/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Find a parametrization of the su... [FREE SOLUTION] | 91Ó°ÊÓ

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Find a parametrization of the surface \(x^{2}-y^{2}=1\) where \(x>0,-1 \leq y \leq 1\) and \(0 \leq z \leq 1 .\) Use your answer to express the area of the surface as an integral.

Short Answer

Expert verified
Use \((x, y, z) = (\cosh(u), \sinh(u), v)\). Integrate \(\cosh(u)\) over \([-\sinh^{-1}(1), \sinh^{-1}(1)]\) and \([0, 1]\).

Step by step solution

01

Understanding the Surface Equation

The given surface equation is a hyperboloid defined by the equation \(x^2 - y^2 = 1\). This is a quadratic surface in three dimensions, specifically a hyperboloid of one sheet, constrained by \(x > 0\), \(-1 \leq y \leq 1\), and \(0 \leq z \leq 1\). Our task is to find a parameterization for this surface.
02

Choose Parametric Equations for x and y

We want a parameterization such that the relation \(x^2 - y^2 = 1 \) holds. A convenient way to parameterize such a relation is to use hyperbolic functions. Let's set \(x = \cosh(u)\) and \(y = \sinh(u)\), where \(u\) is a parameter. These functions satisfy \(x^2 - y^2 = \cosh^2(u) - \sinh^2(u) = 1\).
03

Add the z-parameter

Since \(z\) is independent of \(x\) and \(y\), it can be parametrized separately as simply \(z = v\), where \(0 \leq v \leq 1\). Thus, our complete parameterization of the surface becomes: \((x, y, z) = (\cosh(u), \sinh(u), v)\).
04

Specify the Range of Parameters

Given the constraints \(x > 0\) and \(-1 \leq y \leq 1\), we need to determine the suitable range for \(u\). Since \(\cosh(u)\) is always positive for all real \(u\), and \(-1 \leq \sinh(u) \leq 1\) implies \(-\sinh^{-1}(1) \leq u \leq \sinh^{-1}(1)\), the parameter ranges are: \(-\sinh^{-1}(1) \leq u \leq \sinh^{-1}(1)\) and \(0 \leq v \leq 1\).
05

Expressing the Area as an Integral

To find the area of the parametrized surface, we first need the tangent vectors \(\mathbf{r}_u\) and \(\mathbf{r}_v\). For \(\mathbf{r}(u,v) = (\cosh(u), \sinh(u), v)\), the tangent vectors are \(\mathbf{r}_u = (\sinh(u), \cosh(u), 0)\) and \(\mathbf{r}_v = (0, 0, 1)\). The magnitude of their cross product, \(\|\mathbf{r}_u \times \mathbf{r}_v\|\), gives the differential area element. The cross product results in: \(\mathbf{r}_u \times \mathbf{r}_v = (\cosh(u), -\sinh(u), 0)\), with magnitude \(\cosh(u)\). Thus, the area \(A\) is given by the integral:\[ A = \int_{v=0}^{1} \int_{u=-\sinh^{-1}(1)}^{\sinh^{-1}(1)} \cosh(u) \; du \; dv \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hyperboloid of One Sheet
A hyperboloid of one sheet is a type of quadric surface that appears frequently in algebra and geometry. Think of it like a three-dimensional shape that looks a bit like a curved hourglass or a cooling tower. It has two symmetrical curves that stretch infinitely and smoothly outward. The equation \(x^2 - y^2 = 1\) defines this hyperboloid in a slice of three-dimensional space, revealing its unique structure. Normally, without constraints, it spreads out infinitely both in positive and negative directions. Here, it is limited by the conditions \(x > 0\), \(-1 \leq y \leq 1 \), and \(0 \leq z \leq 1\). These conditions restrict its spread, only allowing a specific segment to be considered.
Overall, understanding the hyperboloid of one sheet helps recognize these distinct surfaces and adapt them as needed for different equations and constraints. In many applications, they offer important geometric properties and are found in various physical systems.
Parametric Equations
Parametric equations are a method to express geometric objects in math. Instead of writing \(x\), \(y\), and \(z\) directly from a standard equation, we describe them using parameters—this often simplifies the problem.
A great example of this is the hyperboloid equation \(x^2 - y^2 = 1\). By using parameters, specifically hyperbolic functions here, we parameterize the equation as \( x = \cosh(u) \) and \( y = \sinh(u) \). These functions are used because they satisfy the original equation: \( \cosh^2(u) - \sinh^2(u) = 1\). For the \(z\)-coordinate, since it’s independent of \(x\) and \(y\), it is simply parameterized as \(z = v\).
By choosing \(u\) and \(v\) as parameters, the three-dimensional surface can be expressed as a set of parametric equations: \((x, y, z) = (\cosh(u), \sinh(u), v)\). This parametrization also respects the constraints \(-\sinh^{-1}(1) \leq u \leq \sinh^{-1}(1)\) and \(0 \leq v \leq 1\), resulting in a neat way to work with the hyperboloid within the given restrictions and makes calculating areas or other properties easier.
Surface Area Integral
The surface area integral is a mathematical expression used to find the area of a surface described by parametric equations. It's an important tool in calculus when working with curved surfaces. By using parametric equations, one can derive tangent vectors necessary for setting up this integral.
For the problem involving the hyperboloid of one sheet, we start with a parameterization: \((x, y, z) = (\cosh(u), \sinh(u), v)\). Calculating the tangent vectors \(\mathbf{r}_u\) and \(\mathbf{r}_v\), we find \(\mathbf{r}_u = (\sinh(u), \cosh(u), 0)\) and \(\mathbf{r}_v = (0, 0, 1)\). These vectors help us determine the differential area element through their cross product, which is \(\mathbf{r}_u \times \mathbf{r}_v = (\cosh(u), -\sinh(u), 0)\).
  • The magnitude of this cross product, \(\cosh(u)\), is crucial for integrating over the surface.
  • The integral takes this magnitude and computes it over the parameter ranges for \(u\) and \(v\), giving us the total area.
Thus, the surface area \(A\) of the parametric surface can be expressed by the integral: \[ A = \int_{v=0}^{1} \int_{u=-\sinh^{-1}(1)}^{\sinh^{-1}(1)} \cosh(u) \, du \, dv \] This captures the area by summing up all the small differential elements defined over the parameter space.

