Chapter 3: Problem 7
Find a linearization at a suitably chosen integer near \(a\) at which the given function and its derivative are easy to evaluate. $$f(x)=x^{2}+2 x, \quad a=0.1$$
Short Answer
Expert verified
The linearization at \( a = 0.1 \) is \( L(x) = 2x \).
Step by step solution
01
Understand Linearization
The linearization of a function provides a linear approximation of the function at a given point. It is written as the equation of the tangent line at that point. The formula for a linearization of a function \( f(x) \) at \( a \) is given by: \[ L(x) = f(a) + f'(a)(x - a) \] where \( f'(a) \) is the derivative of \( f(x) \) at \( a \).
02
Calculate the Derivative of the Function
First, we need to find the derivative of the function to use it in the linearization formula. The given function is \( f(x) = x^2 + 2x \). Use standard differentiation rules to find the derivative:\[ f'(x) = \frac{d}{dx}(x^2) + \frac{d}{dx}(2x) = 2x + 2 \].
03
Choose a Suitable Integer Close to \( a \)
Since \( a = 0.1 \) is close to zero, an integer value near zero is more suitable for easy calculations. Therefore, choose \( a = 0 \) because it simplifies the calculation of both the function \( f \) and its derivative.
04
Evaluate \( f(a) \) and \( f'(a) \) at the Chosen Integer
Substitute \( a = 0 \) into the function and its derivative:- \( f(0) = 0^2 + 2 \times 0 = 0 \).- \( f'(0) = 2 \times 0 + 2 = 2 \).
05
Substitute into the Linearization Formula
Use the calculated values in the linearization formula: \[ L(x) = f(0) + f'(0)(x - 0) = 0 + 2(x - 0) = 2x \].So, the linearization of the function \( f(x) \) near \( x = 0 \) is \( L(x) = 2x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
In calculus, the derivative is a fundamental concept that measures how a function changes as its input changes. For the given function, the derivative is found to determine the slope of the function at any point.
To find the derivative of a function like \( f(x) = x^2 + 2x \), we apply differentiation rules. Differentiation is the process of finding a derivative, using rules such as the power rule and sum rule.
The power rule states that for any function of the form \( ax^n \), the derivative is \( anx^{n-1} \). Applying this to our function, we differentiate each term:
To find the derivative of a function like \( f(x) = x^2 + 2x \), we apply differentiation rules. Differentiation is the process of finding a derivative, using rules such as the power rule and sum rule.
The power rule states that for any function of the form \( ax^n \), the derivative is \( anx^{n-1} \). Applying this to our function, we differentiate each term:
- \( \frac{d}{dx}(x^2) = 2x \)
- \( \frac{d}{dx}(2x) = 2 \)
Tangent Line
The tangent line to a curve at a given point is the straight line that touches the curve at that point and has the same slope as the curve.
When we consider the tangent line for a function, it gives us the best linear approximation to the curve at some specific point. With the function \( f(x) = x^2 + 2x \), the tangent line at \( a = 0 \) can be derived using the derivative.
A tangent line is given by the equation: \[ y = f(a) + f'(a)(x - a) \] where \( f(a) \) is the function value at \( a \) and \( f'(a) \) is the derivative at \( a \).
For our chosen point \( a = 0 \):
When we consider the tangent line for a function, it gives us the best linear approximation to the curve at some specific point. With the function \( f(x) = x^2 + 2x \), the tangent line at \( a = 0 \) can be derived using the derivative.
A tangent line is given by the equation: \[ y = f(a) + f'(a)(x - a) \] where \( f(a) \) is the function value at \( a \) and \( f'(a) \) is the derivative at \( a \).
For our chosen point \( a = 0 \):
- \( f(0) = 0 \)
- \( f'(0) = 2 \)
Differentiation
Differentiation is a critical tool in calculus used to find the derivative of a function. It involves applying specific rules to functions to ascertain their derivatives, which then inform us of the functions' behavior.
For the task of finding the linearization of the function \( f(x) = x^2 + 2x \):
For the task of finding the linearization of the function \( f(x) = x^2 + 2x \):
- We start by differentiating each term of the function separately using the sum and power rules.
- Side by side, we calculate: \( \frac{d}{dx}(x^2) = 2x \) and \( \frac{d}{dx}(2x) = 2 \).
- Combining these, we establish that \( f'(x) = 2x + 2 \), providing the expression for the slope at any point \( x \).
Approximation
In mathematical analysis, approximation refers to finding values close enough to exact numbers, often using simpler expressions or methods. Linearization serves as an approximation technique, offering an easy-to-handle line that mimics the behavior of a function near a given point.
For the function \( f(x) = x^2 + 2x \), the linearization at \( a = 0 \) gives us \( L(x) = 2x \). This is because at \( a = 0 \), the function itself is not complex (\( f(0) = 0 \)), and the slope derived from the derivative (\( f'(0) = 2 \)) helps in forming a straight line.
Approximations using linearization are especially helpful when:
For the function \( f(x) = x^2 + 2x \), the linearization at \( a = 0 \) gives us \( L(x) = 2x \). This is because at \( a = 0 \), the function itself is not complex (\( f(0) = 0 \)), and the slope derived from the derivative (\( f'(0) = 2 \)) helps in forming a straight line.
Approximations using linearization are especially helpful when:
- The actual function is difficult to compute for each desired x-value.
- A quick estimation is needed.