/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A ball hits a floor and rebounds... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A ball hits a floor and rebounds after an inelastic collision. In this case (A) the momentum of the ball just after the collision is the same as that just before the collision. (B) the mechanical energy of the ball remains the same is the collision. (C) the total momentum of the ball and the earth is conserved. (D) the total energy of the ball and the earth is conserved.

Short Answer

Expert verified
The correct statements for the given inelastic collision are A, C, and D. Momentum is conserved during the collision (statement A), total momentum of the ball and Earth is conserved (statement C), and total energy (mechanical energy, heat energy, etc.) of the ball and Earth is conserved (statement D). However, the mechanical energy of the ball is not conserved (statement B is false) as some kinetic energy is transformed into other forms of energy like heat or sound.

Step by step solution

01

Statement A: Conservation of Momentum

In an inelastic collision, the momentum of the ball will be conserved. This means that, just before and just after the collision, the momentum of the ball should be the same. Therefore, statement A is true.
02

Statement B: Mechanical Energy

In an inelastic collision, some of the kinetic energy of the ball is transformed into other forms of energy like heat or sound. This means that the mechanical energy of the ball will not be conserved, making statement B false.
03

Statement C: Total Momentum

Due to the law of conservation of momentum, the total momentum of the ball and the Earth must be conserved, even in an inelastic collision. The Earth and the ball form an isolated system, so their total momentum cannot change. Thus, statement C is true.
04

Statement D: Total Energy

Energy is always conserved in any type of collision, which means that the total energy of the ball and the Earth before and after the collision must be conserved. However, this does not mean that the mechanical energy (which is only part of the total energy) remains the same. Still, statement D is true, because the total energy (mechanical energy, heat energy, etc.) is conserved. So, the correct answers to this exercise are statements A, C, and D.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
Understanding the law of conservation of momentum is crucial when studying inelastic collisions in physics. This principle states that when no external forces act on a system, the total momentum remains constant before and after a collision. When a ball strikes the floor and bounces back, its collision with the floor is considered inelastic, meaning the objects do not bounce back without losing energy.

The momentum of the ball just before the collision can be calculated using the formula \( p = m \times v \), where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity. It's important to note that in the case of the ball and the Earth, they are parts of a closed system, where the Earth's massive size compared to the ball means its momentum change is negligible, making it appear as if the ball alone conserves momentum.

However, if we consider the momentum of the ball and the Earth as a system, we observe that the overall momentum is indeed conserved even though the collision is inelastic. The ball loses some momentum to the Earth, but because the Earth's mass is so great, this transfer is virtually undetectable.
Mechanical Energy Conservation
Mechanical energy conservation in an inelastic collision is a concept that tends to confuse students. Mechanical energy is the sum of kinetic and potential energies within a system. An inelastic collision typically entails a loss of mechanical energy as it is transformed into other forms of energy, such as heat, sound, or even deformation energy.

Diving into the details, let's consider the ball from our exercise. When it hits the ground and rebounds, its kinetic energy just before the impact is not equal to its kinetic energy after the impact. Some of that energy has been transformed irreversibly. Hence, while the conservation of total energy remains valid, the conservation of mechanical energy does not apply in the same way during an inelastic collision.

To make this concept clearer, we can illustrate the energy transformation process: upon collision, some of the ball's kinetic energy is converted to sound (the noise made upon impact), heat (friction between the ball and ground), and in deformations (changes in the ball's shape). These transformations underscore why we cannot say the mechanical energy remains the same post-collision.
Total Energy Conservation
The principle of total energy conservation holds true in all physical interactions and is a foundational concept in physics. It declares that within a closed system, the total energy before an event must equal the total energy after the event, despite the form that energy may assume. In the context of our inelastic collision scenario, although the mechanical energy of the ball is not conserved due to transformations into non-mechanical forms of energy, the total energy of the system comprising the ball and the Earth is conserved.

This concept can be further unpacked by understanding that while mechanical energy changes forms during the collision, the sum total of all energies—including kinetic, potential, thermal, and sound—remains constant. The crucial point to remember is that total energy conservation doesn't mean each type of energy within the system is conserved individually, but rather that the complete energy budget balances out when all forms are accounted for.

Students should integrate this comprehensive view of energy conservation when analyzing inelastic collisions. By acknowledging that energy can shift between forms—yet the total remains constant—they can better appreciate the far-reaching implications of the law of conservation of energy.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Distance of the centre of mass of a solid uniform cone from its vertex is \(z_{0}\). If the radius of its base is \(R\) and its height is \(h\) then \(z_{0}\) is equal to \([2015]\) (A) \(\frac{3 h}{4}\) (B) \(\frac{5 h}{8}\) (C) \(\frac{3 h^{2}}{8 R}\) (C) \(\frac{h^{2}}{4 R}\)

Two blocks of masses \(m_{1}\) and \(m_{2}\) are connected with an ideal spring and kept on a frictionless plane at rest. Another block of mass \(m_{3}\) making elastic head on collision with the block of mass \(m_{1} .\) After the collision the centre of mass of \(\left(m_{1}+m_{2}\right)\) as a system will (A) move with non-uniform acceleration. (B) move with a uniform velocity. (C) remain at rest. (D) move with uniform acceleration.

Statement-1: Two particles moving in the same direction do not lose all their energy in a completely inelastic collision.

A large rectangular box \(A B C D\) falls vertically with an acceleration \(a .\) A toy gun fixed at \(A\) and aimed towards \(C\), fires a particle \(P\) (A) \(P\) will hit \(C\) if \(a=g\) (B) \(P\) will hit the roof \(B C\) if \(a>g\) (C) \(P\) will hit the wall \(C D\) or the floor \(A D\) if \(a

Two balls of masses \(m_{1}\) and \(m_{2}\) are moving towards each other with speeds \(u_{1}\) and \(u_{2}\). They collide head-on and their speeds are \(v_{1}\) and \(v_{2}\) after collision. $\left(m_{1}=8 \mathrm{~kg}, m_{2}=2 \mathrm{~kg}, u_{2}=3 \mathrm{~m} / \mathrm{s}\right)$ Column-I (A) The speed \(u_{1}\) (in \(\mathrm{m} / \mathrm{s}\) ) so that both balls move in same direction if co-efficient of restitution is \(e=0.5\) (B) The speed \(u_{1}\) (in \(\mathrm{m} / \mathrm{s}\) ) so that maximum energy is transformed to \(m_{2}\) (assume elastic collision) (C) Co-efficient of restitution if \(m_{2}\) stops after collision and \(u_{1}=0.5 \mathrm{~m} / \mathrm{s}\) (D) If collision is inelastic and \(u_{1}=3 \mathrm{~m} / \mathrm{s}\), the loss of kinetic energy (in J) after collision may be Column-II 1\. \(\frac{1}{14}\) 2\. \(\frac{1}{8}\) 3\. 2 4\. 4

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.