Chapter 9: Problem 58
Which series converge, and which diverge? Give reasons for your answers. If a series converges, find its sum. $$\sum_{n=0}^{\infty} \frac{\cos n \pi}{5^{n}}$$
Short Answer
Expert verified
The series converges, and its sum is \( \frac{5}{6} \).
Step by step solution
01
Identify the series
The given series is \( \sum_{n=0}^{\infty} \frac{\cos n \pi}{5^{n}} \). For each term, \( \cos n \pi \) alternates between 1 and -1 depending on whether \( n \) is even or odd.
02
Analyze series structure
The series is an infinite geometric series because the common ratio is \( r = \frac{-1}{5} \) when \( n \) is odd and \( r = \frac{1}{5} \) when \( n \) is even. Since \( \vert r \vert < 1 \), this series has the potential to converge.
03
Find the first term (a)
The first term of the series \( a \) is when \( n = 0 \), which results in \( \frac{\cos(0 \cdot \pi)}{5^0} = 1 \).
04
Determine if the series converges
For a geometric series to converge, the absolute value of the common ratio must be less than 1. Here, \( \left| \frac{1}{5} \right| < 1 \) confirms convergence.
05
Calculate the sum of the series
The sum \( S \) of an infinite geometric series is given by the formula \( S = \frac{a}{1 - r} \). Here, \( a = 1 \) and \( r = -\frac{1}{5} \). Substituting the values into the formula, we get: \[ S = \frac{1}{1 - (-\frac{1}{5})} = \frac{1}{1 + \frac{1}{5}} = \frac{1}{\frac{6}{5}} = \frac{5}{6}. \]
06
Conclusion
The series \( \sum_{n=0}^{\infty} \frac{\cos n \pi}{5^{n}} \) converges, and its sum is \( \frac{5}{6} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a series of terms in which each term is a constant multiple, known as the common ratio, of the previous term. To identify a geometric series, you can look for a sequence where each term is obtained by multiplying the preceding term by a fixed non-zero number, called the common ratio, denoted as \( r \). This gives the general form:
The formula for the sum \( S \) of an infinite geometric series is:
- \( a, ar, ar^2, ar^3, \, ... \)
The formula for the sum \( S \) of an infinite geometric series is:
- \( S = \frac{a}{1 - r} \)
Infinite Series
An infinite series is a sum of infinitely many terms defined by a specific rule or pattern. It's denoted as \( \sum_{n=0}^{\infty} a_n \), where each \( a_n \) represents the terms of the series. When dealing with infinite series, a crucial aspect is determining whether a series converges or diverges. If a series converges, the sum of its terms approaches a specific finite value as the number of terms increases indefinitely. On the other hand, if a series diverges, the sum does not approach a finite value.
There are several tests used to determine convergence:
There are several tests used to determine convergence:
- Comparison Test: Compare with a known convergent or divergent series.
- Ratio Test: Useful for series where terms involve factorials or powers.
- Root Test: Similar to the ratio test, works with powers.
Alternating Series
An alternating series is a series in which the terms alternate in sign. This can be seen in series where the terms contain factors like \( (-1)^n \) or \( \cos(n\pi) \), which alternate between positive and negative as \( n \) increases. Alternating series often take the general form:
- \( a_1 - a_2 + a_3 - a_4 + \ldots \)
- The absolute values of the terms \( a_n \) decrease monotonically: \( a_{n+1} \leq a_n \) for all \( n \).
- The terms approach zero: \( \lim_{{n \to \infty}} a_n = 0 \).