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Give the position \(s=f(t)\) of a body moving on a coordinate line ( \(s\) in meters, \(t\) in seconds). Find the body's velocity, speed, acceleration, and jerk at time \(t=\pi / 4\) sec. \(s=\sin t+\cos t\)

Short Answer

Expert verified
Velocity: 0, Speed: 0, Acceleration: \(-\sqrt{2}\), Jerk: 0 at \(t=\frac{\pi}{4}\).

Step by step solution

01

Differentiate to Find Velocity

The velocity of the body is found by taking the first derivative of the position function with respect to time. Given the position function \(s = \sin t + \cos t\), the velocity, \(v(t)\), is:\[ v(t) = \frac{ds}{dt} = \cos t - \sin t \]
02

Calculate Velocity at Given Time

Substitute \(t = \frac{\pi}{4}\) into the velocity function to find the velocity at that time:\[ v\left(\frac{\pi}{4}\right) = \cos\left(\frac{\pi}{4}\right) - \sin\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2} = 0 \]
03

Compute Speed

Speed is the absolute value of velocity. Since the velocity at \(t = \frac{\pi}{4}\) is 0, the speed is:\[ |v(t)| = 0 \]
04

Differentiate to Find Acceleration

Acceleration is the derivative of the velocity function. Differentiating \(v(t) = \cos t - \sin t\), we get the acceleration, \(a(t)\):\[ a(t) = \frac{dv}{dt} = -\sin t - \cos t \]
05

Calculate Acceleration at Given Time

Substitute \(t = \frac{\pi}{4}\) into the acceleration function to find acceleration at that time:\[ a\left(\frac{\pi}{4}\right) = -\sin\left(\frac{\pi}{4}\right) - \cos\left(\frac{\pi}{4}\right) = -\frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2} = -\sqrt{2} \]
06

Differentiate to Find Jerk

Jerk is the derivative of the acceleration function. Differentiating \(a(t) = -\sin t - \cos t\), we find the jerk, \(j(t)\):\[ j(t) = \frac{da}{dt} = -\cos t + \sin t \]
07

Calculate Jerk at Given Time

Substitute \(t = \frac{\pi}{4}\) into the jerk function to find jerk at that time:\[ j\left(\frac{\pi}{4}\right) = -\cos\left(\frac{\pi}{4}\right) + \sin\left(\frac{\pi}{4}\right) = -\frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2} = 0 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a process in calculus that finds the rate at which a function is changing at any point. It's a fundamental tool used to determine important properties like velocity and acceleration. In terms of a moving body's position function, such as \(s = \sin t + \cos t\), differentiating this function with respect to time \(t\) gives us the velocity. This first derivative tells us how quickly the position changes over time.

In our example, to find velocity, we compute the derivative of \(s\) with respect to \(t\). Using standard differentiation rules for trigonometric functions, the derivative becomes \(v(t) = \cos t - \sin t\). This function describes how the position \(s\) changes as time progresses, providing insight into the motion's behavior at any given moment.
Velocity
Velocity is the rate of change of position with respect to time. It has both a magnitude (speed) and direction. In this context, the velocity of a body is derived by taking the first derivative of its position function. For the function \(s = \sin t + \cos t\), the velocity \(v(t)\) is obtained as \(\cos t - \sin t\). This means at every point \(t\), the body's velocity is the difference between the cosine and sine of \(t\).
  • It's important to note that velocity differs from speed; velocity includes direction while speed does not.
  • By calculating \(v\left(\frac{\pi}{4}\right) = 0\), we discovered that at time \(t=\frac{\pi}{4}\), the velocity is zero, indicating no change in position at that precise moment.
Acceleration
Acceleration is the rate of change of velocity with respect to time. It tells us how quickly velocity is changing, providing insight into the dynamics of motion. To find acceleration from velocity, we differentiate the velocity function \(v(t) = \cos t - \sin t\).

This differentiation gives the acceleration function \(a(t) = -\sin t - \cos t\). Calculating the acceleration at a specific time, such as \(t=\frac{\pi}{4}\), we find \(a\left(\frac{\pi}{4}\right) = -\sqrt{2}\). This value indicates the rate at which the body's velocity is decreasing at that instant, as it is a negative value, implying a deceleration.
Jerk
Jerk is the rate of change of acceleration with respect to time. Think of it as how the acceleration itself is changing. It's a significant factor, especially in understanding smoother transitions in motion.
  • Jerk is determined by differentiating the acceleration function. For the example in question, \(a(t) = -\sin t - \cos t\), the derivative (or jerk function) is \(j(t) = -\cos t + \sin t\).
  • When we compute \(j\left(\frac{\pi}{4}\right) = 0\), it reveals that the acceleration is not changing at this specific point in time (\(t = \frac{\pi}{4}\)). This might mean the transition in the motion is quite smooth at this instant.

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