/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 A thin sheet of glass \((\mu=1.5... [FREE SOLUTION] | 91Ó°ÊÓ

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A thin sheet of glass \((\mu=1.5)\) of thickness 6 microns introduced in the path of one of interfering beams of a double slit experiment shifts the central fringes to a position previously occupied by fifth bright fringe. Then the wavelength of the light used is (A) \(6000 \AA\) (B) \(3000 \AA\) (C) \(4500 \AA\) (D) \(7500 \AA\)

Short Answer

Expert verified
The wavelength of the light used in the double-slit experiment is \(6000 \AA\). The correct answer is (A) \(6000 \AA\).

Step by step solution

01

Optical Path Difference

Recall that the optical path difference is given by the formula: Optical Path Difference = (µ - 1) * thickness. In this problem, we have µ = 1.5 and the thickness of the glass = 6 microns. Let's calculate the optical path difference: Optical Path Difference = (1.5 - 1) * 6 microns = 0.5 * 6 microns = 3 microns
02

Relationship between Optical Path Difference and Fringe Shift

We are told that the central fringe shifts to the position previously occupied by the fifth bright fringe. This means that the optical path difference caused by the glass must be equal to five times the wavelength (5λ) of the light used in the double-slit experiment: Optical Path Difference = 5λ
03

Solve for Wavelength

Now we have enough information to solve for the wavelength of the light: 3 microns = 5λ To find the wavelength, divide both sides of the equation by 5: λ = (3 microns) / 5 = 0.6 microns
04

Convert Wavelength to Angstroms

Finally, we need to convert the wavelength from microns to Angstroms. Recall that 1 micron = 10,000 Angstroms: λ = 0.6 microns * 10,000 Angstroms/micron = 6000 Angstroms The wavelength of the light used in the double-slit experiment is 6000 Angstroms. The correct answer is (A) \(6000 \AA\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Optical Path Difference
The concept of optical path difference is crucial in understanding the interaction of light through different media. It helps us measure the additional distance that light travels in a medium other than vacuum. To calculate this, use the formula:
  • Optical Path Difference = (Refractive Index - 1) * Thickness
In our case, the refractive index (\(\mu\)) of the glass sheet is 1.5, and its thickness is 6 microns. By substituting these values into the formula, we get:\[\text{Optical Path Difference} = (1.5 - 1) \times 6 \text{ microns} = 3 \text{ microns}\]This difference is responsible for shifting the interference pattern in a double slit experiment.
Fringe Shift
Fringe shift is a key outcome in interference experiments like the double slit experiment. It refers to the movement of interference fringes when an optical path difference is introduced.In this scenario, the introduction of the glass causes a central fringe shift to where the fifth bright fringe would normally appear. This indicates that the glass has induced a path difference equal to the wave path of five wavelengths. We express this as:\[\text{Optical Path Difference} = 5\lambda\]Substituting the previously calculated optical path difference of 3 microns into this equation gives us a framework to solve for the wavelength \(\lambda\), as the fringe shift shows a direct link between path difference and wavelength.
Wavelength in Microns
Understanding wavelength in microns helps us handle calculations in a scale appropriate for the phenomenon. In the given problem, the optical path differences and shifts are expressed in microns because the thickness and the light effects involved are minuscule.To find the wavelength \(\lambda\) of the light, we utilize the relationship established from the fringe shift:\[3 \text{ microns} = 5\lambda\]Solving for \(\lambda\), we divide both sides by 5:\[\lambda = \frac{3 \text{ microns}}{5} = 0.6 \text{ microns}\]This calculation gives us the wavelength expressed in microns, a widespread unit choice for physics problems involving light on such small scales.
Wavelength Conversion to Angstroms
Converting wavelength from microns to Angstroms is often helpful for scientific applications, where precision and standard units are important. The conversion can be done using the fact that:
  • 1 micron = 10,000 Angstroms
In the problem, we determined the wavelength as 0.6 microns, which needs to be converted to Angstroms:\[\lambda = 0.6 \text{ microns} \times 10,000 \text{ Angstroms/micron}\]This results in:\[\lambda = 6000 \text{ Angstroms}\]Thus the wavelength of light in the double slit experiment is 6000 Angstroms, fitting neatly into the unit system used for precise and uniform exchange of scientific information.

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