Chapter 4: Problem 5
Find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation. a. \(\frac{1}{x^{2}}\) b. \(\frac{5}{x^{2}}\) c. \(2-\frac{5}{x^{2}}\)
Short Answer
Expert verified
Antiderivatives are a. \(-\frac{1}{x} + C\); b. \(-\frac{5}{x} + C\); c. \(2x + \frac{5}{x} + C\).
Step by step solution
01
Find Antiderivative for \( \frac{1}{x^2} \)
The function can be rewritten as \( x^{-2} \). The antiderivative of a power function \( x^n \) is \( \frac{x^{n+1}}{n+1} + C \), where \( C \) is the constant of integration. Thus, the antiderivative of \( x^{-2} \) is \( \frac{x^{-1}}{-1} + C = -\frac{1}{x} + C \).
02
Check the Antiderivative by Differentiation for \( \frac{1}{x^2} \)
Differentiate \( -\frac{1}{x} + C \). The derivative is \( \frac{d}{dx}(-\frac{1}{x}) = \frac{d}{dx}(x^{-1}) = -x^{-2} = -\frac{1}{x^2} \). This matches the original function, so the antiderivative is correct.
03
Find Antiderivative for \( \frac{5}{x^2} \)
The function \( \frac{5}{x^2} \) can be rewritten as \( 5x^{-2} \). The antiderivative of \( 5x^{-2} \) is \( 5(-\frac{1}{x}) + C = -\frac{5}{x} + C \).
04
Check the Antiderivative by Differentiation for \( \frac{5}{x^2} \)
Differentiate \( -\frac{5}{x} + C \). The derivative is \( 5(x^{-2}) = \frac{5}{x^2} \). This matches the original function, hence the antiderivative is correct.
05
Find Antiderivative for \( 2 - \frac{5}{x^2} \)
Separate the terms: \( 2x^0 \) and \( -5x^{-2} \). The antiderivative of \( 2x^0 \) is \( 2x \) and for \( -5x^{-2} \) it is \( 5\frac{1}{x} \). Combine them: \( 2x + \frac{5}{x} + C \).
06
Check the Antiderivative by Differentiation for \( 2 - \frac{5}{x^2} \)
Differentiate \( 2x + \frac{5}{x} + C \). The derivative is \( 2 - \frac{5x^{-2}} = 2 - \frac{5}{x^2} \), which matches the original function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation
Differentiation is a fundamental concept in calculus that involves finding the rate at which a function changes at any point. The process is essentially about taking a derivative, which is represented as \( \frac{d}{dx} \) for a function of \( x \). Think of it as measuring how steep or flat a curve is at any given spot.
When checking the correctness of an antiderivative, differentiation allows us to reverse-engineer the process. By differentiating the antiderivative, we should arrive back at the original function.
When checking the correctness of an antiderivative, differentiation allows us to reverse-engineer the process. By differentiating the antiderivative, we should arrive back at the original function.
- For instance, if we have the antiderivative \( -\frac{1}{x} + C \), differentiating gives us \( \frac{1}{x^2} \).
- The derivative brought us back to the original function we started with, confirming our antiderivative calculation was spot-on.
Power Function
Power functions have the form \( x^n \), where \( n \) is any real number, and they play a crucial role in differentiation and integration. In the context of finding antiderivatives, power functions follow a specific rule:
Consider the function \( \frac{5}{x^2} \), which can be expressed as \( 5x^{-2} \). To find its antiderivative:
- The antiderivative of a power function \( x^n \) is given by \( \frac{x^{n+1}}{n+1} + C \), provided \( n eq -1 \).
Consider the function \( \frac{5}{x^2} \), which can be expressed as \( 5x^{-2} \). To find its antiderivative:
- Apply the power rule: increment the power from \( -2 \) to \( -1 \), and divide by the new exponent.
- The antiderivative becomes \( -\frac{5}{x} + C \).
Constant of Integration
When calculating an antiderivative, you'll always include a special element: the constant of integration, denoted as \( C \). Why is this important? Because differentiating a function removes any constant added, and integration, being the inverse, doesn't automatically replace it.
Essentially, there are infinitely many antiderivatives for any given function differing only by a constant. This is due to the nature of derivatives:
Essentially, there are infinitely many antiderivatives for any given function differing only by a constant. This is due to the nature of derivatives:
- For instance, differentiating \( -\frac{1}{x} + C \) gives \( \frac{1}{x^2} \), regardless of the value of \( C \).
- This means that while the slope of the curve remains unchanged, its position along the \( y \)-axis can vary.