/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 The diagram shows a solenoid car... [FREE SOLUTION] | 91Ó°ÊÓ

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The diagram shows a solenoid carrying time varying current \(I=I_{0} t\). On the axis of this solenoid, a ring has been placed. The mutual inductance of the ring and the solenoid is \(M\) and the self-inductance of the ring is \(L\). If the resistance of the ring is \(R\) then maximum current which can flow through the ring is (A) \(\frac{(2 M+L) I_{0}}{R}\) (B) \(\frac{M I_{0}}{R}\) (C) \(\frac{(2 M-L) I_{0}}{R}\) (D) \(\frac{(M+L) I_{0}}{R}\)

Short Answer

Expert verified
The maximum current that can flow through the ring is \(I_{max} = \frac{(M - L)I_{0}}{R}\), which corresponds to choice (C).

Step by step solution

01

Find the emf due to self-inductance

Self-inductance opposes the change in current flow in a circuit. The formula to find the induced emf due to self-inductance is given by Faraday's law of electromagnetic induction as \(e_{L} = -L \frac{di}{dt}\). Since there's no current in the ring initially, the change in current is the current itself. Thus, \(e_{L} = -L \frac{dI}{dt} = -L \frac{I_{0}}{dt}\).
02

Find the emf due to mutual inductance

Mutual inductance is defined by the formula \(e_{M} = M \frac{dI}{dt}\), where \(I\) is the current in the solenoid. Similarly, as there's no initial current, the emf due to mutual inductance becomes \(e_{M} = M \frac{dI}{dt} = M \frac{I_{0}}{dt}\).
03

Add up the emf's

Because of Lenz's law, the emf due to self-inductance \(e_{L}\) and the emf due to mutual inductance \(e_{M}\) point in the same direction, and thus add up to find the total emf in the ring, \(E_{total} = e_{L} + e_{M} = -L \frac{I_{0}}{dt} + M \frac{I_{0}}{dt} = (M - L) \frac{I_{0}}{dt}\).
04

Use Ohm's Law to find the maximum current

Ohm’s Law states that the current through a conductor between two points is directly proportional to the voltage across the two points. That is \(I = \frac{E_{total}}{R}\), where \(E_{total}\) is the total emf and \(I\) is the current flowing through the ring. Substituting \(E_{total}\) from step 3 into this equation, we find the maximum current \(I_{max}\) in the ring is: \[I_{max} = \frac{(M - L)I_{0}}{R}\] So, (C) is the correct choice.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solenoid
A solenoid is essentially a long coil of wire, shaped like a helix, designed to produce a uniform magnetic field inside when an electric current flows through it. As the current in the solenoid changes with time, it can induce an electromotive force (emf) in nearby conductive structures due to electromagnetic induction.

When electric current flows through the solenoid, it generates a magnetic field similar to the field of a bar magnet, with a distinct north and south pole. The strength of the magnetic field created by the solenoid depends on the number of turns per unit length as well as the current passing through the solenoid. Interestingly, this also means the solenoid becomes an electromagnet, with the ability to turn its magnetic field on and off, or even reverse it, by changing the direction of the current.
Mutual inductance
Mutual inductance is a measure of the ability of one circuit, when experiencing a change in current, to induce an emf in a neighboring circuit. This principle is foundational in the operation of transformers, inductive sensors, and various forms of wireless energy transfer. The mutual inductance, denoted by the symbol \(M\), depends on the geometrical arrangement and distance between the two circuits, as well as the nature of the material that separates them.

In our exercise, the ring placed along the axis of the solenoid can have an induced current due to the changing magnetic field created by the solenoid's time-varying current. The stronger the coupling (which is often determined by how close the ring is to the solenoid and their respective shapes and sizes), the greater the mutual inductance.
Self-inductance
Self-inductance is the property of a circuit, often a coil, to resist changes in the current flow through it by inducing a voltage (also referred to as back emf) in itself. This is caused by the changing magnetic field that accompanies the changing current. Every loop or coil of wire with current flowing through it not only generates a magnetic field but also interacts with that field.

The self-inductance is represented by the symbol \(L\) and is affected by the physical characteristics of the coil such as the number of turns, the area of the loops, and the type of material inside the coil (such as a magnetic core). In the provided exercise, the self-inductance of the ring opposes the increase in the current created by the emf induced due to the solenoid's changing current.
Electromagnetic induction
Electromagnetic induction is the process by which a changing magnetic field within a circuit generates an electric current in a nearby circuit without the circuits being connected. This is described by Faraday's Law, which states that the induced emf in a circuit is equal to the rate of change of magnetic flux through the circuit. It's important to note that only a changing magnetic field can produce an induced current; a steady magnetic field will not.

In our exercise, the time-varying current in the solenoid creates a changing magnetic field, which induces an emf in the nearby ring. This induced emf can cause a current to flow in the ring if the circuit is closed, and the magnitude of this current is dictated by other properties of the ring such as its resistance and inductance, as illustrated in the steps of the solution.

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