/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 If \(S\) is stress and \(Y\) is ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If \(S\) is stress and \(Y\) is Young's modulus of material of a wire, then the energy stored in the wire per unit volume is (A) \(2 S^{2} Y\) (B) \(S^{2} / 2 Y\) (C) \(2 Y / S^{2}\) (D) \(S / 2 Y\)

Short Answer

Expert verified
The short answer is: (B) \(S^{2} / 2 Y\)

Step by step solution

01

Write the expression for Strain energy density

The given formula for strain energy density (U) is: \(U\) = (1/2) × stress × strain
02

Re-write the strain from the given Young's modulus formula

Using the relationship (Y = S /strain), we rewrite the strain in terms of stress and Young's modulus: strain = S / Y
03

Substitute the value of the strain obtained in Step 2 into the formula in Step 1

Now we substitute the strain value (S/Y) into the strain energy density formula: \(U\) = (1/2) × stress × (S/Y)
04

Simplify the expression

We can now simplify the expression for strain energy density: \(U\) = (1/2) × S × (S/Y) \(U\) = \(S^{2}\) / (2Y)
05

Match the expression with the given options

Comparing the derived expression, \(U\) = \(S^{2}\) / (2Y), with the given options, we find that it matches with the option (B). So the correct answer to this exercise is (B) \(S^{2} / 2 Y\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A cubic vessel (with face horizontal + vertical) contains an ideal gas at NTP. The vessel is being carried by a rocket which is moving at a speed of \(500 \mathrm{~ms}^{-1}\) in vertical direction. The pressure of the gas inside the vessel as observed by us on the ground (A) Remains the same because \(500 \mathrm{~ms}^{-1}\) is very much smaller than \(v_{\mathrm{rms}}\) of the gas. (B) Remains the same because motion of the vessel as a whole does not affect the relative motion of the gas molecules and the walls. (C) Will increase by a factor equal to \(\left(v_{\mathrm{mns}}^{2}+(500)^{2}\right) / v_{\mathrm{mns}}^{2}\), where \(v_{\mathrm{rms}}\) was the original mean square velocity of the gas. (D) Will be different on the top wall and bottom wall of the vessel.

An inflated rubber balloon contains 1 mole of an ideal gas, has a pressure \(p\), volume \(V\), and temperature \(T\). If the temperature rises to \(1.1 T\), and the volume is increased to \(1.05 \mathrm{~V}\), the final pressure will be (A) \(1.1 p\) (B) \(p\) (C) less than \(p\) (D) between \(p\) and \(1.1\)

If spring is disconnected and top part of cylinder is removed, then find the angular frequency for small oscillation. (Assuming pressure of gas at equilibrium position is \(P_{1}\) and length of gas column is \(l_{1}^{-}\)) (A) \(\sqrt{\frac{\gamma P_{1} S_{0}}{m l_{1}}}\) (B) \(\sqrt{\frac{2 \gamma P S_{0}}{m l_{1}}}\) (C) \(\sqrt{\frac{\gamma P_{1} S_{0}}{4 m l_{1}}}\) (D) \(\sqrt{\frac{\gamma P_{1} S_{0}}{2 m l_{1}}}\)

Mark the correct options (A) A system \(X\) is in thermal equilibrium with \(Y\) but not with \(Z\). The system \(Y\) and \(Z\) may be in thermal equilibrium with each other. (B) A system \(X\) is in thermal equilibrium with \(Y\) but not with \(Z\). The system \(Y\) and \(Z\) are not in thermal equilibrium with each other. (C) A system \(X\) is neither in thermal equilibrium with \(Y\) nor with \(Z\). The systems \(Y\) and \(Z\) must be in thermal equilibrium with each other. (D) A system \(X\) is neither in thermal equilibrium with \(Y\) nor with \(Z\). The systems \(Y\) and \(Z\) may be in thermal equilibrium with each other.

A wooden wheel of radius \(R\) is made of two semicircular parts (see Fig. 10.24). The two parts are held together by a ring made of a metal strip of crosssectional area \(S\) and length \(L . L\) is slightly less than \(2 p R\). To fit the ring on the wheel, it is heated so that its temperature rises by \(\Delta T\) and it just steps over the wheel. As it cools down to surrounding temperature, it presses the semi-circular parts together. If the coefficient of linear expansion of the metal is \(a\) and its Young's modulus is \(Y\), then the force that one part of the wheel applies on the other part is (A) \(2 \pi S Y \alpha \Delta T\) (B) \(S Y \alpha \Delta T\) (C) \(\pi S Y \alpha \Delta T\) (D) \(2 S Y \alpha \Delta T\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.