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Chapter 14: Problem 177

In the circuit shown, the current in the resistor is (A) \(0 \mathrm{~A}\) (B) \(0.13 \mathrm{~A}\), from \(Q\) to \(P\) (C) \(0.13 \mathrm{~A}\), from \(P\) to \(Q\) (D) \(1.3 \mathrm{~A}\), from \(P\) to \(Q\)

Short Answer

Expert verified
The short answer based on the steps provided would be: To find the current in the resistor, apply Ohm's Law (\(V = IR\)) and rearrange it to \(I = \frac{V}{R}\). Substitute the given values for voltage and resistance, and calculate the current. Determine the direction of the current according to the polarity of the voltage source and the orientation of the resistor in the circuit. Compare the calculated current and direction with the given options to find the correct answer.

Step by step solution

01

Choose the correct circuit diagram

To find the appropriate exercise, we should use a circuit diagram including a battery with cells (voltage \(V\)), a resistor with resistance \(R\), and a switch.
02

Calculate the total resistance of the circuit

For the given circuit, the total resistance will be the resistance of the resistor, \(R\). This value will be used to calculate the current in the circuit using Ohm's Law.
03

Apply Ohm's Law

Ohm's Law states that \(V = IR\), where \(V\) is the voltage across the resistor, \(I\) is the current through the resistor, and \(R\) is the resistance of the resistor. To find the current in the resistor, we can rearrange this equation to solve for \(I\): \[I = \frac{V}{R}\]
04

Substitute the given values into the equation

We don't have concrete values for voltage and resistance in this exercise, but hypothetically, you would substitute their given values into the above equation and calculate the current \(I\).
05

Determine the direction of the current

The direction of the current in the resistor will be according to the polarity of the voltage source and the orientation of the resistor in the circuit. In a typical circuit, the current flows from the positive terminal of the voltage source to the negative terminal, passing through the resistor.
06

Compare the calculated value with the given options

Compare the calculated current with the given options (A), (B), (C), and (D). Select the option that corresponds to the calculated current value and direction. Keep in mind that this is a general approach to solving this type of problem. You will need to have all the values and diagrams specific to the exercise to make accurate calculations.

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Most popular questions from this chapter

Two conductors have the same resistance at \(0^{\circ} \mathrm{C}\) but their temperature coefficients of resistance are \(\alpha_{1}\) and \(\alpha_{2} .\) The respective temperature coefficients of their series and parallel combinations are nearly (A) \(\frac{\alpha_{1}+\alpha_{2}}{2}, \alpha_{1}+\alpha_{2}\) (B) \(\alpha_{1}+\alpha_{2}, \frac{\alpha_{1}+\alpha_{2}}{2}\) (C) \(\alpha_{1}+\alpha_{2}, \frac{\alpha_{1} \alpha_{2}}{\alpha_{1}+\alpha_{2}}\) (D) \(\frac{\alpha_{1}+\alpha_{2}}{2}, \frac{\alpha_{1}+\alpha_{2}}{2}\)

Five cells, each of EMF \(E\) and internal resistance \(r\) are connected in series. If due to oversight, one cell is connected wrongly, then the equivalent EMF and internal resistance of the combination, is (A) \(5 E\) and \(5 r\) (B) \(3 E\) and \(3 r\) (C) \(3 E\) and \(5 r\) (D) \(5 E\) and \(3 r\)

Kirchhoff's second law is based on the law of conservation of (A) Momentum (B) Charge (C) Energy (D) Sum of mass and energy

Figure \(14.47\) shows the circuit of a potentiometer. The length of the potentiometer wire \(A B\) is \(50 \mathrm{~cm}\). The EMF \(E_{1}\) of the battery is \(4 \mathrm{~V}\), having negligible internal resistance. Value of \(R_{1}\) and \(R_{2}\) are \(15 \Omega\) and \(5 \Omega\), respectively. When both the keys are open, the null point is obtained at a distance of \(31.25 \mathrm{~cm}\) from \(A\), but when both the keys are closed, the balance length reduces to \(5 \mathrm{~cm}\) only. Given \(R_{A B}=10 \Omega\) The balance length when key \(K_{2}\) is open and \(K_{1}\) is closed is given by (A) \(10.5 \mathrm{~cm}\) (B) \(11.5 \mathrm{~cm}\) (C) \(12.5 \mathrm{~cm}\) (D) \(13.5 \mathrm{~cm}\)

There are \(n\) similar resistors each of resistance \(R\). The equivalent resistance comes out to be \(x\) when connected in parallel. If they are connected in series, the resistance comes out to be (A) \(x / n^{2}\) (B) \(n^{2} x\) (C) \(x / n\) (D) \(n x\)
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