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If \(\varepsilon_{0}\) and \(\mu_{0}\) represent the permittivity and permeability of vacuum, \(\varepsilon\) and \(\mu\) represent the permittivity and permeability of medium, then refractive index of the medium is given by (A) \(\sqrt{\frac{\mu_{0} \varepsilon_{0}}{\mu \varepsilon}}\) (B) \(\sqrt{\frac{\mu \varepsilon}{\mu_{0} \varepsilon_{0}}}\) (C) \(\sqrt{\frac{\varepsilon}{\mu_{0} \varepsilon_{0}}}\) (D) \(\sqrt{\frac{\mu_{0} \varepsilon_{0}}{\mu}}\)

Short Answer

Expert verified
The short answer is: The refractive index of the medium is given by option (B) \[n = \sqrt{\frac{\mu \varepsilon}{\mu_{0} \varepsilon_{0}}}\].

Step by step solution

01

Recall the definition of refractive index

Refractive index (n) is the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v). It can be written as: \[n = \frac{c}{v}\]
02

Recall the relations between permittivity, permeability, and speed of light

In a medium with permittivity (\(\varepsilon\)) and permeability (\(\mu\)), the speed of light (v) is given by: \[v = \frac{1}{\sqrt{\mu \varepsilon}}\] In vacuum, the speed of light (c) is given by: \[c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}\]
03

Substitute the values of c and v in the refractive index formula

Now, substituting the values of c and v in the refractive index formula, we get: \[n = \frac{\frac{1}{\sqrt{\mu_0 \varepsilon_0}}}{\frac{1}{\sqrt{\mu \varepsilon}}}\]
04

Simplify the formula

Simplifying the above equation to find n, we get: \[n = \frac{1}{\sqrt{\mu_0 \varepsilon_0}} \times \frac{\sqrt{\mu \varepsilon}}{1}\] \[n = \sqrt{\frac{\mu \varepsilon}{\mu_0 \varepsilon_0}}\] Comparing this to the given options, we can conclude:
05

Choose the correct option

The correct answer is denoted by option (B), which is: \[n = \sqrt{\frac{\mu \varepsilon}{\mu_{0} \varepsilon_{0}}}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permittivity and Permeability
Permittivity (\( \text{symbol:} \varepsilon \) and permeability (\( \text{symbol:} \text{μ} \) are fundamental properties of materials that affect how electromagnetic fields interact with them. These properties determine the ability of a material to transmit or 'permit' an electric field (\textbf{permittivity}) and a magnetic field (\textbf{permeability} respectively).
  • \textbf{Permittivity (\( \text{symbol:} \text{ε} \) refers to a material's ability to permit electric field lines. High permittivity means an electric field can 'easily' pass through the medium, which essentially stores electric potential energy.
  • \textbf{Permeability (\( \text{symbol:} \text{μ} \) is about a material's ability to permit magnetic field lines. A material with high permeability allows magnetic fields to pass through it more 'easily', indicating that it can store magnetic potential energy.
In a vacuum, these values are constants represented by \( \text{ε}_0 \) and \( \text{μ}_0 \) and are crucial for calculating various electromagnetic phenomena. When considering a different medium, both permittivity and permeability can vary significantly from their vacuum values.
Speed of Light in Vacuum and Medium
The speed of light in a vacuum (\textbf{symbol: c}) is a constant, precisely 299,792,458 meters per second. It's one of the fundamental constants of nature and an important parameter in physics. When light travels through a medium other than a vacuum, its speed changes and is represented as \textbf{v}.
  • The speed of light in a vacuum is determined by the vacuum permittivity (\( \text{ε}_0 \) and vacuum permeability (\( \text{μ}_0 \) using the formula \( c = \frac{1}{\text{sqrt}(\text{μ}_0 \text{ε}_0)}\).
  • Similarly, the speed of light within a medium with permeability (\textbf{μ}) and permittivity (\textbf{ε}) can be expressed as \( v = \frac{1}{\text{sqrt}(μ \text{ε})}\).
This change in speed is associated with a phenomenon called refraction, which is directly related to the refractive index of the medium. The slower the light travels in a medium compared to a vacuum, the higher the refractive index will be.
Relationship Between Refractive Index and Permittivity/Permeability
Understanding how light behaves as it passes from one medium to another can be quite intriguing. One of the key aspects governing this behavior is the refractive index of a medium, which is influenced by both permittivity and permeability. The refractive index (\textbf{n}) of a medium is defined as the ratio of the speed of light in a vacuum (\textbf{c}) to that in the medium (\textbf{v}), expressed as \( n = \frac{c}{v}\).Incorporating the expressions for the speed of light in vacuum and medium using permittivity and permeability, we derive the refractive index as \( n = \frac{1}{\text{sqrt}(\text{μ}_0 \text{ε}_0)} \times \frac{\text{sqrt}(μ \text{ε})}{1} = \text{sqrt}(\frac{μ \text{ε}}{\text{μ}_0 \text{ε}_0})\).

Significance of Refractive Index

The refractive index indicates how much the speed of light is reduced in the medium compared to its speed in a vacuum. A greater refractive index implies that light travels more slowly in the medium, and the optical density is higher.

How It Relates to Permittivity/Permeability

This relationship tells us that a medium's optical properties are deeply connected to its electric and magnetic properties. Knowing the permittivity and permeability of a medium, we can predict its refractive index and thus understand how light will propagate and bend within that medium. This crucial relationship is foundational in the fields of optics and material science, helping us to design lenses, optical fibers, and even manipulate light in sophisticated ways. The correct choice to represent this relationship, as given in our initial problem, is \( n = \text{sqrt}(\frac{μ \text{ε}}{\text{μ}_0 \text{ε}_0}) \), which directly shows how both permittivity (ε) and permeability (μ) of a medium contribute to its refractive index.

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