Chapter 2: Problem 20
Evaluate \(\int_{0}^{1} \frac{x+4}{x^{2}+3 x+2} d x\)
Short Answer
Expert verified
\(\ln\left(\frac{32}{9}\right)\)
Step by step solution
01
Factor the Denominator
First, we need to factor the quadratic expression in the denominator \(x^2 + 3x + 2\). This factors into \((x + 1)(x + 2)\).
02
Setup Partial Fraction Decomposition
Express \(\frac{x+4}{(x+1)(x+2)}\) as partial fractions. Let \(\frac{x+4}{(x+1)(x+2)} = \frac{A}{x+1} + \frac{B}{x+2}\).
03
Solve for Coefficients A and B
Multiply through by \((x+1)(x+2)\) to clear the fractions: \(x + 4 = A(x + 2) + B(x + 1)\). Equating coefficients, simplify to find \(A = 3\) and \(B = -2\).
04
Integrate Each Term Separately
Now integrate each term separately:\[\int \frac{3}{x+1} \, dx - \int \frac{2}{x+2} \, dx.\]This yields:\[3\ln|x+1| - 2\ln|x+2| + C.\]
05
Evaluate the Definite Integral
Evaluate the integrated function from 0 to 1:\[\left[ 3\ln|x+1| - 2\ln|x+2| \right]_0^1.\]Substitute to find:\[3\ln(2) - 2\ln(3) - (3\ln(1) - 2\ln(2)) = 3\ln(2) - 2\ln(3) + 2\ln(2).\]Combine: \[5\ln(2) - 2\ln(3).\]This is equal to:\[\ln\left(\frac{32}{9}\right).\]
06
Final Answer
The value of the definite integral is \(\ln\left(\frac{32}{9}\right)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
Definite integrals represent the signed area under the curve of a function in a specific interval—between an upper and a lower limit. These limits are denoted at the top and bottom of the integral sign. For example, in our original exercise, we want to evaluate \[ \int_{0}^{1} \frac{x+4}{x^{2}+3 x+2} \, dx \].
This symbol indicates that we want to find the net area from 0 to 1 under the curve described by the fractional function.
This method gives us the total area we seek.
This symbol indicates that we want to find the net area from 0 to 1 under the curve described by the fractional function.
- Start by performing any necessary algebraic simplifications on the function, such as factoring or partial fraction decomposition.
- Integrals can often produce functions with logarithms or polynomials, depending on the integrand's structure.
This method gives us the total area we seek.
Partial Fraction Decomposition
Partial fraction decomposition is a crucial step in integrals involving complex rational functions. By breaking a fraction down into simpler components, we make the integral easier to solve. In our example, we start with:\[ \frac{x+4}{(x+1)(x+2)} \].
The goal is to express this as:\[ \frac{A}{x+1} + \frac{B}{x+2} \].
Follow these actions:
The goal is to express this as:\[ \frac{A}{x+1} + \frac{B}{x+2} \].
Follow these actions:
- Clear the denominators by multiplying through by the factored denominator expression.
- Compare coefficients of corresponding powers of \[ x \] to solve for constants \[ A \] and \[ B \].
Factoring Quadratic Expressions
Factoring quadratic expressions is an essential skill, especially when dealing with rational functions in integrals. A quadratic expression is typically of the form \[ ax^2 + bx + c \].
For the given \[ x^2 + 3x + 2 \], the process involves finding two numbers that multiply to \[ c \] (in this case, 2) and add to \[ b \] (3).
For the given \[ x^2 + 3x + 2 \], the process involves finding two numbers that multiply to \[ c \] (in this case, 2) and add to \[ b \] (3).
- The quadratic \[ x^2 + 3x + 2 \] factors into \[ (x+1)(x+2) \].
- This step is pivotal as it sets up for partial fraction decomposition, making rational functions manageable.