Chapter 9: Problem 102
Show that the error \(\left(L-s_{n}\right)\) obtained by replacing a convergent geometric series with one of its partial sums \(s_{n}\) is \(a r^{n} /(1-r)\).
Short Answer
Expert verified
The error is \( \frac{ar^n}{1-r} \).
Step by step solution
01
Understanding the Geometric Series
A geometric series is a series of the form \( a + ar + ar^2 + ar^3 + \cdots \). If \( |r| < 1 \), the series converges to \( L = \frac{a}{1-r} \). Here, \( a \) is the first term and \( r \) is the common ratio.
02
Define a Partial Sum
The partial sum \( s_n \) of the first \( n \) terms of a geometric series is given by \( s_n = a + ar + ar^2 + \cdots + ar^{n-1} \). This sum can be represented by the formula \( s_n = \frac{a(1-r^n)}{1-r} \).
03
Defining the Error Term
The error \( (L - s_n) \) represents the difference between the sum \( L \) of the infinite series and the partial sum \( s_n \). This can be written as \( (L - s_n) = \frac{a}{1-r} - \frac{a(1-r^n)}{1-r} \).
04
Simplify the Error Term
To simplify \( L - s_n \), use the formula expressions: \[ L - s_n = \frac{a}{1-r} - \frac{a(1-r^n)}{1-r} \]. Subtract the two fractions: \( L - s_n = \frac{a - a(1-r^n)}{1-r} = \frac{a - a + ar^n}{1-r} \).
05
Final Simplification
Simplify the expression \( \frac{a - a + ar^n}{1-r} \) to get \( \frac{ar^n}{1-r} \), which is the error in approximating the infinite sum by the partial sum \( s_n \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Sum
The concept of a partial sum is essential to understanding any series, including geometric series. In a geometric series, a partial sum refers to the sum of the first few terms of the series. For instance, if we have a geometric series like
- \( a + ar + ar^2 + ar^3 + \cdots \)
- where \( a \) is the first term and \( r \) is the common ratio.
- \( s_n = a + ar + ar^2 + \cdots + ar^{n-1} \).
- \( s_n = \frac{a(1-r^n)}{1-r} \).
Convergent Series
A geometric series is said to be convergent if the series approaches a particular value as more and more terms are added. Specifically, a geometric series
- \( a + ar + ar^2 + ar^3 + \cdots \)
- \( |r| < 1 \).
- \( L = \frac{a}{1-r} \).
Error Analysis
When working with convergent series, determining the error is crucial, especially because we often approximate these sums using just a few terms (a partial sum) rather than calculating an infinite number of terms. The error here is the difference between the actual sum of the series (the limit \( L \)) and the partial sum \( s_n \). This is denoted mathematically as
- \( (L - s_n) \).
- \( (L - s_n) = \frac{a}{1-r} - \frac{a(1-r^n)}{1-r} \).
- \( \frac{ar^n}{1-r} \).