Chapter 1: Problem 70
\(V^{-1}\) stands for (A) electric flux. (B) electric pressure. (C) electric field density. (D) capacitance.
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Chapter 1: Problem 70
\(V^{-1}\) stands for (A) electric flux. (B) electric pressure. (C) electric field density. (D) capacitance.
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\(\vec{A}=3 \hat{i}+4 \hat{j}+2 \hat{k}, \vec{B}=6 \hat{i}-\hat{j}+3 \hat{k}\). Find a vector paral- lel to \(\vec{A}\) whose magnitude is equal to that of \(\vec{B}\). (A) \(\sqrt{\frac{46}{29}}(3 \hat{i}+4 \hat{j}+2 \hat{k})\) (B) \(\sqrt{\frac{46}{29}}(6 \hat{i}-\hat{j}+3 \hat{k})\) (C) \(\sqrt{\frac{29}{46}}(3 \hat{i}+4 \hat{j}+2 \hat{k})\) (D) None
Unit vector parallel to the resultant of vectors \(\vec{A}=4 \hat{i}-3 \hat{j}\) and \(\vec{B}=8 \hat{i}+8 \hat{j}\) will be (A) \(\frac{24 \hat{i}+5 \hat{j}}{13}\) (B) \(\frac{12 \hat{i}+5 \hat{j}}{13}\) (C) \(\frac{6 \hat{i}+5 \hat{j}}{13}\) (D) None of these
A river is flowing from \(\mathrm{W}\) to \(\mathrm{E}\) with a speed \(5 \mathrm{~m} / \mathrm{min}\). A man can swim in still waters at a velocity \(10 \mathrm{~m} / \mathrm{min}\). In which direction should a man swim to take the shortest path to reach the south bank? (A) \(30^{\circ}\) East of South (B) \(60^{\circ}\) East of North (C) South (D) \(30^{\circ}\) West of North
A wire is of mass \((0.3 \pm 0.003) \mathrm{gm}\). The radius is \((0.5 \pm 0.005) \mathrm{mm}\) and length is \((6.0 \pm 0.06) \mathrm{cm}\) then \(\%\) error in density is (A) 3 (B) 4 (C) 6 (D) \(-2\)
Consider a collection of large number of particles, each moving with a speed \(v\). The direction of velocity is randomly distributed in the collection. The magnitude of the relative velocity between a pair of particles averaged over all the pairs in the collection (A) \(v\) (B) \(\frac{2 v}{\pi}\) (C) \(\frac{\pi v}{4}\) (D) \(\frac{4 v}{\pi}\)
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