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Which of the following units denotes the dimension \(\frac{M L^{2}}{Q^{2}}\), where \(Q\) denotes the electric charge? (A) \(\mathrm{Wb} / \mathrm{m}^{2}\) (B) Henry (H) (C) \(\mathrm{H} / \mathrm{m}^{2}\) (D) Weber (Wb)

Short Answer

Expert verified
The unit that denotes the dimension \(\frac{M L^{2}}{Q^{2}}\) is Henry (H).

Step by step solution

01

Analyze given units

We are given 4 units: \(\mathrm{Wb} / \mathrm{m}^{2}\), Henry (H), \(\mathrm{H} / \mathrm{m}^{2}\), and Weber (Wb). To identify which of these represents the given dimension, we need to find their respective dimensions in terms of mass (\(M\)), length (\(L\)), and electric charge (\(Q\)).
02

Dimension of Weber (Wb)

The Weber (Wb) is the SI unit for magnetic flux, and its dimension can be written as: \[Wb = T \times m^{2} = (M L Q^{-2} T^{-1})\times m^{2} = M L^{2} Q^{-2} T^{-1}\]
03

Dimension of \(\frac{\mathrm{Wb}}{\mathrm{m}^{2}}\)

Using the dimension found in step 2, we can find the dimension for \([\frac{\mathrm{Wb}}{\mathrm{m}^{2}}]\) as follows: \[\frac{M L^{2} Q^{-2} T^{-1}}{L^{2}} = M Q^{-2} T^{-1}\]
04

Dimension of Henry (H)

The Henry (H) is the SI unit for inductance, and its dimension can be formulated as: \[H = \mathrm{V \times s \times A^{-1}} = M L^{2} T^{-2} A^{-1} = M L^{2} Q^{-2}\]
05

Dimension of \(\frac{\mathrm{H}}{\mathrm{m}^{2}}\)

Using the dimension found in step 4, we can find the dimension of \([\frac{\mathrm{H}}{\mathrm{m}^{2}}]\) as follows: \[\frac{M L^{2} Q^{-2}}{L^{2}} = M Q^{-2}\] Based on the above steps, only option B (Henry) has the asked dimension of \(\frac{M L^{2}}{Q^{2}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SI Units
Understanding the International System of Units (SI Units) is fundamental in physics and across all scientific disciplines. These units provide a standardized system for measuring various physical quantities, allowing for clear and consistent communication of measurements around the world. The SI unit system is built upon seven base units which include the meter (m) for length, kilogram (kg) for mass, second (s) for time, ampere (A) for electric current, kelvin (K) for temperature, mole (mol) for the amount of substance, and candela (cd) for luminous intensity.

Integral to the SI system are derived units, which are combinations of these base units to measure other physical quantities like velocity, acceleration, and in the case of our textbook exercise, magnetic flux and inductance. It's crucial for students to familiarize themselves with the SI system and these derived units to understand exercises involving dimension analysis, such as the one provided.
Magnetic Flux
Magnetic flux is a measure of the quantity of magnetism, taking into account the strength and the extent of a magnetic field. It is represented by the SI unit weber (Wb), which can be conceptually understood as the total magnetic field passing through a certain area.

The magnetic flux through a surface is proportional to the number of magnetic field lines that pass through that surface. The concept is analogous to the flow of water through a net: just as the amount of water is measured by how much passes through the net, magnetic flux measures how much of the magnetic field passes through a given area. It's a scalar quantity, meaning it has magnitude but no direction. The formal definition involves the integral of the magnetic field over a surface, often symbolized as \( \text{Magnetic Flux} = \text{B} \times \text{A} \times \text{cos}(θ) \), where \( B \) is the magnetic field's strength, \( A \) is the area of the surface, and \( θ \) is the angle between the field lines and the normal (perpendicular) to the surface.
Inductance
Inductance is the property of an electrical conductor by which a change in current flowing through it induces an electromotive force (voltage) in the conductor itself (self-inductance) or in any nearby conductors (mutual inductance). Its SI unit is the henry (H).

Inductance is fundamentally a measure of an inductor's ability to store energy in a magnetic field, and it relies on the physical configuration of the electric circuit, including the number of coils and their shape. The exercise we are looking at involves identifying the dimension of inductance, which is given as \( \text{Henry (H)} = \text{V} \times \text{s} \times \text{A}^{-1} \). This can further be broken down into SI base units of mass (\text{M}), length (\text{L}), time (\text{T}), and electric charge (\text{Q}), resulting in the dimension \( \text{M} \text{L}^{2} \text{T}^{-2} \text{A}^{-1} \), which simplifies to \( \text{M} \text{L}^{2} \text{Q}^{-2} \) when considering the charge in terms of amperes and time. Understanding the dimensionality of such quantities aids in deeper comprehension of various physical phenomena linked to electromagnetism and electrical circuits.

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Most popular questions from this chapter

When the current changes from \(+2 \mathrm{~A}\) to \(-2 \mathrm{~A}\) in \(0.05 \mathrm{~s}\), an EMF of \(8 \mathrm{~V}\) is induced in a coil. The coefficient of self-induction of the coil is (A) \(0.1 \mathrm{H}\) (B) \(0.2 \mathrm{H}\) (C) \(0.4 \mathrm{H}\) (D) \(0.8 \mathrm{H}\)

A conducting circular loop is placed in a uniform magnetic field of induction \(B\) tesla with its plane normal to the field. Now the radius of the loop starts shrinking at the rate ( \(d r / d t\) ). Then the induced EMF at the instant when the radius is \(r\) will be (A) \(\pi r B\left(\frac{d r}{d t}\right)\) (B) \(2 \pi r B\left(\frac{d r}{d t}\right)\) (C) \(\pi r^{2}\left(\frac{d B}{d t}\right)\) (D) \(B \frac{\pi r^{2}}{2} \frac{d r}{d t}\)

A varying magnetic flux linking a coil is given by \(\phi=3 t^{2}\). The magnitude of induced EMF in the loop at \(t=3 \mathrm{~s}\) is (A) \(3 \mathrm{~V}\) (B) \(9 \mathrm{~V}\) (C) \(18 \mathrm{~V}\) (D) \(27 \mathrm{~V}\)

A particle of mass \(M\) and charge \(Q\) moving with a velocity \(\vec{v}\) describes a circular path of radius \(R\) when subjected to a uniform transverse magnetic field of induction \(B\). The work done by the field when the particle completes a full circle is (A) Zero (B) \(B Q 2 \pi R\) (C) \(B Q v(2 \pi R)\) (D) \(\left(\frac{M v^{2}}{R}\right)(2 \pi R)\)

A magnetized wire of moment \(M\) is bent into an arc of a circle subtending an angle of \(60^{\circ}\) at the centre, the new magnetic moment is (A) \(\frac{2 M}{\pi}\) (B) \(\frac{M}{\pi}\) (C) \(\frac{3 \sqrt{3} M}{\pi}\) (D) \(\frac{3 M}{\pi}\)

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