/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 87 Find the derivative of \(y\) wit... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the derivative of \(y\) with respect to the given independent variable. $$y=\log _{2}\left(8 t^{\ln 2}\right)$$

Short Answer

Expert verified
The derivative is \(\frac{1}{t}\).

Step by step solution

01

Simplify the Expression

Rewrite the expression inside the logarithm base 2 using properties of logarithms. Recognize that \(8 = 2^3\), so:\[y = \log_2(2^3 t^{\ln 2}) = \log_2(2^3) + \log_2(t^{\ln 2})\].This simplifies to:\[y = 3 + \ln 2 \cdot \log_2 t\].
02

Apply the Derivative

The derivative of a constant is zero and the derivative of \(\log_2 t\) is \(\frac{1}{t \ln 2}\) by the logarithmic differentiation formula. Use these to find the derivative of \(y\):\[\frac{dy}{dt} = 0 + \ln 2 \cdot \frac{1}{t \ln 2}\].
03

Simplify the Derivative

Simplify the expression obtained in the previous step:\[\frac{dy}{dt} = \frac{1}{t}\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
Understanding derivatives is crucial in calculus. A derivative represents how a function changes as its input changes. In simple terms, it finds the rate of change or slope of a function at any given point. For any function, the derivative is like its sensitive measure of how one variable (often time) influences another.
  • One of the basic rules to remember is that the derivative of a constant is always zero. This is because constants do not change, hence their rate of change is zero.
  • For functions of the form \(x^n\), the derivative is \(nx^{n-1}\). This power rule is quite handy in finding the derivative of polynomial functions.
  • The derivative of the natural logarithm \(\ln(x)\) is \(1/x\), and similarly for other logarithmic functions with a different base, logarithmic differentiation techniques are used.
Understanding derivatives helps in modeling real-world phenomena, such as speed, growth, decay, and more. They offer a mathematical way to project how a change in one quantity results in a change in another.
Properties of Logarithms
The properties of logarithms are essential in simplifying expressions before solving them, especially when dealing with complex equations. Logarithms have several key properties that make calculations more manageable:
  • The product property: \(\log_b(MN) = \log_b(M) + \log_b(N)\). This helps break down products inside a logarithm into sums.
  • The quotient property: \(\log_b\left(\frac{M}{N}\right) = \log_b(M) - \log_b(N)\), which separates divisions inside a logarithm into differences.
  • The power property: \(\log_b(M^p) = p\cdot\log_b(M)\). This property is particularly useful when handles with exponents inside a logarithmic function.
In the given exercise, these properties are used to simplify the expression \( \log_2(8 t^{\ln 2}) \) into more manageable terms. Recognizing that \(8 = 2^3\) allows breakdown into parts using these rules. This simplification turns complex equations into more straightforward ones for the differentiation process.
Chain Rule
The chain rule is a powerful tool in calculus when dealing with composite functions. It helps find the derivative by addressing each part of the composite function separately. Essentially, the chain rule states:"If a function \(y=f(g(x))\) is the composition of two functions \(f\) and \(g\), then its derivative is \(f'(g(x)) \cdot g'(x)\)."This means you take the derivative of the outer function evaluated at the inner function, then multiply by the derivative of the inner function. It allows solving derivatives of nested functions more systematically.
  • Identify the inner function \(g(x)\) and outer function \(f(g)\).
  • Find the derivatives \(f'(g(x))\) and \(g'(x)\).
  • Multiply these derivatives together to get the final result.
While the chain rule was not explicitly needed in simplifying the original exercise, understanding it provides a broader perspective in solving complex derivatives—particularly when more than one function is at play. It's an invaluable asset when faced with compounded expressions.

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Most popular questions from this chapter

The effect of flight maneuvers on the heart The amount of work done by the heart's main pumping chamber, the left ventricle, is given by the equation $$ W=P V+\frac{V \delta v^{2}}{2 g} $$ where \(W\) is the work per unit time, \(P\) is the average blood pressure, \(V\) is the volume of blood pumped out during the unit of time, \(\delta\) ("delta") is the weight density of the blood, \(v\) is the average velocity of the exiting blood, and \(g\) is the acceleration of gravity. When \(P, V, \delta,\) and \(v\) remain constant, \(W\) becomes a function of \(g\), and the equation takes the simplified form $$ W=a+\frac{b}{g}(a, b \text { constant }) $$ As a member of NASA's medical team, you want to know how sensitive \(W\) is to apparent changes in \(g\) caused by flight maneuvers, and this depends on the initial value of \(g\). As part of your investigation, you decide to compare the effect on \(W\) of a given change \(d g\) on the moon, where \(g=5.2 \mathrm{ft} / \mathrm{sec}^{2}\), with the effect the same change \(d_{8}\) would have on Earth, where \(g=32 \mathrm{ft} / \mathrm{sec}^{2}\). Use the simplified equation above to find the ratio of \(d W_{\text {moon }}\) to \(d W_{\text {Barth }}\)

Find the derivative of \(y\) with respect to the given independent variable. $$y=\log _{2}\left(\frac{x^{2} e^{2}}{2 \sqrt{x+1}}\right)$$

Use logarithmic differentiation or the method in Example 7 to find the derivative of \(y\) with respect to the given independent variable. $$y=x^{\ln x}$$

Slopes on sine curves a. Find equations for the tangent lines to the curves \(y=\sin 2 x\) and \(y=-\sin (x / 2)\) at the origin. Is there anything special about how the tangent lines are related? Give reasons for your answer. b. Can anything be said about the tangent lines to the curves \(y=\sin m x\) and \(y=-\sin (x / m)\) at the origin (m a constant \(\neq 0\) )? Give reasons for your answer. c. For a given \(m,\) what are the largest values the slopes of the curves \(y=\sin m x\) and \(y=-\sin (x / m)\) can ever have? Give reasons for your answer. d. The function \(y=\sin x\) completes one period on the interval \([0,2 \pi],\) the function \(y=\sin 2 x\) completes two periods, the function \(y=\sin (x / 2)\) completes half a period, and so on. Is there any relation between the number of periods \(y=\sin m x\) completes on \([0,2 \pi]\) and the slope of the curve \(y=\sin m x\) at the origin? Give reasons for your answer.

Graph \(f(x)=\tan ^{-1} x\) together with its first two derivatives. Comment on the behavior of \(f\) and the shape of its graph in relation to the signs and values of \(f^{\prime}\) and \(f^{\prime \prime}\).

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