Chapter 9: Problem 27
Find a polynomial that will approximate \(F(x)\) throughout the given interval with an error of magnitude less than \(10^{-3}\) $$F(x)=\int_{0}^{x} \tan ^{-1} t d t, \quad \text { (a) }[0,0.5] \quad \text { (b) }[0,1]$$
Short Answer
Expert verified
Approximate polynomial:
\( F(x) = \frac{x^2}{2} - \frac{x^4}{12} + \frac{x^6}{30} \) for \([0,0.5]\)
and add \(-\frac{x^8}{56}\) for \([0,1]\).
Step by step solution
01
Define the Function
The given function is an integral of the inverse tangent function: \( F(x) = \int_{0}^{x} \tan^{-1}(t) \, dt \). We need to find a polynomial approximation for \( F(x) \) that maintains the error less than \( 10^{-3} \) over the specified intervals.
02
Taylor Series Expansion
To approximate \( \tan^{-1}(t) \), use its Taylor series: \( \tan^{-1}(t) = t - \frac{t^3}{3} + \frac{t^5}{5} - \frac{t^7}{7} + \cdots \). This series is centered at 0 and valid for \( |t| \leq 1 \).
03
Integrate the Series
Integrate the series term-by-term to approximate \( F(x) \):\[F(x) = \int_{0}^{x} \tan^{-1}(t) \, dt \approx \int_{0}^{x} \left( t - \frac{t^3}{3} + \frac{t^5}{5} - \cdots \right) dt.\]Integrating term by term, we obtain: \[F(x) \approx \left[ \frac{t^2}{2} - \frac{t^4}{12} + \frac{t^6}{30} - \cdots \right]_{0}^{x} \approx \frac{x^2}{2} - \frac{x^4}{12} + \frac{x^6}{30} - \cdots\]
04
Determine Necessary Terms for Desired Accuracy
To ensure the error is less than \( 10^{-3} \), estimate the remainder by calculating the next term for both intervals. Calculate the term values for \( x = 0.5 \) and \( x = 1 \) to determine the necessary truncation for accuracy. Each term is \( \frac{-1^n}{2n+1} \cdot \frac{x^{2n+2}}{(2n+2)} \) where the successive terms must be evaluated until the remainder term's absolute value is below \( 10^{-3} \).
05
Simplify Polynomial
For interval \([0,0.5]\), use terms up to \( x^6 \), as higher powers contribute negligibly small errors. For interval \([0,1]\), estimate at which power truncation keeps the error below \( 10^{-3} \). Typically, terms beyond \( x^8 \) for \([0, 1]\) should be negligible.
06
Approximate Polynomial
Through calculations, the polynomial satisfying the error condition on both intervals can be approximated as:\[F(x) \approx \begin{cases} \frac{x^2}{2} - \frac{x^4}{12} + \frac{x^6}{30}, & [0,0.5] \ \frac{x^2}{2} - \frac{x^4}{12} + \frac{x^6}{30} - \frac{x^8}{56}, & [0,1] \end{cases}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor Series
The Taylor Series is a powerful tool for approximating functions around a given point using polynomials. In essence, it transforms a complex function into a series of simpler polynomials that are easier to handle and calculate. For the function \( \tan^{-1}(t) \), its Taylor series expansion is:
- \( \tan^{-1}(t) = t - \frac{t^3}{3} + \frac{t^5}{5} - \frac{t^7}{7} + \cdots \)
Definite Integral
Understanding the concept of a definite integral is crucial when seeking to approximate a function like in our exercise. A definite integral of a function, \( \int_a^b f(t) \, dt \), represents the area under the curve \( f(t) \) from \( t = a \) to \( t = b \).
- This area gives us important insights into things such as the accumulated change or total quantity over a certain interval.
Error Estimation
Error estimation is an essential aspect of polynomial approximations. It helps determine how accurately our polynomial represents the original function within a certain range. By carefully analyzing the error, we ensure that our approximation is within acceptable limits, like less than \( 10^{-3} \) in our exercise.
- The error is primarily determined by the terms that we choose to include or exclude in the series.
Inverse Trigonometric Functions
Inverse trigonometric functions, such as \( \tan^{-1}(x) \), are functions that help us find the angle associated with a given trigonometric value. They reverse the action of the standard trigonometric functions, reflecting their pivotal role in various mathematical fields.
- The function \( \tan^{-1}(t) \) is particularly important, as it provides the angle whose tangent is \( t \).