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91Ó°ÊÓ

Which series converge, and which diverge? Give reasons for your answers. If a series converges, find its sum. $$\sum_{n=0}^{\infty} \frac{e^{n \pi}}{\pi^{n e}}$$

Short Answer

Expert verified
The series diverges because its common ratio \( r > 1 \).

Step by step solution

01

Analyze the Form of the Series

The given series is \( \sum_{n=0}^{\infty} \frac{e^{n \pi}}{\pi^{n e}} \). To analyze convergence, observe that the term of the series, \( a_n = \frac{e^{n \pi}}{\pi^{n e}} \), resembles a geometric series term form \( ar^n \), where \( a = 1 \) and \( r = \frac{e^{\pi}}{\pi^e} \).
02

Check Convergence of Geometric Series

A geometric series \( \sum a r^n \) converges if the absolute value of the common ratio \( |r| < 1 \). Calculate the common ratio here: \( r = \frac{e^{\pi}}{\pi^e} \).
03

Determine if the Ratio \( r \) is Less Than 1

Evaluate the expression \( r = \frac{e^{\pi}}{\pi^e} \) to see if it is less than 1. Knowing the values, \( e^{\pi} > 23 \) and \( \pi^e \) is approximately 22.459, it appears as \( r > 1 \).
04

Conclusion on Convergence or Divergence

Since \( r > 1 \), the series does not satisfy \( |r| < 1 \). Therefore, the series \( \sum_{n=0}^{\infty} \frac{e^{n \pi}}{\pi^{n e}} \) diverges as it resembles a geometric series with a ratio greater than 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Series
A geometric series is a series of terms that are generated from a constant ratio between subsequent terms. This characteristic makes it distinctively easy to identify and analyze. Each term in a geometric series can be denoted as \( a r^n \), where \( a \) is the first term (often referred to as the initial term), \( r \) is the constant ratio (known as the common ratio), and \( n \) represents the term number.
A classic example of a geometric series is the sequence \( 2, 4, 8, 16, \ldots \), where the common ratio \( r \) is 2. Each term is obtained by multiplying the previous term by the common ratio.
Understanding the geometric structure helps determine whether such a series converges or diverges.
Common Ratio
The common ratio is a crucial component in defining the behavior of a geometric series. It is derived from the ratio between any two successive terms in the series.
Mathematically, the common ratio \( r \) is defined as \( \frac{a_{n+1}}{a_n} \) for a geometric series.
In the series presented in the exercise, the common ratio is calculated as \( r = \frac{e^{\pi}}{\pi^e} \).
Understanding and identifying the common ratio allows us to apply convergence tests, such as the criteria for convergence of a geometric series.
Criteria for Convergence
The convergence of a geometric series is heavily reliant on its common ratio. The criteria to determine if a geometric series \( \sum ar^n \) converges is given by:
  • If \( |r| < 1 \), the series converges.
  • If \( |r| \geq 1 \), the series diverges.

This is because when the magnitude of \( r \) is less than 1, the terms get progressively smaller and sum to a finite limit. Conversely, if \( r \) is equal to or greater than 1, the terms do not decrease in magnitude, leading to a series that perpetually grows.
For our series, the calculated common ratio \( r = \frac{e^{\pi}}{\pi^e} \) is greater than 1, which indicates that the series diverges.
Divergence of Series
In the context of series, divergence indicates that the series does not settle to a fixed sum even if infinitely many terms are added. A divergent series essentially has a sum that tends to infinity or oscillates without reaching a finite value.
For the given series \( \sum_{n=0}^{\infty} \frac{e^{n \pi}}{\pi^{n e}} \), the divergence is mainly due to the fact that the calculated common ratio is greater than 1. This conclusion stems from the failure to meet the criteria for convergence of a geometric series.
Recognizing the divergence of a series is crucial, as it dictates that one cannot assign a finite sum to the series, reflecting its infinite or unbounded nature.

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