Chapter 2: Problem 16
Let \(A=\left[\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right]\) (a) Considering \(A: \mathbb{R}^{2} \rightarrow \mathbb{R}^{2}\) as a linear map, explicitly write the component functions of \(A\) (b) Show that \(A\) is continuous on all of \(\mathbb{R}^{2}\).
Short Answer
Expert verified
The component functions are \(y_1 = x_1 + 2x_2\) and \(y_2 = 3x_1 + 4x_2\). Matrix \(A\) is continuous on \(\mathbb{R}^2\).
Step by step solution
01
Understanding Matrix-Vector Multiplication
Given the matrix \(A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix}\), and a vector \(\mathbf{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix}\), we want to express how \(A\) acts on \(\mathbf{x}\). The product \(A \mathbf{x}\) involves multiplying the matrix \([a_{ij}]\) by the vector \([x_j]\). This results in a new vector in \(\mathbb{R}^2\).
02
Writing the Component Functions
The matrix multiplication \(A \mathbf{x} = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \begin{bmatrix} x_1 \ x_2 \end{bmatrix}\) yields the components:\[ y_1 = 1 \cdot x_1 + 2 \cdot x_2 = x_1 + 2x_2 \]\[ y_2 = 3 \cdot x_1 + 4 \cdot x_2 = 3x_1 + 4x_2 \]Thus, the component functions are \(y_1 = x_1 + 2x_2\) and \(y_2 = 3x_1 + 4x_2\).
03
Definition of Continuity for Linear Maps
A linear map \(A: \mathbb{R}^2 \rightarrow \mathbb{R}^2\), represented by matrix \(A\), is continuous if for any sequence \(\mathbf{x}_n \rightarrow \mathbf{x}\) in \(\mathbb{R}^2\), the sequence \(A(\mathbf{x}_n) \rightarrow A(\mathbf{x})\). Continuity is guaranteed for linear maps initially defined on \(\mathbb{R}^n\) with real coefficients.
04
Showing Continuity of Matrix A
To show continuity, we need to verify that the limit definition holds. Let \(\mathbf{x}_n \rightarrow \mathbf{x}\), i.e., \(\mathbf{x}_n = \begin{bmatrix} x_{1,n} \ x_{2,n} \end{bmatrix} \rightarrow \begin{bmatrix} x_1 \ x_2 \end{bmatrix}\). Then,\[ A(\mathbf{x}_n) = \begin{bmatrix} x_{1,n} + 2x_{2,n} \ 3x_{1,n} + 4x_{2,n}\end{bmatrix} \rightarrow \begin{bmatrix} x_1 + 2x_2 \ 3x_1 + 4x_2 \end{bmatrix} = A(\mathbf{x}) \]Since the operations are algebraic and linear, and limits in linear operations such as addition and multiplication with real coefficients preserve continuity, hence \(A\) is continuous.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix-Vector Multiplication
Matrix-vector multiplication is a fundamental operation in linear algebra that involves a matrix and a vector. Given a matrix \( A = \begin{bmatrix} a_{11} & a_{12} \ a_{21} & a_{22} \end{bmatrix} \) and a vector \( \mathbf{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix} \), the multiplication \( A\mathbf{x} \) results in another vector. This operation can be seen as a series of dot products between rows of the matrix and the vector itself.
To illustrate, consider the matrix \( A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \) and vector \( \mathbf{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix} \). The multiplication proceeds as follows:
To illustrate, consider the matrix \( A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \) and vector \( \mathbf{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix} \). The multiplication proceeds as follows:
- Compute the dot product of the first row of \( A \) with \( \mathbf{x} \): \( y_1 = 1 \cdot x_1 + 2 \cdot x_2 = x_1 + 2x_2 \).
- Compute the dot product of the second row: \( y_2 = 3 \cdot x_1 + 4 \cdot x_2 = 3x_1 + 4x_2 \).
Linear Map
A linear map, in the context of linear algebra, is a function that models the transformation of vectors from one vector space to another, when represented by a matrix. The map preserves vector addition and scalar multiplication properties. For instance, if \( A: \mathbb{R}^2 \rightarrow \mathbb{R}^2 \) represents a linear map, as seen with matrix \( A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \), each input vector \( \mathbf{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix} \) generates outputs through component functions.
These component functions are derived from matrix-vector multiplication, and for \( A \), they are:
These component functions are derived from matrix-vector multiplication, and for \( A \), they are:
- \( y_1 = x_1 + 2x_2 \)
- \( y_2 = 3x_1 + 4x_2 \)
Continuity of Linear Transformations
The continuity of linear transformations is a key concept in both real analysis and linear algebra. For a linear map \( A: \mathbb{R}^2 \rightarrow \mathbb{R}^2 \), continuity means that small changes in the input vector \( \mathbf{x} \) result in small changes in the output \( A(\mathbf{x}) \).
To establish this, consider a sequence of vectors \( \mathbf{x}_n \rightarrow \mathbf{x} \) in \( \mathbb{R}^2 \). The corresponding outputs \( A(\mathbf{x}_n) \) must converge to \( A(\mathbf{x}) \). For the matrix \( A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \), this translates mathematically to:
To establish this, consider a sequence of vectors \( \mathbf{x}_n \rightarrow \mathbf{x} \) in \( \mathbb{R}^2 \). The corresponding outputs \( A(\mathbf{x}_n) \) must converge to \( A(\mathbf{x}) \). For the matrix \( A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \), this translates mathematically to:
- If \( \mathbf{x}_n = \begin{bmatrix} x_{1,n} \ x_{2,n} \end{bmatrix} \rightarrow \begin{bmatrix} x_1 \ x_2 \end{bmatrix} \), then \( A(\mathbf{x}_n) = \begin{bmatrix} x_{1,n} + 2x_{2,n} \ 3x_{1,n} + 4x_{2,n}\end{bmatrix} \rightarrow \begin{bmatrix} x_1 + 2x_2 \ 3x_1 + 4x_2 \end{bmatrix} = A(\mathbf{x}) \).