Chapter 2: Problem 48
Prove the limit statements $$\lim _{x \rightarrow 1} f(x)=2 \quad \text { if } \quad f(x)=\left\\{\begin{array}{ll} 4-2 x, & x<1 \\ 6 x-4, & x \geq 1 \end{array}\right.$$
Short Answer
Expert verified
The limit is 2 as \( x \to 1 \).
Step by step solution
01
Identify the Function Value Approaching from the Left
To prove \( \lim_{x \to 1} f(x) = 2 \), start by evaluating the value of \( f(x) \) as \( x \) approaches 1 from the left. Since \( x < 1 \) in this case, use the expression \( f(x) = 4 - 2x \). Substitute \( x = 1 \) into this expression: \( 4 - 2 \times 1 = 2 \). So, \( \lim_{x \to 1^-} f(x) = 2 \).
02
Identify the Function Value Approaching from the Right
Now, evaluate the value of \( f(x) \) as \( x \) approaches 1 from the right. Since \( x \geq 1 \), use the expression \( f(x) = 6x - 4 \). Substitute \( x = 1 \) into this expression: \( 6 \times 1 - 4 = 2 \). Thus, \( \lim_{x \to 1^+} f(x) = 2 \).
03
Compare Limits from Both Directions
Both one-sided limits, \( \lim_{x \to 1^-} f(x) \) and \( \lim_{x \to 1^+} f(x) \), are equal to 2. Since both approaches yield the same value, the overall limit exists.
04
Conclude the Limit Statement
Since the value of the function \( f(x) \) approaches 2 as \( x \) approaches 1 from both the left and the right, we can conclude that \( \lim_{x \to 1} f(x) = 2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Piecewise Functions
Piecewise functions are a special type of mathematical expression that involve different expressions for different intervals of the independent variable, typically defined by different conditions. Imagining a piecewise function is like considering different paths depending on the direction you're walking. In practical terms, it equips us with the ability to express complex, real-world phenomena that cannot be described with a single equation.
For instance, consider the piecewise function from our example: \[f(x) = \left\{ \begin{array}{ll} 4-2x, & x<1 \ 6x-4, & x \geq 1 \end{array} \right. \]Here:
For instance, consider the piecewise function from our example: \[f(x) = \left\{ \begin{array}{ll} 4-2x, & x<1 \ 6x-4, & x \geq 1 \end{array} \right. \]Here:
- When \(x\) is less than 1, the function is defined by \(4 - 2x\).
- When \(x\) is greater than or equal to 1, the function uses \(6x - 4\).
One-Sided Limits
One-sided limits are fundamental when dealing with piecewise functions, especially to determine the behavior of a function at points of transition between different pieces. Essentially, when we talk about one-sided limits, we're examining what a function approaches as its variable gets arbitrarily close to a certain point from either the left or the right.
For example, in our function:
For example, in our function:
- The left-hand limit, \( \lim_{x \to 1^-} f(x) = 2\), is found using \(4-2x\), as \(x\) approaches 1 from values less than 1.
- The right-hand limit, \( \lim_{x \to 1^+} f(x) = 2\), utilizes \(6x-4\), when approaching 1 from values greater than or equal to 1.
Limit Definition
The concept of a limit in mathematics is essential for understanding how functions behave close to a point, even if they are not defined at that point. The limit of a function as \(x\) approaches a particular value is essentially the value that \(f(x)\) gets closer to as \(x\) nears the specific value.
This exercise sought to establish \( \lim_{x \to 1} f(x) = 2 \). Through the step-by-step evaluation of one-sided limits, you confirm that the limit from both sides points to the same number.
Here are a few key points about limits:
This exercise sought to establish \( \lim_{x \to 1} f(x) = 2 \). Through the step-by-step evaluation of one-sided limits, you confirm that the limit from both sides points to the same number.
Here are a few key points about limits:
- If the left-hand limit \( \lim_{x \to a^-} f(x) \) equals the right-hand limit \( \lim_{x \to a^+} f(x) \), then \( \lim_{x \to a} f(x) \) exists and equals this common value.
- If these one-sided limits differ, then the limit at that point is undefined.