Chapter 1: Problem 8
Compute \(\|\mathbf{u}\|,\|\mathbf{v}\|,\) and \(\mathbf{u} \cdot \mathbf{v}\) for the given vectors in \(\mathbb{R}^{3}\). $$\mathbf{u}=5 \mathbf{i}-\mathbf{j}+2 \mathbf{k}, \mathbf{v}=\mathbf{i}+\mathbf{j}-\mathbf{k}$$
Short Answer
Expert verified
\( \|\mathbf{u}\| = \sqrt{30}, \|\mathbf{v}\| = \sqrt{3}, \mathbf{u} \cdot \mathbf{v} = 2 \)
Step by step solution
01
Calculate Magnitude of Vector \( \mathbf{u} \)
To find \( \|\mathbf{u}\| \), use the formula for the magnitude of a vector: \[ \|\mathbf{u}\| = \sqrt{u_1^2 + u_2^2 + u_3^2} \]Given \( \mathbf{u} = 5\mathbf{i} - \mathbf{j} + 2\mathbf{k} \), compute:\[ \|\mathbf{u}\| = \sqrt{5^2 + (-1)^2 + 2^2} = \sqrt{25 + 1 + 4} = \sqrt{30} \]
02
Calculate Magnitude of Vector \( \mathbf{v} \)
To find \( \|\mathbf{v}\| \), use the magnitude formula:\[ \|\mathbf{v}\| = \sqrt{v_1^2 + v_2^2 + v_3^2} \]Given \( \mathbf{v} = \mathbf{i} + \mathbf{j} - \mathbf{k} \), compute:\[ \|\mathbf{v}\| = \sqrt{1^2 + 1^2 + (-1)^2} = \sqrt{1 + 1 + 1} = \sqrt{3} \]
03
Calculate Dot Product \( \mathbf{u} \cdot \mathbf{v} \)
To compute the dot product, apply the formula:\[ \mathbf{u} \cdot \mathbf{v} = u_1v_1 + u_2v_2 + u_3v_3 \]For \( \mathbf{u} = 5\mathbf{i} - \mathbf{j} + 2\mathbf{k} \) and \( \mathbf{v} = \mathbf{i} + \mathbf{j} - \mathbf{k} \):\[ \mathbf{u} \cdot \mathbf{v} = 5 \times 1 + (-1) \times 1 + 2 \times (-1) = 5 - 1 - 2 = 2 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of a Vector
The magnitude of a vector is an important concept in vector calculus. It represents the length or the size of the vector. In a three-dimensional space, any vector is composed of three components, typically represented by the basis vectors \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \). For example, a vector \( \mathbf{u} \) can be expressed as \( u_1 \mathbf{i} + u_2 \mathbf{j} + u_3 \mathbf{k} \). Each coefficient \( u_1, u_2, \) and \( u_3 \) stands for the component of the vector along the respective axes.
To calculate the magnitude of such a vector, you can utilize the formula: \[ \|\mathbf{u}\| = \sqrt{u_1^2 + u_2^2 + u_3^2} \]This is an application of the Pythagorean theorem in three dimensions, which combines the squares of the vector's components into one square rooted value.
To calculate the magnitude of such a vector, you can utilize the formula: \[ \|\mathbf{u}\| = \sqrt{u_1^2 + u_2^2 + u_3^2} \]This is an application of the Pythagorean theorem in three dimensions, which combines the squares of the vector's components into one square rooted value.
- First, square each component of the vector.
- Sum up all squared components.
- Finally, take the square root of this sum to find the magnitude.
Dot Product
The dot product, also known as the scalar product, is a fundamental operation between two vectors that results in a scalar. It measures how much one vector extends in the direction of another, essentially projecting one vector onto the other. The dot product of two vectors \( \mathbf{u} = u_1 \mathbf{i} + u_2 \mathbf{j} + u_3 \mathbf{k} \) and \( \mathbf{v} = v_1 \mathbf{i} + v_2 \mathbf{j} + v_3 \mathbf{k} \) is calculated by:\[ \mathbf{u} \cdot \mathbf{v} = u_1v_1 + u_2v_2 + u_3v_3 \]Performing the dot product involves:
- Multiplying the corresponding components of the vectors along each axis.
- Adding the results of these multiplications.
- If the dot product is zero, it means the two vectors are orthogonal (perpendicular) to each other.
- The dot product can also help to find the angle between two vectors using the cosine relation.
Vectors in 3D
Vectors in three-dimensional space exhibit a broader range of interactions compared to their two-dimensional counterparts. A vector in 3D is represented not just with an \( x \) and \( y \) component, but also with a \( z \) component, typically expressed as \( \mathbf{i}, \mathbf{j}, \) and \( \mathbf{k} \) basis vectors. This augmentation allows for modeling movements and forces in real-world phenomena more accurately.
Each vector can be visualized as an arrow in space, where:
Each vector can be visualized as an arrow in space, where:
- The tail of the vector is positioned at the origin of the coordinate system.
- The head of the vector points toward its coordinates \( (u_1, u_2, u_3) \).
- They facilitate the representation of forces, velocities, and positions.
- In graphics, vectors help in operations like rotations and scaling.