/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 A long metallic bar is carrying ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 10: Problem 91

A long metallic bar is carrying heat from one end to the other under steady state. The variation of temperature \(\theta\) along the length \(x\) of the bar from its hot end is best described by which of the following.

Short Answer

Expert verified
The temperature variation along the length of the bar would be a linear function with a negative slope.

Step by step solution

01

Identify the Knowledge

Understand that this problem relates to the heat conduction in stationary media. The key principle to keep in mind is Fourier's law of heat conduction, which states that heat transfer by conduction is proportional to the temperature gradient.
02

Apply the Knowledge

Since the system is in steady state, the temperature will not be changing with time. This implies that the rate of heat conduction will remain constant from one end of the bar to the other.
03

Find the Temperature Variation

From Fourier's law of heat conduction, we know that the rate of heat conduction is directly proportional to the negative gradient of the temperature. Hence, the variation of temperature \(\theta\) along the length \(x\) of the bar would be linear with a negative slope.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The temperature of a substance increases by \(27^{\circ} \mathrm{C}\). On the Kelvin scale, this increase is equal to (A) \(300 \mathrm{~K}\) (B) \(2.46 \mathrm{~K}\) (C) \(27 \mathrm{~K}\) (D) \(7 \mathrm{~K}\)

A cubic vessel (with face horizontal + vertical) contains an ideal gas at NTP. The vessel is being carried by a rocket which is moving at a speed of \(500 \mathrm{~ms}^{-1}\) in vertical direction. The pressure of the gas inside the vessel as observed by us on the ground (A) Remains the same because \(500 \mathrm{~ms}^{-1}\) is very much smaller than \(v_{\mathrm{rms}}\) of the gas. (B) Remains the same because motion of the vessel as a whole does not affect the relative motion of the gas molecules and the walls. (C) Will increase by a factor equal to \(\left(v_{\mathrm{mns}}^{2}+(500)^{2}\right) / v_{\mathrm{mns}}^{2}\), where \(v_{\mathrm{rms}}\) was the original mean square velocity of the gas. (D) Will be different on the top wall and bottom wall of the vessel.

\(100 \mathrm{~g}\) of ice at \(0^{\circ} \mathrm{C}\) is mixed with \(100 \mathrm{~g}\) of water at \(100^{\circ} \mathrm{C}\). What will be the final temperature of the mixture? (Latent of fusion for ice \(=80 \mathrm{cal} / \mathrm{gm}\) and specific heat of water is \(1 \mathrm{cal} / \mathrm{gm}^{\circ} \mathrm{C}\) ) (A) \(10^{\circ} \mathrm{C}\) (B) \(20^{\circ} \mathrm{C}\) (C) \(30^{\circ} \mathrm{C}\) (D) \(0^{\circ} \mathrm{C}\)

A constant volume gas thermometer shows pressure reading of \(50 \mathrm{~cm}\) and \(90 \mathrm{~cm}\) of mercury at \(0^{\circ} \mathrm{C}\) and \(100^{\circ} \mathrm{C}\), respectively. When the pressure reading is \(60 \mathrm{~cm}\) of mercury, the temperature is (A) \(25^{\circ} \mathrm{C}\) (B) \(40^{\circ} \mathrm{C}\) (C) \(15^{\circ} \mathrm{C}\) (D) \(12.5^{\circ} \mathrm{C}\)

At what temperature, the Fahrenheit and the Celsius scales will give numerically equal (but opposite in sign) values? (A) \(-40^{\circ} \mathrm{F}\) and \(40^{\circ} \mathrm{C}\) (B) \(11.43^{\circ} \mathrm{F}\) and \(-11.43^{\circ} \mathrm{C}\) (C) \(-11.43^{\circ} \mathrm{F}\) and \(+11.43^{\circ} \mathrm{C}\) (D) \(+40^{\circ} \mathrm{F}\) and \(-40^{\circ} \mathrm{C}\)
See all solutions

Recommended explanations on Physics Textbooks

Waves Physics

Read Explanation

Torque and Rotational Motion

Read Explanation

Fields in Physics

Read Explanation

Mechanics and Materials

Read Explanation

Geometrical and Physical Optics

Read Explanation

Physics of Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.