/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Evaluate the integrals in terms ... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the integrals in terms of a. inverse hyperbolic functions. b. natural logarithms. $$\int_{1}^{2} \frac{d x}{x \sqrt{4+x^{2}}}$$

Short Answer

Expert verified
The integral results in terms of inverse hyperbolic functions or natural logarithms by substitutions using \( x = 2 \sinh(t) \) or \( x = 2 \tan(\theta) \), respectively.

Step by step solution

01

Identify the Integral Form

The given integral is \( \int_{1}^{2} \frac{d x}{x \sqrt{4+x^{2}}} \). We need to identify which standard integral form it resembles. This integral can be tackled using substitutions that lead to expressions involving inverse hyperbolic functions or natural logarithms.
02

Make a Substitution for Inverse Hyperbolic Functions

Use the substitution \( x = 2 \sinh(t) \), which implies that \( dx = 2 \cosh(t) \, dt \). The limits change to \( x = 1 \Rightarrow t = \sinh^{-1}(1/2) \) and \( x = 2 \Rightarrow t = \sinh^{-1}(1) \). Substitute into the integral: \[ \int \frac{2 \cosh(t) \, dt}{(2 \sinh(t)) \cdot \sqrt{4 + (2 \sinh(t))^2}} = \int \frac{1}{2 \sinh(t)} \, dt. \]
03

Evaluate the Integral with Inverse Hyperbolic Functions

The integral \( \int \frac{1}{2 \sinh(t)} \, dt \) simplifies using the identity \( \sqrt{4 + 4 \sinh^2(t)} = 2 \cosh(t) \), resulting in \[ \int \frac{dt}{\sinh(t)} = \ln |\tanh(t/2)| + C. \] Evaluate between the limits to find the definite integral result: \[ \ln \left| \frac{\tanh(\sinh^{-1}(1)/2)}{\tanh(\sinh^{-1}(1/2)/2)} \right|. \]
04

Use a Different Substitution for Natural Logarithms

Now let \( x = 2 \tan(\theta) \), so \( dx = 2 \sec^2(\theta) \, d\theta \) and \( \sqrt{4+x^2} = 2\sec(\theta) \). The limits become \( x=1 \Rightarrow \theta = \tan^{-1}(1/2) \) and \( x=2 \Rightarrow \theta = \pi/4 \). The integral becomes:\[ \int \frac{2 \sec^2(\theta) \, d\theta}{2 \tan(\theta) \cdot 2 \sec(\theta)} \equiv \int \frac{\sec(\theta) \, d\theta}{\tan(\theta)}. \]
05

Evaluate the Integral with Natural Logarithms

The integral \( \int \frac{\sec(\theta)}{\tan(\theta)} \, d\theta \) simplifies to \[ \int \frac{d\theta}{\sin(\theta) \cos(\theta)} = \int \frac{d\theta}{\frac{1}{2} \sin(2\theta)} = \ln |\sin(2\theta)| + C. \]Evaluate the definite integral and replace with original variables to express in terms of natural logs. \[ \ln \left| \frac{\sin(\pi/2)}{\sin(2\tan^{-1}(1/2))} \right|. \]
06

Simplify Final Expressions

Calculate the values: - \( \tan^{-1}(1/2) \approx 0.4636 \), use trigonometric identities and approximations if needed.- For inverse hyperbolic function form, simplify the evaluation using properties of \( \tanh \). Each expression can be replaced with numerical values or kept in symbolic form if needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Hyperbolic Functions
Inverse hyperbolic functions are analogs of trigonometric functions but for hyperbolas. They are primarily used to find angles when given a hyperbolic sine, cosine, or tangent value. These functions include the inverse hyperbolic sine \(\sinh^{-1}(x)\), cosine \(\cosh^{-1}(x)\), and tangent \(\tanh^{-1}(x)\), among others.

When integrating, these functions often emerge from situations involving quadratic expressions under square roots, similar to trigonometric results for circular functions. An example is the substitution \(x = a \sinh(t)\) where \(a\) is a constant, which can transform integrals involving \(\sqrt{a^2 + x^2}\) into simpler forms. This transformation leverages identities like \(\cosh^2(t) - \sinh^2(t) = 1\), allowing the integration to become manageable.

In the exercise, using the substitution \(x = 2\sinh(t)\) relates directly to these functions. It changes the form of the integral making it possible to express the final result in terms of inverse hyperbolic function expressions, such as \(\ln|\tanh(t/2)|\). A deep understanding of these functions not only aids in calculus problems but also in solving real-world phenomena modeled by hyperbolic curves.
Natural Logarithms
Natural logarithms are the logarithms to the base \(e\), where \(e\) is an irrational constant approximately equal to 2.71828. These logarithms are essential in calculus due to their innate connection to exponential growth and decay, making them pivotal in many mathematical applications.

