/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 A ball is travelling with unifor... [FREE SOLUTION] | 91Ó°ÊÓ

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A ball is travelling with uniform translatory motion. This means that (A) it is at rest. (B) the path can be a straight line or circular and the ball travels with uniform speed. (C) all parts of the ball have the same velocity (magnitude and direction) and the velocity is constant. (D) the centre of the ball moves with constant velocity and the ball spins about its centre uniformly.

Short Answer

Expert verified
The correct answer is (C) all parts of the ball have the same velocity (magnitude and direction) and the velocity is constant, as it accurately describes uniform translatory motion.

Step by step solution

01

(A) it is at rest.

In uniform translatory motion, the ball isn't at rest because it has a constant velocity. So, statement (A) is incorrect.
02

(B) the path can be a straight line or circular and the ball travels with uniform speed.

Although the ball travels with a uniform speed, the path of the motion in uniform translatory motion should be a straight line, not a circle. Thus, statement (B) is incorrect.
03

(C) all parts of the ball have the same velocity (magnitude and direction) and the velocity is constant.

This statement fits the definition of uniform translatory motion: all parts of the object move with the same constant velocity (magnitude and direction). Statement (C) is correct.
04

(D) the centre of the ball moves with constant velocity and the ball spins about its centre uniformly.

Focusing on the spinning of the ball around its center is not relevant for uniform translatory motion. We are only concerned with the constant velocity of all parts of the object. So, statement (D) is incorrect. From the analysis of each statement, we can conclude that the correct answer is (C) all parts of the ball have the same velocity (magnitude and direction) and the velocity is constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Physics JEE MAIN Preparation
Preparing for physics in the JEE MAIN exam requires a solid understanding of key concepts presented in a variety of contexts and questions. One such concept is uniform translatory motion, which occurs when an object moves with constant velocity without any rotation. To tackle questions on this topic effectively, it's important to not only memorize definitions but also understand them conceptually and be able to apply them to different scenarios. Breakdown complex definitions into manageable parts, such as recognizing that 'constant velocity' implies both constant speed and direction, and translating 'translatory motion' to mean that the object isn't spinning or rotating.

During your preparation, practice with these concepts by solving numerous problems that test different aspects of uniform translatory motion. Make use of diagrams to visualize the motion and remember the distinction between uniform translatory motion and motion where the object's orientation changes. This attention to detail will help you quickly eliminate incorrect answer choices in multiple-choice questions like the one in our exercise.
Kinematics
Kinematics is the branch of mechanics that deals with the motion of objects without considering the forces that cause this motion. In the context of our textbook problem, uniform translatory motion is a fundamental concept in kinematics. It is characterized by an object moving in a straight line with a constant velocity, which means both the speed and direction of the object remain unchanged.

In kinematics, it is crucial to understand different types of motion and the relationships between displacement, velocity, and acceleration. For instance, in uniform translatory motion, acceleration is zero because the velocity is constant. Problems in kinematics often require calculation skills, but they also demand a deep comprehension of motion concepts. Utilize graphs and equations of motion to analyze the motion of objects, and apply the appropriate kinematic equations for objects moving with constant velocity.
Constant Velocity
The concept of constant velocity is intrinsic to the understanding of uniform translatory motion. By definition, an object moving with constant velocity has both unchanging speed and direction — contrasting with acceleration, where these quantities change. When an object demonstrates constant velocity, it does not speed up, slow down, or change direction.

Understanding constant velocity is crucial to solving physics problems. It means that the object’s position changes linearly with time, which simplifies calculations and predictions about an object's future position or the time it will take to travel between two points. Furthermore, remember that constant velocity is a vector quantity; thus, when documenting an object's motion, you must specify its speed and the direction of motion. This consideration is essential when distinguishing between scenarios with constant speed (but changing direction) and true constant velocity motion.

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Most popular questions from this chapter

A disc is rotating with an angular velocity \(\omega_{0}\). A constant retarding torque is applied on it to stop the disc. The angular velocity becomes \(\omega_{0} / 2\) after \(n\) rotations. How many more rotations will it make before coming to rest? (A) \(n\) (B) \(2 n\) (C) \(\frac{n}{2}\) (D) \(\frac{n}{3}\)

A string of length \(L\) and mass \(M\) are lying on a horizontal table. A force \(F\) is applied at one of its ends. Tension in the string at a distance \(x\) from the ends at which force is applied is (A) Zero (B) \(F\) (C) \(F(L-x) / L\) (D) \(F(L-x) / M\)

The upper half of an incline plane with inclination \(\phi\) is perfectly smooth, while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom if the co-efficient of friction for the lower half is given by (A) \(2 \tan \phi\) (B) \(\tan \phi\) (C) \(2 \sin \phi\) (D) \(2 \cos \phi\)

A block of mass \(m\) is connected to another block of mass \(M\) by a spring (massless) of spring constant \(k\). The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched. Then a constant force \(F\) starts acting on the block of mass \(M\) to pull it. Find the force on the block of mass \(m .\) (A) \(\frac{m F}{M}\) (B) \(\frac{(M+m) F}{m}\) (C) \(\frac{m F}{(m+M)}\) (D) \(\frac{M F}{(m+M)}\)

A pebble of mass \(0.05 \mathrm{~kg}\) is thrown vertically upwards. The direction and magnitude of the net force on the pebble is given below, choose the incorrect option. (A) During its upward motion, force is \(0.5 \mathrm{~N}\) in vertically upward. (B) During its downward motion, force is \(0.5 \mathrm{~N}\) in vertically downward. (C) At the highest point, where it is momentarily at rest, force is \(0.5 \mathrm{~N}\) in vertically downward. (D) If the pebble was thrown at an angle of say \(45^{\circ}\) with the horizontal direction, force is \(0.5 \mathrm{~N}\) in vertically downward (Ignoring air resistance).

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