Chapter 1: Problem 11
The dimensional formula of magnetic flux is (A) \(\left[M L^{2} T^{-2} A^{-1}\right]\) (B) \(\left[M L^{0} T^{-2} A^{-2}\right]\) (C) \(\left[M^{0} L^{-2} T^{-2} A^{-2}\right]\) (D) \(\left[M L^{2} T^{-1} A^{3}\right]\)
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Chapter 1: Problem 11
The dimensional formula of magnetic flux is (A) \(\left[M L^{2} T^{-2} A^{-1}\right]\) (B) \(\left[M L^{0} T^{-2} A^{-2}\right]\) (C) \(\left[M^{0} L^{-2} T^{-2} A^{-2}\right]\) (D) \(\left[M L^{2} T^{-1} A^{3}\right]\)
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Given \(\left|\overrightarrow{A_{1}}\right|=2,\left|\overrightarrow{A_{2}}\right|=3\) and \(\left|\overrightarrow{A_{1}}+\overrightarrow{A_{2}}\right|=3\). Find the value of \(\left(\overrightarrow{A_{1}}+2 \overrightarrow{A_{2}}\right) \cdot\left(3 \overrightarrow{A_{1}}-4 \overrightarrow{A_{2}}\right)\) (A) \(-64\) (B) 60 (C) \(-60\) (D) 64
A wire is of mass \((0.3 \pm 0.003) \mathrm{gm}\). The radius is \((0.5 \pm 0.005) \mathrm{mm}\) and length is \((6.0 \pm 0.06) \mathrm{cm}\) then \(\%\) error in density is (A) 3 (B) 4 (C) 6 (D) \(-2\)
The component of vector \(\vec{A}=2 \hat{i}+3 \hat{j}\) along the vector \(\hat{i}+\hat{j}\) is (A) \(\frac{5}{\sqrt{2}}\) (B) \(10 \sqrt{2}\) (C) \(5 \sqrt{2}\) (D) 5
\(\int \frac{d x}{\sqrt{a^{2}-x^{2}}}=\frac{1}{a} \sin ^{-1} \frac{a}{x}\) (A) is dimensionally correct. (B) dimensionally incorrect. (C) such mathematical relations cannot be tested. (D) cannot say.
Two vectors \(\vec{A}\) and \(\vec{B}\) are such that \(\vec{A}+\vec{B}=\vec{C}\) and \(A^{2}+B^{2}=C^{2}\) If \(\theta\) is the angle between positive direction of \(\vec{A}\) and \(\vec{B}\) then the correct statement is (B) \(\theta=\frac{2 \pi}{3}\) (A) \(\theta=\pi\) (C) \(\theta=0\) (D) \(\theta=\frac{\pi}{2}\)
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