Chapter 9: Problem 43
Converge, and which diverge? Use any method, and give reasons for your answers. $$\sum_{n=2}^{\infty} \frac{1}{n !}$$ (Hint: First show that \((1 / n !) \leq(1 / n(n-1))\) for \(n \geq 2\).)
Short Answer
Expert verified
The series \( \sum_{n=2}^{\infty} \frac{1}{n!} \) converges by the Comparison Test.
Step by step solution
01
Understand the Series
The series given is \( \sum_{n=2}^{\infty} \frac{1}{n!} \). This is an infinite series where each term is the reciprocal of the factorial of \( n \), starting from \( n=2 \).
02
Apply the Comparison Test
To determine the convergence of the series, we will use the Comparison Test. The hint suggests showing that \( \frac{1}{n!} \leq \frac{1}{n(n-1)} \) for \( n \geq 2 \).
03
Prove the Inequality
For \( n \geq 2 \), calculate \( n! = n \times (n-1) \times \ldots \times 2 \times 1 \). Therefore, \( n! \geq n(n-1) \), which implies \( \frac{1}{n!} \leq \frac{1}{n(n-1)} \).
04
Recognize the Comparison Series
The series \( \sum_{n=2}^{\infty} \frac{1}{n(n-1)} \) is known as a telescoping series. Its partial sums simplify significantly.
05
Analyze the Comparison Series
Rewrite \( \frac{1}{n(n-1)} \) using partial fractions as \( \frac{1}{n-1} - \frac{1}{n} \). This makes the series \( \sum_{n=2}^{\infty} \left( \frac{1}{n-1} - \frac{1}{n} \right) \).
06
Evaluate Convergence of the Comparison Series
This is a telescoping series, which means its terms cancel out over time. The series converges to 1. Since the original series \( \frac{1}{n!} \leq \frac{1}{n(n-1)} \) fits under a convergent series, it also converges by the Comparison Test.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Comparison Test
The Comparison Test is a powerful mathematical tool used to determine the convergence or divergence of an infinite series. It involves comparing a given series with another series whose convergence behavior is already known. The basic idea is straightforward:
In the exercise, we use the Comparison Test by proving that each term of our series \( \frac{1}{n!} \) is less than or equal to the terms of the comparison series \( \frac{1}{n(n-1)} \). The comparison series is known to be convergent, thereby proving the convergence of the original series.
- If the terms of the given series are smaller than the terms of a known convergent series and all terms are non-negative, the original series converges.
- Conversely, if the terms of the original series are larger than those of a known divergent series, it diverges.
In the exercise, we use the Comparison Test by proving that each term of our series \( \frac{1}{n!} \) is less than or equal to the terms of the comparison series \( \frac{1}{n(n-1)} \). The comparison series is known to be convergent, thereby proving the convergence of the original series.
Telescoping Series
A telescoping series is a series where most terms cancel during summation. When the terms cancel, only a few terms from the beginning and the end of the series remain, greatly simplifying the sum.
An example of a telescoping series is \( \sum_{n=2}^{\infty} \left( \frac{1}{n-1} - \frac{1}{n} \right) \). When expanded, this series's terms cancel in succession:
An example of a telescoping series is \( \sum_{n=2}^{\infty} \left( \frac{1}{n-1} - \frac{1}{n} \right) \). When expanded, this series's terms cancel in succession:
- \( \left( \frac{1}{1} - \frac{1}{2} \right) + \left( \frac{1}{2} - \frac{1}{3} \right) + \left( \frac{1}{3} - \frac{1}{4} \right) + \cdots \)
- Almost every term in the series after the \( \frac{1}{1} \) term cancels out with its corresponding pair, leaving us with only the first fraction and the last in the expanded sequence.
Factorial
The factorial of a non-negative integer \( n \), denoted as \( n! \), is the product of all positive integers less than or equal to \( n \). Factorials grow very fast as \( n \) increases, illustrated as follows:
Factorials are fundamental in combinatorial mathematics, with applications ranging from evaluating permutations to solving sequence problems, making them an essential part of mathematical studies and analyses.
- \( 0! = 1 \)
- \( 1! = 1 \)
- \( 2! = 2 \times 1 = 2 \)
- \( 3! = 3 \times 2 \times 1 = 6 \)
- \( 4! = 4 \times 3 \times 2 \times 1 = 24 \)
Factorials are fundamental in combinatorial mathematics, with applications ranging from evaluating permutations to solving sequence problems, making them an essential part of mathematical studies and analyses.