Chapter 3: Problem 13
Assume that \(f\) is a strictly increasing function with domain \((0, \infty)\) and range \(R\) which satisfies (i) \(f(a)=1\) (ii) \(f(x \times y)=f(x)+f(y)\) for each \(x, y>0\) Show that \(f^{-1}\) is a continuous function which satisfies (i)' \(f^{-1}(1)=a\) (ii)' \(f^{-1}(x+y)=f^{-1}(x) \times f^{-1}(y)\) for each \(x, y \in \mathbb{R}\) Deduce that \(f(x)=\log _{a} x\) for each \(x>0\)
Short Answer
Step by step solution
Understand Inverse Function Continuity
Prove Inverse Function Identity
Derive Functional Equation for Inverse Function
Verify Logarithmic Form of Original Function
Conclude that \(f(x) = \log_a x\)
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