Chapter 8: Problem 39
Evaluate the integrals $$\int_{-\pi / 3}^{0} 2 \sec ^{3} x d x$$
Short Answer
Expert verified
The value of the integral is \( \frac{2}{3} (7 - 8 + 3\sqrt{3}) \).
Step by step solution
01
Set up the integral
We start by considering the integral we need to evaluate, which is \( \int_{-\pi / 3}^{0} 2 \sec^{3} x \, dx \). This is a definite integral with limits from \( -\pi/3 \) to \( 0 \).
02
Simplify the integrand
Recall that \( \sec(x) = \frac{1}{\cos(x)} \). Therefore, \( \sec^3(x) = \frac{1}{\cos^3(x)} \). This allows us to recognize that the integral can potentially benefit from substitution or trigonometric identities.
03
Perform substitution
Let \( u = \sec(x) + \tan(x) \), then \( du = (\sec(x) \tan(x) + \sec^2(x)) \, dx \), simplifying the expression for \( dx = \frac{du}{\sec(x) \tan(x) + \sec^2(x)} \). This substitution allows us to set up a substitution method for solving the integral.
04
Express the integral in terms of u
Substituting these into the integral, we get:\[\int 2 \sec^3 x \, dx = \int 2 \cdot u^2 \, du.\]The limits of integration in terms of \( u \) need to be found from \( x = -\pi/3 \to 0 \) to the corresponding \( u \)-values.
05
Determine the new limits of integration
For the substitution \( u = \sec(x) + \tan(x) \), evaluate \( u \) at the original bounds. At \( x = -\pi/3 \), \( \sec(-\pi/3) = 2 \) and \( \tan(-\pi/3) = -\sqrt{3} \), thus, \( u = 2 - \sqrt{3} \). At \( x = 0 \), \( \sec(0) = 1 \) and \( \tan(0) = 0 \), thus, \( u = 1 \). New bounds are from \( 2 - \sqrt{3} \) to \( 1 \).
06
Evaluate the integral
Integrate with respect to \( u \):\[\int 2 u^2 \, du = \left[ \frac{2}{3} u^3 \right]_{2-\sqrt{3}}^1.\]
07
Calculate the definite integral
Substitute the bounds into the evaluated integral:\[\frac{2}{3} \left[1^3 - (2-\sqrt{3})^3 \right].\]Find \((2 - \sqrt{3})^3 \), then subtract from \(1\).
08
Simplify and finalize answer
The evaluated value, after calculation, results in\[\frac{2}{3} \left[ 1 - (8 - 12\sqrt{3} + 3\sqrt{3}) \right] \].Thus, the evaluated integral value equals can be numerically determined from this expression.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
Definite integrals provide a means to calculate the net area under a curve between two specific points on the x-axis. This is possible because the definite integral represents the accumulation of quantities over an interval. For the problem at hand, we have a definite integral with the limits from \(-\pi/3\) to \(0\) which tells us that we are evaluating the accumulation of the function \(2 \sec^{3} x\) from \(-\pi/3\) to \(0\).
A definite integral such as the one we have here, \(\int_{-\pi/3}^{0} 2 \sec^{3} x \; dx\), is different from an indefinite integral because it computes the area between the function and the x-axis over the specified interval. The result is a specific number representing this area, considering any areas below the x-axis are negative.
A definite integral such as the one we have here, \(\int_{-\pi/3}^{0} 2 \sec^{3} x \; dx\), is different from an indefinite integral because it computes the area between the function and the x-axis over the specified interval. The result is a specific number representing this area, considering any areas below the x-axis are negative.
- Lower and Upper Limits: These are the points \(-\pi/3\) and \(0\) which serve as bounds for the region being calculated.
- Net Area Calculation: This involves calculating the entire area above the x-axis minus the area below the x-axis within the specified limits.
Trigonometric Substitution
Trigonometric substitution is a strategic method used in calculus to simplify the integration process, especially when dealing with integrals involving trigonometric functions. The core idea is to substitute trigonometric identities or expressions to transform a complex integrand into a simpler form that is easier to integrate.
In our exercise, we used the substitution \( u = \sec(x) + \tan(x) \). This substitution is clever because it simplifies the integrand from \(2 \sec^3 x\) into \(2 u^2\), an algebraic expression that is more straightforward to integrate.
In our exercise, we used the substitution \( u = \sec(x) + \tan(x) \). This substitution is clever because it simplifies the integrand from \(2 \sec^3 x\) into \(2 u^2\), an algebraic expression that is more straightforward to integrate.
- Choosing the Right Substitution: The key to successful trigonometric substitution is selecting a substitution that simplifies the expressions effectively. Here, choosing \(\sec(x) + \tan(x)\) takes advantage of trigonometric identities.
- Derivative Relationship: Calculating \(du\) in terms of \(dx\) is essential. This involves deriving the expression for \(u\), which includes derivatives like \(\sec(x) \tan(x) + \sec^2(x)\).
Integrand Simplification
Simplifying the integrand is a fundamental step in the integration process. It involves transforming the integrand function into a form that is easier to work with or integrate.
When we observe the original integrand \(2 \sec^{3} x\), recognizing trigonometric identities can greatly aid simplification. In this case, using the identity \(\sec(x) = 1/\cos(x)\) leads to rewriting \(\sec^3(x)\) as \(\frac{1}{\cos^3(x)}\).
When we observe the original integrand \(2 \sec^{3} x\), recognizing trigonometric identities can greatly aid simplification. In this case, using the identity \(\sec(x) = 1/\cos(x)\) leads to rewriting \(\sec^3(x)\) as \(\frac{1}{\cos^3(x)}\).
- Rewriting Using Identities: Transforming \(\sec^3(x)\) into a simpler algebraic expression was an important step. It could help reveal a standard integration form or allow for substitution.
- Simplification for Ease: By rewriting the function, we aim to either reduce its complexity or convert it into a standard form appearing in integral tables.