In integration, natural logarithms often arise after performing certain algebraic manipulations or substitutions. For instance, expressions resulting from separating rational functions or through trigonometric substitutions can often simplify to integrals of the form \(\int \frac{1}{x} \, dx = \ln|x| + C\). These are crucial when evaluating definite integrals involving trigonometric identities.

In the solution step utilizing the substitution \(x = 2\tan(\theta)\), the integral transforms such that the final antiderivative involves natural logarithms. The outcome is expressed as \(\ln|\sin(2\theta)|\), leveraging trigonometric identities and logarithmic properties. Understanding these concepts facilitates efficient handling of complex integrals in terms of natural logarithms.
Trigonometric Substitutions
Trigonometric substitutions are techniques used in calculus to simplify the integration of functions. They replace expressions by trigonometric identities, with \(x= a \sin(\theta)\), \(x= a \cos(\theta)\), or \(x= a \tan(\theta)\) being the most common forms.

These substitutions are helpful for expressions containing radicals, especially when dealing with sums or differences of squares. The primary goal is to transform the integral into a trigonometric form that is easier to solve, often reducing the complexity of square roots.
  • Use \(x = a\sin(\theta)\) where \(\sqrt{a^2 - x^2}\) occurs, assuming \(a^2 > x^2\).
  • Use \(x = a\tan(\theta)\) when you have \(\sqrt{a^2 + x^2}\).
  • Use \(x = a\sec(\theta)\) for \(\sqrt{x^2 - a^2}\).
In the given exercise, the substitution \(x = 2\tan(\theta)\) dealt with the square root involving \(4+x^2\), converting the integral into one involving \(\tan(\theta)\) and \(\sec(\theta)\). Recognizing when and how to use these substitutions helps solve integrals leading to clearer, solvable results with trigonometric identities.

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Most popular questions from this chapter

The answers to most of the following exercises are in terms of logarithms and exponentials. A calculator can be helpful, enabling you to express the answers in decimal form. A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. At the end of 3 hours there are 10,000 bacteria. At the end of 5 hours there are \(40,000 .\) How many bacteria were present initially?

The answers to most of the following exercises are in terms of logarithms and exponentials. A calculator can be helpful, enabling you to express the answers in decimal form. To encourage buyers to place 100 -unit orders, your firm's sales department applies a continuous discount that makes the unit price a function \(p(x)\) of the number of units \(x\) ordered. The discount decreases the price at the rate of \(\$ 0.01\) per unit ordered. The price per unit for a 100 -unit order is \(p(100)=\$ 20.09\). a. Find \(p(x)\) by solving the following initial value problem. $$\begin{aligned} &\text { Differential equation: } \quad \frac{d p}{d x}=-\frac{1}{100} p\\\ &\text { Initial condition: } \quad p(100)=20.09 \end{aligned}$$ b. Find the unit price \(p(10)\) for a 10 -unit order and the unit price \(p(90)\) for a 90 -unit order. c. The sales department has asked you to find out if it is discounting so much that the firm's revenue, \(r(x)=x \cdot p(x),\) will actually be less for a 100 -unit order than, say, for a 90 -unit order. Reassure them by showing that \(r\) has its maximum value at \(x=100\). d. Graph the revenue function \(r(x)=x p(x)\) for \(0 \leq x \leq 200\).

Evaluate the integrals. $$\int_{1 / 10}^{10} \frac{\log _{10}(10 x)}{x} d x$$

Evaluate the integrals. $$\int_{-\ln 2}^{0} \cosh ^{2}\left(\frac{x}{2}\right) d x$$

The answers to most of the following exercises are in terms of logarithms and exponentials. A calculator can be helpful, enabling you to express the answers in decimal form. Earth's atmospheric pressure \(p\) is often modeled by assuming that the rate \(d p / d h\) at which \(p\) changes with the altitude \(h\) above sea level is proportional to \(p .\) Suppose that the pressure at sea level is 1013 millibars (about 14.7 pounds per square inch) and that the pressure at an altitude of \(20 \mathrm{km}\) is 90 millibars. a. Solve the initial value problem Differential equation: \(\quad d p / d h=k p \quad\) (k a constant) Initial condition: \(\quad p=p_{0} \quad\) when \(\quad h=0\) to express \(p\) in terms of \(h .\) Determine the values of \(p_{0}\) and \(k\) from the given altitude-pressure data. b. What is the atmospheric pressure at \(h=50 \mathrm{km} ?\) c. At what altitude does the pressure equal 900 millibars?

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