Chapter 3: Problem 33
Find the derivatives of the functions in Exercises \(17-40 .\) $$y=x^{9 / 4}+e^{-2 x}$$
Short Answer
Expert verified
The derivative is \( y' = \frac{9}{4} x^{\frac{5}{4}} - 2e^{-2x} \).
Step by step solution
01
Identify the components of the function
The given function is composed of two terms: 1. The first term is a power function: \( x^{9/4} \).2. The second term is an exponential function: \( e^{-2x} \).
02
Differentiate the power function
To differentiate the power function \( x^{9/4} \), use the power rule: \( \frac{d}{dx}[x^n] = nx^{n-1} \). Applying this, the derivative of \( x^{9/4} \) is:\[ \frac{9}{4} x^{\frac{9}{4} - 1} = \frac{9}{4} x^{\frac{5}{4}} \]
03
Differentiate the exponential function
To differentiate the exponential function \( e^{-2x} \), use the chain rule, where \( \frac{d}{dx}[e^{u}] = e^{u} \cdot u' \). Let \( u = -2x \), so \( u' = -2 \). The derivative is:\[ \frac{d}{dx}[e^{-2x}] = e^{-2x} \cdot (-2) = -2e^{-2x} \]
04
Combine the derivatives
Combine the derivatives of the individual terms to find the derivative of the complete function.The derivative of \( y = x^{9/4} + e^{-2x} \) is:\[ y' = \frac{9}{4} x^{\frac{5}{4}} - 2e^{-2x} \]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
The power rule is a fundamental tool in calculus differentiation used to find derivatives of functions of the form \[x^n\] where \(n\) can be any real number. To apply the power rule effectively, follow these simple steps:
- Identify the exponent \(n\).
- Bring down the exponent \(n\) just in front of the function.
- Subtract one from the exponent \(n\).
- Perform any additional simplifications if needed.
Chain Rule
The chain rule is a crucial technique in calculus used to differentiate compositions of functions. This is particularly useful when dealing with exponential functions where the exponent itself is a function of \(x\). The general form of the chain rule is:
\[\frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x)\]
To apply the chain rule accurately, follow these steps:
\[\frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x)\]
To apply the chain rule accurately, follow these steps:
- Identify the inner function, \(g(x)\).
- Determine the derivative of the outer function, \(f'(g(x))\), keeping \(g(x)\) as the variable.
- Find the derivative of the inner function, \(g'(x)\).
- Multiply the derivatives together.
Exponential Functions
Exponential functions are expressed in the form \(e^{u(x)}\), where \(e\) is the base of natural logarithms, approximated as 2.718. They are prevalent in calculus due to their unique property where the derivative of an exponential function with a linear exponent can be neatly derived using the chain rule.
Here’s how you deal with differentiating exponential functions:
Here’s how you deal with differentiating exponential functions:
- Identify the exponent \(u(x)\).
- Apply the exponential derivative \(e^{u(x)}\).
- Multiply by the derivative of the inside function \(u(x)\).