in opposite directions are placed at \(x=\pm a\) parallel to \(v\)-axis with \(z=0\). Then (A) Magnetic field \(B_{1}\) at 1\. \(\frac{\mu_{0} i}{3 \pi a}\) origin \(O\) (B) Magnetic field \(B_{2}\) at \(P\) 2\. \(\frac{\mu_{0} i}{4 \pi a}\) \((2 a, 0,0)\) \((a, 0,0)\) (C) Magnetic field at \(M\) 3\. \(\frac{\mu_{0} i}{\pi a}\) (D) If wire carries current in 4\. Zero the same direction, then magnetic field at origin 5\. None

Current \(i\) is carried in a wire of length \(L\). If the wire is turned into a circular coil, the maximum magnitude of torque in a given magnetic field \(B\) will be (A) \(\frac{L^{2} i B}{2}\) (B) \(\frac{L^{2} i B}{\pi}\) (C) \(\frac{L^{2} i B}{4 \pi}\) (D) \(\frac{L i^{2} B}{4 \pi}\)

Two very long, straight, parallel wires carry steady current \(I\) and \(-I\), respectively. The distance between the wires is \(d\). At a certain instant of time, a point charge \(q\) is at a point equidistant from the two wires and in the plane of the wires. Its instantaneous velocity \(\vec{v}\) is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is (A) \(\frac{\mu_{0} I q v}{2 \pi d}\) (B) \(\frac{\mu_{0} I q v}{\pi d}\) (C) \(\frac{2 \mu_{0} I q v}{\pi d}\) (D) Zero
See all solutions

Recommended explanations on Physics Textbooks

Magnetism

Read Explanation

Engineering Physics

Read Explanation

Fields in Physics

Read Explanation

Rotational Dynamics

Read Explanation

Medical Physics

Read Explanation

Electricity and Magnetism

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.