/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Find \(d y / d x\). $$y=-10 x+... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(d y / d x\). $$y=-10 x+3 \cos x$$

Short Answer

Expert verified
\( \frac{dy}{dx} = -10 - 3 \sin x \).

Step by step solution

01

Identify the Function Components

The given function is \( y = -10x + 3 \cos x \), which has two distinct components: a linear term \(-10x\) and a trigonometric term \(3 \cos x\). We'll differentiate each component separately with respect to \(x\).
02

Differentiate the Linear Term

The derivative of a linear function \( -10x \) with respect to \( x \) is simply the coefficient of \( x \), which is \(-10\). Thus, \( \frac{d}{dx}(-10x) = -10 \).
03

Differentiate the Trigonometric Term

The derivative of \( \cos x \) is \( -\sin x \). Therefore, the derivative of \( 3 \cos x \) is \( 3 \times (-\sin x) = -3 \sin x \).
04

Apply the Sum Rule

Using the sum rule of differentiation, we combine the derivatives of the individual components. Thus, \( \frac{dy}{dx} = -10 + (-3 \sin x) \).
05

Simplify the Expression

Finally, we simplify the expression obtained in the previous step: \( \frac{dy}{dx} = -10 - 3 \sin x \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Function
A linear function is one of the most basic types of functions in mathematics. In its simplest form, a linear function is expressed as \( y = mx + b \), where \( m \) represents the slope and \( b \) is the y-intercept. In this setup, the slope \( m \) indicates how much y changes when x changes by 1 unit. For example, if the slope is -10 as in the given function component \( -10x \), it tells us that for each unit increase in \( x \), \( y \) decreases by 10 units. This characteristic makes linear functions very predictable and easy to work with.
In differentiation, finding the derivative of a linear term like \( mx \) with respect to \( x \) is straightforward. The derivative is simply the slope \( m \). This is because the rate of change of \( y \) with respect to \( x \) is constant in a linear function. So, for \( -10x \), the derivative is \( -10 \), conveying a constant downward slope.
Trigonometric Function
Trigonometric functions, such as sine and cosine, relate to angles and periodic phenomena. In this context, we're concerned with the function \( \cos x \), which depicts a wave oscillating between -1 and 1, based on the angle \( x \) measured in radians. These functions are fundamental in addressing problems related to cycles, oscillations, and waves.
Differentiation of trigonometric functions follows specific rules. For cosine, the derivative of \( \cos x \) becomes \( -\sin x \). This transformation reflects how the slope of the tangent to the cosine curve at any point is represented by the value of \( -\sin x \) at that point. In the given expression \( 3 \cos x \), applying this rule means the rate of change in \( y \), relative to \( x \), results in \( -3 \sin x \). This simply multiplies the transformation of cosine's derivative by the constant coefficient in front of it.
Sum Rule of Differentiation
When dealing with functions that are combinations of multiple simpler functions, the sum rule of differentiation is a powerful tool. It allows you to differentiate each term separately and then sum the derivatives. This is crucial when you have a function involving both linear and trigonometric components, like \( y = -10x + 3 \cos x \).
To apply the sum rule, differentiate each part with respect to \( x \) and add them up:
  • The linear term: \( -10x \) gives \( -10 \)
  • The trigonometric term: \( 3 \cos x \) gives \( -3 \sin x \)
By summing these derivatives, you form the complete derivative of the function, which becomes \( \frac{dy}{dx} = -10 - 3 \sin x \). This rule streamlines the process, allowing differentiation of more complex functions by breaking them into manageable parts before recombining the results.

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