Chapter 1: Problem 20
Show that \(\mathbf{I}_{1}(t)=(1,2,3)+t(1,0,-2)\) and \(\mathbf{l}_{2}(t)=(2,2,1)+t(-2,0,4)\) parametrize the same line.
Short Answer
Expert verified
Both lines are the same because they have collinear direction vectors and share a common point.
Step by step solution
01
Establish the Direction Vectors
First, identify the direction vectors of both lines. For \( \mathbf{I}_{1}(t) \), the direction vector is \( \mathbf{d}_{1} = (1, 0, -2) \). For \( \mathbf{l}_{2}(t) \), the direction vector is \( \mathbf{d}_{2} = (-2, 0, 4) \).
02
Verify Collinearity of Direction Vectors
Check if the direction vectors are collinear by finding if one is a scalar multiple of the other. \[ \mathbf{d}_1 = (1, 0, -2) = -\frac{1}{2} \times (-2, 0, 4) = -\frac{1}{2} \times \mathbf{d}_2 \] Thus, the direction vectors are collinear.
03
Check a Common Point on Both Lines
Find a common point between the two lines to confirm they are actually the same line. For \( \mathbf{I}_{1}(t) \), when \( t=0 \), the point is \( (1, 2, 3) \). For \( \mathbf{l}_{2}(t) \), substitute and solve: \( (2, 2, 1) + t(-2, 0, 4) = (1, 2, 3) \). This leads to the system of equations: \[ 2 - 2t = 1 \] \[ 2 = 2 \] \[ 1 + 4t = 3 \]. Solving gives \( t = \frac{1}{2} \). Substitute back: \( (2, 2, 1) + \frac{1}{2}(-2, 0, 4) = (1, 2, 3) \) confirms a common point.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations are a powerful tool in mathematics, particularly in vector calculus and geometry, to represent lines, curves, or surfaces. They allow us to express the coordinates of points on a geometrical shape as functions of one or more parameters.
The general form of a parametric equation for a line in three-dimensional space is given by:
\( \vec{r}(t) = \vec{a} + t\vec{d} \),
where \( \vec{a} \) is a point on the line (also called the position vector) and \( \vec{d} \) is the direction vector of the line. The parameter \( t \) is a real number, typically representing time.
The general form of a parametric equation for a line in three-dimensional space is given by:
\( \vec{r}(t) = \vec{a} + t\vec{d} \),
where \( \vec{a} \) is a point on the line (also called the position vector) and \( \vec{d} \) is the direction vector of the line. The parameter \( t \) is a real number, typically representing time.
- Parametric Equations provide flexibility: You can easily obtain any point on the line by altering the parameter \( t \).
- They simplify the representation of curves, which are difficult to express using traditional equations in three-dimensional space.
Direction Vectors
Direction vectors play a pivotal role in defining the orientation of a line in space. They are vectors that indicate the direction in which a line extends.
For a parametric line equation \( \vec{r}(t) = \vec{a} + t\vec{d} \), \( \vec{d} \) is the direction vector.
The direction vector helps us determine several properties of a line:
For a parametric line equation \( \vec{r}(t) = \vec{a} + t\vec{d} \), \( \vec{d} \) is the direction vector.
The direction vector helps us determine several properties of a line:
- Collinearity: If two lines have direction vectors that are scalar multiples of each other, those lines are parallel or collinear.
- Line Uniqueness: A direction vector defines the unique direction of the line, but not its position.
Collinearity
Collinearity is a fundamental concept that describes when points or vectors lie on the same line. For vectors, collinearity occurs when one vector can be expressed as a scalar multiple of another.
In the context of direction vectors, checking for collinearity involves:
\( \mathbf{d}_1 = (1, 0, -2) = -\frac{1}{2} \times (-2, 0, 4) = -\frac{1}{2} \times \mathbf{d}_2 \).
Because a scalar \( k \) was found, we confirmed that the lines share collinear direction vectors.
In the context of direction vectors, checking for collinearity involves:
- Finding if there exists a constant \( k \) such that one direction vector \( \mathbf{d}_1 \) can be expressed as \( k \mathbf{d}_2 \).
\( \mathbf{d}_1 = (1, 0, -2) = -\frac{1}{2} \times (-2, 0, 4) = -\frac{1}{2} \times \mathbf{d}_2 \).
Because a scalar \( k \) was found, we confirmed that the lines share collinear direction vectors.
Line Equations
Line Equations are essential for understanding and describing lines in both two-dimensional and three-dimensional spaces.
In three dimensions, a line can be expressed using parametric equations, whereas in two dimensions, either slope-intercept or point-slope forms are typically used.
Key elements of three-dimensional line equations include:
In three dimensions, a line can be expressed using parametric equations, whereas in two dimensions, either slope-intercept or point-slope forms are typically used.
Key elements of three-dimensional line equations include:
- Position Vector \( \vec{a} \): A point through which the line passes.
- Direction Vector \( \vec{d} \): Defines the line's orientation in space.
- Parameter \( t \): Determines points along the line when substituted into the equation.