Chapter 3: Problem 12
Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there. $$f(x)=x-2 x^{2}, \quad(1,-1)$$
Short Answer
Expert verified
The slope is -3, and the equation of the tangent line is \( y = -3x + 2 \).
Step by step solution
01
Find the Derivative of the Function
To find the slope of the function at a given point, we first need to find the derivative of the function. The derivative of a function gives us the slope of the tangent line at any point. Let's differentiate the function: Given \( f(x) = x - 2x^2 \), the derivative \( f'(x) \) is found using standard differentiation rules. The derivative is:\[ f'(x) = \frac{d}{dx}(x) - \frac{d}{dx}(2x^2) = 1 - 4x. \]
02
Evaluate the Derivative at the Given Point
Now that we have the derivative, we can find the slope of the tangent line at the given point \((1, -1)\). Substitute \( x = 1 \) into \( f'(x) \):\[ f'(1) = 1 - 4(1) = 1 - 4 = -3. \]The slope of the tangent line at the point \((1, -1)\) is \(-3\).
03
Use the Point-Slope Form to Write the Equation
With the slope found in Step 2, we can write the equation of the tangent line using the point-slope form of a line:\[ y - y_1 = m(x - x_1), \]where \((x_1, y_1)\) is the point \((1, -1)\) and \(m\) is the slope \(-3\). Substituting in these values:\[ y - (-1) = -3(x - 1). \]Simplifying, we get:\[ y + 1 = -3x + 3. \]Further simplify to:\[ y = -3x + 2. \]
04
Verify the Tangent Matches at Point
It is good practice to verify that our tangent line passes through the point \((1, -1)\). Substitute \( x = 1 \) into our tangent line equation, \( y = -3x + 2 \):\[ y = -3(1) + 2 = -3 + 2 = -1. \]Thus, the line \( y = -3x + 2 \) correctly goes through the point \((1, -1)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent Line
When we talk about the tangent line to the graph of a function at a particular point, we are referring to a line that just "touches" the curve at that point. This line doesn't cut through the curve; instead, it represents the path the curve is taking at that precise location.
- Imagine drawing a straight line that barely touches a bendy path without cutting into it. That's your tangent line.
- The tangent line has the same slope as the function's graph at that point.
Slope of a Function
The slope of a function at a given point is a key concept, especially when dealing with calculus. Generally, the slope tells us how steep a line is. In a function's graph, it represents how much the function's value changes with a small change in input.
- Slope is calculated using derivatives. This is because the derivative at a point gives us the instantaneous rate of change of the function.
- If a function's slope is positive, the function is increasing at that point; if negative, it's decreasing.
Differentiation Rules
Differentiation is a set of rules and methods used to find the derivative of functions efficiently. When we find a derivative, we are essentially finding the slope of the tangent line to the function at a point.
- The basic rules include the power rule, constant rule, and sum rule among others.
- These rules help simplify complex functions into manageable parts we can easily differentiate.
- The derivative of \( x \) (first term) is \( 1 \) (constant rule).
- The derivative of \( 2x^2 \) (second term) involves the power rule, leading to \( 4x \).