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Most popular questions from this chapter

Let the curve \(y=f(x), a \leq x \leq b,\) be rotated about the \(y\) axis. Show that the area of the surface swept out is given by equation (6)\(;\) that is, $$A=2 \pi \int_{a}^{b}|x| \sqrt{1+\left[f^{\prime}(x)\right]^{2}} d x$$ Interpret the formula geometrically using arc length and slant height.

Evaluate \(\int_{c} f d s,\) where \(f(x, y, z)=z\) and \(\mathbf{c}(t)=(t \cos t, t \sin t, t)\) for \(0 \leq t \leq t_{0}\)

Find the area of the graph of the function \(f(x, y)=\) \(\frac{2}{3}\left(x^{3 / 2}+y^{3 / 2}\right)\) that lies over the domain \([0,1] \times[0,1]\).

Let \(\Phi(u, v)=\left(e^{u} \cos v, e^{u} \sin v, v\right)\) be a mapping from \(D=[0,1] \times[0, \pi]\) in the \(u v\) plane onto a surface \(S\) in \(x y z\) space. (a) Find \(T_{u} \times T_{v}\) (b) Find the equation for the tangent plane to \(S\) when \((u, v)=\left(0, \frac{\pi}{2}\right)\) (c) Find the area of \(\Phi(D)\)

Let \(\mathbf{c}:[a, b] \rightarrow \mathbb{R}^{3}\) be a path such that \(c^{\prime}(t) \neq 0 .\) Recall from Section 4.1 that when this condition holds, \(e\) is said to be regular. Let the function \(f\) be defined by the formula \(f(x)=\int_{a}^{x}\left[c^{\prime}(t)\right] d t\) (a) What is \(d f / d n ?\) (b) Using the answer to part (a), prove that \(f:[a, b] \rightarrow[0, L],\) where \(L\) is the length of \(c,\) has a differentiable inverse \(g:[0, L] \rightarrow[a, b]\) satisfying \(f \circ g(s)=s, g \circ f(x)=x .\) (You may use the one-variable inverse function theorem stated at the beginning of Section \(3.5 .)\) (c) Compute dg/ds. (d) Recall that a path \(s \rightarrow \mathbf{b}(s)\) is said to be of unit speed, or parametrized by are length, if \(1 \mathbf{b}^{\prime}(s) 1=1\) Show that the reparametrization of \(c\) given by \(\mathrm{b}(s)=c \circ g(s)\) is of unit speed. Conclude that any regular path can be reparametrized by are length. (Thus, for example, the Frener formulas in Exercise 23 of Section 4.2 can be applied to the reparametrization \(\mathbf{b} .\) )

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