/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 Electrons in a TV tube move hori... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Problem 80

Electrons in a TV tube move horizontally South to North. Vertical component of earth's magnetic field points down. The electron is deflected towards (A) West (B) No deflection (C) East (D) North to South

Short Answer

Expert verified
The electron is deflected towards the East (C) due to the Earth's magnetic field. This is determined using the left-hand rule, with the thumb pointing in the opposite direction of the moving electron's path (North to South), fingers pointing in the direction of the magnetic field (downwards), and palm facing East.

Step by step solution

01

In this problem, the electron's direction of motion is given as South to North. Keep this in mind. #Step 2: Identify the Direction of the Magnetic Field#

The vertical component of Earth's magnetic field is pointing downwards. #Step 3: Use the Right-Hand Rule #
02

For a negatively charged particle like an electron, we need to use the left-hand rule instead of the right-hand rule. Position your left hand with the thumb pointing in the opposite direction of the moving electron's path (since the electron is negatively charged) which is North to South, and the fingers pointing in the direction of the magnetic field, which is downwards. Now, curl the fingers towards the direction of the thumb. The direction of your palm will point towards the direction of the force acting on the electron. In this case, the palm is facing in the East direction. #Step 4: Determine the Direction of the Electron's Deflection#

Since the force due to the Earth's magnetic field is acting towards the East, the electron will be deflected towards the East. Therefore the correct option is: (C) East

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Parsec is the unit of (A) Time (B) Distance (C) Frequency (D) Angular acceleration

A man starts from \(O\) moves \(500 \mathrm{~m}\) turns by \(60^{\circ}\) and moves \(500 \mathrm{~m}\) again turns by \(60^{\circ}\) and moves \(500 \mathrm{~m}\) and so on. Find the displacement after (i) 5 th turn, (ii) 3 rd turn (A) \(500 \mathrm{~m}, 1000 \mathrm{~m}\) (B) \(500 \mathrm{~m}, 500 \sqrt{3} \mathrm{~m}\) (C) \(1000 \mathrm{~m}, 500 \sqrt{3} \mathrm{~m}\) (D) None of these

A force \(6 \hat{i}+3 \hat{j}+\hat{k}\) Newton displaces a particles from \(A(0,3,2)\) to \(B(5,1,6)\). Find the work done. (A) \(10 \mathrm{~J}\) (B) \(22 \mathrm{~J}\) (C) \(32 \mathrm{~J}\) (D) \(\underline{41 J}\)

If the vectors \(\vec{P}=a \hat{i}+a \hat{j}+3 \hat{k}\) and \(\vec{Q}=a \hat{i}-2 \hat{j}-\hat{k}\) are perpendicular to each other, then the positive value of a is (A) Zero (B) 1 (B) 2 (D) 3

Charge on the capacitor is given by \(Q=I \alpha e^{-\frac{t}{\Delta V \varepsilon_{0} \beta}}\), where \(\alpha\) and \(\beta\) are constant, \(t=\) time, \(I=\) current, \(\Delta V=\) Potential difference then, dimension of \(\frac{\beta}{\alpha}\) is same as dimension of (A) \(\frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}\) (B) \(\mu_{0} \varepsilon_{0}\) (C) \(\frac{\mu_{0}}{\varepsilon_{0}}\) (D) \(\frac{1}{\mu_{0} \varepsilon_{0}}\)
See all solutions

Recommended explanations on Physics Textbooks

Classical Mechanics

Read Explanation

Oscillations

Read Explanation

Electricity

Read Explanation

Physics of Motion

Read Explanation

Atoms and Radioactivity

Read Explanation

Linear Momentum

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.