Chapter 15: Problem 1
The line on the earth's surface joining the points where the earth's magnetic field is horizontal is called (A) Magnetic meridian (B) Magnetic axis (C) Magnetic line (D) Magnetic equator
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Chapter 15: Problem 1
The line on the earth's surface joining the points where the earth's magnetic field is horizontal is called (A) Magnetic meridian (B) Magnetic axis (C) Magnetic line (D) Magnetic equator
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Assertion: A conducting circular disc of radius \(R\) rotates about its own axis with angular velocity \(\omega\) in uniform magnetic field \(B_{0}\) along axis of the disc then no EMF is induced in the disc. Reason: Whenever a conductor cuts across magnetic lines of flux, an EMF is induced in the conductor. (A) \(\mathrm{A}\) (B) \(\mathrm{B}\) (C) \(\overline{\mathrm{C}}\) (D) D
A magnet makes 30 oscillations per minute at a plane where intensity is \(32 \mathrm{~T}\). At another place it takes \(1 \mathrm{~s}\) to complete one oscillation. The value of horizontal intensity at the second place is, (A) \(12.8 \mathrm{~T}\) (B) \(25.6 \mathrm{~T}\) (C) \(128 \mathrm{~T}\) (D) \(256 \mathrm{~T}\)
In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in this region. The path of the particle will be a (A) Helix (B) Straight line (C) Ellipse (D) Circle
Through two parallel wires \(A\) and \(B, 10\) and \(2 \mathrm{~A}\) of currents are passed, respectively, in opposite direction. If the wire \(A\) is infinitely long and the length of the wire \(B\) is \(2 \mathrm{~m}\), the force on the wire \(B\), which is situated at \(10 \mathrm{~cm}\) distance from \(A\) will be (A) \(8 \times 10^{-5} \mathrm{~N}\) (B) \(4 \times 10^{-7} \mathrm{~N}\) (C) \(4 \times 10^{-5} \mathrm{~N}\) (D) \(4 \pi \times 10^{-7} \mathrm{~N}\)
Two very long, straight, parallel wires carry steady current \(I\) and \(-I\), respectively. The distance between the wires is \(d\). At a certain instant of time, a point charge \(q\) is at a point equidistant from the two wires and in the plane of the wires. Its instantaneous velocity \(\vec{v}\) is perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is (A) \(\frac{\mu_{0} I q v}{2 \pi d}\) (B) \(\frac{\mu_{0} I q v}{\pi d}\) (C) \(\frac{2 \mu_{0} I q v}{\pi d}\) (D) Zero
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