/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Temperature of \(100 \mathrm{gm}... [FREE SOLUTION] | 91影视

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Chapter 12: Problem 34

Temperature of \(100 \mathrm{gm}\) water in changed from \(0^{\circ} \mathrm{C}\) to \(3^{\circ} \mathrm{C}\). In this process, heat supplied to water will be (specified heat of water \(=1 \mathrm{cal} / \mathrm{gm}{ }^{\circ} \mathrm{C}\) ) (A) Equal to \(300 \mathrm{cal}\) (B) Greater than \(300 \mathrm{cal}\) (C) Less than \(300 \mathrm{cal}\) (D) Data is insufficient

Short Answer

Expert verified
The heat supplied to water in this process is equal to \(300 cal\). Therefore, the correct answer is (A) Equal to \(300 cal\).

Step by step solution

01

Identify the given variables

Mass of water (m) = 100 gm Initial temperature (T1) = 0掳C Final temperature (T2) = 3掳C Specific heat of water (c) = 1 cal/gm掳C
02

Calculate the change in temperature

The change in temperature (鈭員) can be found by subtracting the initial temperature (T1) from the final temperature (T2): 鈭員 = T2 - T1 鈭員 = 3掳C - 0掳C 鈭員 = 3掳C
03

Calculate the heat transferred

We will now calculate the heat transferred (Q) using the following formula: Q = mc鈭員 where Q = heat transferred m = mass of the water c = specific heat of water 鈭員 = change in temperature Substitute the known values into the formula: Q = (100 gm) * (1 cal/gm掳C) * (3掳C) Q = 300 cal
04

Compare the calculated heat with 300 cal

The calculated heat transferred (Q) is found to be equal to 300 cal. We can compare this value to 300 cal: - If Q is equal to 300 cal, the answer is (A) - If Q is greater than 300 cal, the answer is (B) - If Q is less than 300 cal, the answer is (C) Since the calculated heat is equal to 300 cal, the correct answer is (A) Equal to 300 cal.

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