/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 For which numbers \(x\) does the... [FREE SOLUTION] | 91Ó°ÊÓ

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For which numbers \(x\) does the series \(\sum_{x=0}^{x} x^{n}\) converge? If \(D\) is the set of \(x\) for which that series converges then we can define a function \(f\) by $$ f(x)=\sum_{n=0}^{\infty} x^{n}=1+x+x^{2}+x^{3}+\cdots \text { for } x \in D $$ Give a more direct formulation of \(f\) which does not involve infinite sums. (Solutions on page 243 )

Short Answer

Expert verified
Function \(f(x)\) is defined as \(\frac{1}{1-x}\) for \(|x| < 1\).

Step by step solution

01

Understand the Geometric Series

The series given is a geometric series: \(\sum_{n=0}^{\infty} x^{n} = 1 + x + x^{2} + x^{3} + \cdots \). For the geometric series \(\sum_{n=0}^{\infty} r^{n}\), it converges if the absolute value of \(r\) is less than 1, i.e., \(|r| < 1\).
02

Determine the Convergence Interval

In our series, \(x\) plays the role of \(r\). Therefore, the series \(\sum_{n=0}^{\infty} x^{n}\) will converge if \(|x| < 1\). Thus, the set \(D\) where the series converges is \((-1, 1)\).
03

Apply the Formula for Geometric Series Sum

The sum of an infinite geometric series \(\sum_{n=0}^{\infty} x^{n}\) with \(|x| < 1\) is given by the formula \(\frac{1}{1-x}\). This provides a closed form for the function \(f(x)\) within the convergence interval.
04

Express Function f Without Infinite Sum

Based on the previous step, the function \(f(x)\) for \(x\in D\) can be expressed as \(f(x) = \frac{1}{1-x}\) for \(|x| < 1\). This is the requested formulation that does not involve infinite sums.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Convergence
A series convergence refers to the behavior of adding up infinite terms. Specifically, we want to determine whether these series of numbers approach a particular finite value. If the series converges, it means that as we continue to add terms, the sum will settle down to a single number. This is an important concept in calculus and analysis because it allows us to make sense of adding infinitely many numbers together.

In the context of a geometric series like \( \sum_{n=0}^{\infty} x^{n} = 1 + x + x^{2} + x^{3} + \cdots \), convergence criteria depend on the value of \( x \). To ensure the series converges, we need \( |x| < 1 \). If this condition is met, we can conclude the series will converge to a specific value instead of diverging to infinity.
Infinite Series
An infinite series is a sum of infinitely many terms, each following a specific rule or pattern. Often represented in the form \( \sum_{n=0}^{\infty} a_n \), this concept allows mathematicians to examine sequences that continue indefinitely.

The geometric series is a specific type of infinite series where each term is a constant times the previous term. For example, the series \( 1 + x + x^{2} + x^{3} + \cdots \) is an infinite geometric series with a common ratio of \( x \). Because the series stretches to infinity, convergence becomes a crucial query: when does the sum of an infinite series equal a finite number?
  • Infinite series can diverge, meaning they don't settle to a limit.
  • The behavior of these series heavily depends on their rules and the values of their terms.
Sum Formula
The sum formula for a geometric series is an elegant solution for calculating the sum of infinitely many numbers in a geometric setup. For a series \( \sum_{n=0}^{\infty} x^{n} \) where \( |x| < 1 \), the sum evaluates to \( \frac{1}{1-x} \). This formula provides a quick computation method and invaluable insight into the nature of these series.

Here’s why it’s useful:
  • It turns an infinite process into a simple arithmetic operation.
  • Allows us to express the infinite sum with a single expression, \( \frac{1}{1-x} \).
  • Simplifies calculations and understanding, especially in theoretical work.
When applied to a series like \( f(x) = \sum_{n=0}^{\infty} x^{n} \), the sum formula eliminates the burdens of comprehending infinite addition.
Interval of Convergence
The interval of convergence refers to the set of values for which a series converges. In simpler terms, it's the range of \( x \) values that make a series sum up to a finite number.

For an infinite series like \( \sum_{n=0}^{\infty} x^{n} \), the series converges when \( |x| < 1 \), so the interval of convergence is \((-1, 1)\). Outside this interval, the series does not converge, meaning it does not approach a finite limit.
  • The interval determines the domain for which the derived function, like \( f(x) = \frac{1}{1-x} \), is valid.
  • Understanding the interval is crucial when applying the series or function in mathematical or real-world contexts.

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Most popular questions from this chapter

Let \(f\) be a function whose domain is an interval. Then \(f\) is called convex if whenever a chord is drawn between two points on its graph that chord lies either on or above the graph, as illustrated in the left-hand figure. Earlier we considered the convex function given by \(f(x)=x^{2}(x \in \mathbb{R})\) and calculated a sequence of gradients of chords from \(P(1,1)\) to other points on the graph of \(f\). These points were to the right of \(P\) and closer and closer to it. The sequence we obtained was $$ 2.8,2.4,2.2,2.1,2.05, \ldots $$ which is decreasing. We shall now see that a sequence obtained in this way for a convex function will always be decreasing. So now let \(f\) be any convex function and consider the points \(P\) \(\left(x_{0}, f\left(x_{0}\right)\right)\) and \(Q\left(x_{1}, f\left(x_{1}\right)\right)\) on the graph of \(f\). Let \(x_{2}\) satisfy \(x_{0}

Show that if \(x_{1}, x_{2}, x_{3}, \ldots\) converges to \(x\) then any of its subsequences also converges to \(x\). Deduce that the sequence \(1, \frac{1}{2}, \frac{1}{3}, 1, \frac{1}{4}, \frac{1}{5}, 1, \frac{1}{6}, \frac{1}{7}, 1, \ldots\) is divergent.

Write down the definition of the sequence \(x_{1}, x_{2}, x_{3}, \ldots\) converging to \(x\), and also write down the same definition applied to the sequence \(x_{1}-x, x_{2}-x, x_{3}-x, \ldots\) converging to 0 . Observe that the two statements are saying equivalent things. (Hence \(x_{1}, x_{2}, x_{3}, \ldots\) converges to \(x\) if and only if \(x_{1}-x, x_{2}-x, x_{3}-x, \ldots\) converges to 0 .) Deduce that if the sequence \(x_{1}, x_{2}, x_{3}, \ldots\) converges to \(x\) then for any number \(y\) the sequence \(x_{1}+y, x_{2}+y, x_{3}+y, \ldots\) converges to \(x+y\) (i.e. you can 'add a constant to a convergent sequence').

Are the following sequences convergent? If so find their limits, justifying your answers. (i) \(\left(\frac{2 n^{3}+1}{3 n^{3}+n+2}\right)\) (ii) \(\left(\left(1+\frac{1}{\sqrt{n}}\right)^{2}\right)\) (iii) \(\left(\left(100+5^{n}\right)^{1 / n}\right)\)

Test the convergence of the following series: (i) \(\sum \frac{\left(n^{2}+1\right)^{3}}{\left(n^{4}+1\right)^{2}}\); (ii) \(\sum \frac{5^{2 n}(n !)^{3}}{(3 n) !}\); (iii) \(\sum \sin n\)

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