Chapter 1: Problem 59
(a) What is the length of $$ \overrightarrow{\mathbf{w}}_{n}=\vec{e}_{1}+2 \vec{e}_{2}+\cdots+n \vec{e}_{n}=\sum_{i=1}^{n} i \vec{e}_{i} ? $$ Vhat is the angle \(\alpha_{n, k}\) between \(\vec{w}_{n}\) and \(\vec{e}_{k} ?\) What are the limits $$ \lim _{n \rightarrow \infty} \alpha_{n, k} \quad, \quad \lim _{n \rightarrow \infty} \alpha_{n, n} \quad, \quad \lim _{n \rightarrow \infty} \alpha_{n,[n / 2]} $$
Short Answer
Step by step solution
Introduce the vector
Calculate the length of the vector
Simplify the length formula
Calculate the angle \(\alpha_{n,k}\) between \(\vec{w}_n\) and \(\vec{e}_k\)
Calculate the limits
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dot Product
- \( \|\vec{a}\| \) and \( \|\vec{b}\| \) are the magnitudes of vectors \( \vec{a} \) and \( \vec{b} \).
- \( \theta \) is the angle between the two vectors.
The dot product formula \( \vec{w}_n \cdot \vec{e}_k = k \) helps us find the cosine of the angle, highlighting how a simple arithmetic operation can unveil deeper geometric insights.
Magnitude of a Vector
In the context of our exercise with the vector \( \vec{w}_n \), the magnitude is:\[\| \vec{w}_n \| = \sqrt{1^2 + 2^2 + ... + n^2}\]To simplify, this sum of squares can be expressed using the formula:\[\sum_{i=1}^n i^2 = \frac{n(n+1)(2n+1)}{6}\]This simplification gives us a neat computation of the length of \( \vec{w}_n \), helping in further calculations like finding angles or performing vector projections.
Basis Vectors
- \( \vec{e}_1 = (1, 0, 0, ..., 0) \)
- \( \vec{e}_2 = (0, 1, 0, ..., 0) \)
- Continuing to \( \vec{e}_n = (0, 0, 0, ..., 1) \)
In the original problem, \( \vec{w}_n \) is a sum of scaled basis vectors. This highlights how they are utilized to build complex vectors in \( \mathbb{R}^n \). The use of basis vectors simplifies many operations since they are orthogonal, making dot products straightforward and reducing computational errors.
Angle Between Vectors
For any vectors \( \vec{a} \) and \( \vec{b} \), the cosine of the angle \( \theta \) between them is given by:\[\cos \theta = \frac{\vec{a} \cdot \vec{b}}{\|\vec{a}\| \|\vec{b}\|}\]Here,
- \( \vec{a} \cdot \vec{b} \) denotes the dot product.
- \( \|\vec{a}\| \) and \( \|\vec{b}\| \) are the magnitudes of \( \vec{a} \) and \( \vec{b} \).