Chapter 9: Problem 35
Find the first three nonzero terms of the Maclaurin series for each function. $$f(x)=\cos x-(2 /(1-x))$$
Short Answer
Expert verified
The first three nonzero terms are \(-1\), \(-2x\), and \(-\frac{5x^2}{2}\).
Step by step solution
01
Understand the Maclaurin Series
The Maclaurin series is a type of Taylor series centered at 0. For a function \(f(x)\), it is represented as \(f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + \ldots\). Our task is to find the first three nonzero terms.
02
Determine the Maclaurin Series for \(\cos x\)
The Maclaurin series for \(\cos x\) is \(1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots\). We focus on the first three nonzero terms: \(\cos x = 1 - \frac{x^2}{2} + \frac{x^4}{24}\).
03
Determine the Maclaurin Series for \(\frac{2}{1-x}\)
The function \(\frac{2}{1-x}\) can be expanded using the geometric series with a factor of 2: \(2(1 + x + x^2 + x^3 + \cdots) = 2 + 2x + 2x^2 + 2x^3 + \cdots\). We will need the component up to \(x^2\) and verify what impacts deterministically beyond this.
04
Calculate the Maclaurin Series for \(f(x) = \cos x - \frac{2}{1-x}\)
Subtract the series of \(\frac{2}{1-x}\) from the series of \(\cos x\): - \(1 - \frac{x^2}{2} + \frac{x^4}{24}\)- \(-2 - 2x - 2x^2\)Combining terms, we get:\(-1 - 2x + \left(-\frac{x^2}{2} - 2x^2\right) + \frac{x^4}{24}\). Simplify to:\[-1 - 2x - \frac{5x^2}{2} + \frac{x^4}{24} + \cdots\]
05
Identify the First Three Nonzero Terms
The series derived is \(-1 - 2x - \frac{5x^2}{2} + \frac{x^4}{24} + \ldots\). The first three nonzero terms are \(-1\), \(-2x\), and \(-\frac{5x^2}{2}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor Series
The Taylor Series is a powerful mathematical tool used to represent functions as infinite sums of terms calculated from the values of their derivatives at a single point. Specifically, a Maclaurin series is a special case of the Taylor series, centered at zero. For any differentiable function \( f(x) \), the Taylor series expands as:
In the case of the Maclaurin series, where the expansion is about \( a = 0 \), the series simplifies to:
This representation is particularly useful in approximating complex functions with polynomial terms, especially for values of \( x \) close to zero. By following the Taylor series formula, we can systematically derive series for functions like \( \cos x \) and \( \frac{2}{1-x} \), helping us better understand their behavior around the origin.
- \( f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f'''(a)}{3!}(x-a)^3 + \ldots \)
In the case of the Maclaurin series, where the expansion is about \( a = 0 \), the series simplifies to:
- \( f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + \cdots \)
This representation is particularly useful in approximating complex functions with polynomial terms, especially for values of \( x \) close to zero. By following the Taylor series formula, we can systematically derive series for functions like \( \cos x \) and \( \frac{2}{1-x} \), helping us better understand their behavior around the origin.
Geometric Series
The geometric series is another essential concept in mathematics, representing a series of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the ratio. A geometric series can be expressed as:
where \( a \) is the first term and \( r \) is the common ratio. When \(|r| < 1\), the series converges to a sum given by:
For the function \( \frac{2}{1-x} \), we can expand it using the geometric series formula by recognizing it as:
This expansion is tremendously useful in deriving the Maclaurin series by yielding straightforward expressions for terms in the form of powers of \( x \). Thus, it complements the process of deriving a combined series representation when functions like \( \cos x \) are involved.
- \( a + ar + ar^2 + ar^3 + \ldots \)
where \( a \) is the first term and \( r \) is the common ratio. When \(|r| < 1\), the series converges to a sum given by:
- \( \frac{a}{1-r} \)
For the function \( \frac{2}{1-x} \), we can expand it using the geometric series formula by recognizing it as:
- \( 2 \cdot \left( 1 + x + x^2 + x^3 + \cdots \right) \)
This expansion is tremendously useful in deriving the Maclaurin series by yielding straightforward expressions for terms in the form of powers of \( x \). Thus, it complements the process of deriving a combined series representation when functions like \( \cos x \) are involved.
Cosine Function
The cosine function is a fundamental trigonometric function that can be expanded into an infinite series using the Maclaurin series approach. Known for its even periodic nature, the Maclaurin series for \( \cos x \) is given by:
This series results from repeatedly taking derivatives of \( \cos x \) and evaluating them at \( x = 0 \). Because the cosine function is even (symmetric about the \( y \)-axis), the series only contains even-powered \( x \) terms. It provides an accurate approximation of the cosine function near \( x = 0 \), with each additional term improving accuracy.
When finding the Maclaurin series for composite functions like \( \cos x - \frac{2}{1-x} \), understanding this expansion is crucial. It enables us to systematically subtract or combine terms, as demonstrated in our original exercise, to achieve the desired polynomial approximation.
- \( \cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots \)
This series results from repeatedly taking derivatives of \( \cos x \) and evaluating them at \( x = 0 \). Because the cosine function is even (symmetric about the \( y \)-axis), the series only contains even-powered \( x \) terms. It provides an accurate approximation of the cosine function near \( x = 0 \), with each additional term improving accuracy.
- For the first three terms, we have: \( 1 - \frac{x^2}{2} + \frac{x^4}{24} \).
When finding the Maclaurin series for composite functions like \( \cos x - \frac{2}{1-x} \), understanding this expansion is crucial. It enables us to systematically subtract or combine terms, as demonstrated in our original exercise, to achieve the desired polynomial approximation.