Chapter 9: Problem 13
Find the Maclaurin serics for the functions in Exercises \(11-24\) $$\frac{1}{1+x}$$
Short Answer
Expert verified
\( \frac{1}{1+x} = \sum_{n=0}^{\infty} (-1)^n x^n \) for \(|x| < 1\).
Step by step solution
01
Identify the Function and Maclaurin Series
We need to find the Maclaurin series for \( f(x) = \frac{1}{1+x} \). A Maclaurin series is a Taylor series expansion of a function about \( x = 0 \) and is given by \( f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!}x^n \).
02
Recognize the Geometric Series
The function \( \frac{1}{1+x} \) resembles the sum of an infinite geometric series \( \sum_{n=0}^{\infty} (-1)^n x^n \). This is because for \(|x| < 1\), the series \( \frac{1}{1-t} = \sum_{n=0}^{\infty} t^n \) holds, and our function can be written as \( \frac{1}{1-(-x)} \).
03
Write the Series Form
Using the geometric series formula, the Maclaurin series for \( \frac{1}{1+x} \) is \( \sum_{n=0}^{\infty} (-1)^n x^n \). This series is valid for \(|x| < 1\).
04
Summarize the Maclaurin Series
Thus, the Maclaurin series for \( \frac{1}{1+x} \) is \[ 1 - x + x^2 - x^3 + x^4 - \cdots \] which is \( \sum_{n=0}^{\infty} (-1)^n x^n \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor Series
The Taylor series is a powerful mathematical tool used to approximate functions. It works by expressing a function as an infinite sum of terms calculated from the values of its derivatives at a single point. This means we can write a function as:
- \( f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots \)
Geometric Series
A geometric series is a series with a constant ratio between successive terms. It typically takes the form
- \( S = a + ar + ar^2 + ar^3 + \cdots \)
- \( S = \frac{a}{1-r} \)
Power Series
A power series is a series of the form:
- \( \sum_{n=0}^{\infty} a_n (x-c)^n \)
- \( \sum_{n=0}^{\infty} a_n x^n \)
Convergence Radius
The convergence radius is a critical concept when working with series such as Taylor, Maclaurin, and power series. It defines the extent or region in which the series converges to the function it represents. For a series centered at \(c\), convergence occurs when \(|x-c| < R\), where \(R\) is the radius of convergence. For instance, the series representing \(\frac{1}{1+x}\),
- \( \sum_{n=0}^{\infty} (-1)^n x^n \)