Chapter 17: Problem 54
In Exercises verify that the given function is a particular solution to the specified nonhomogeneous equation. Find the general solution, and evaluate its arbitrary constants to find the unique solution satisfying the equation and the given initial conditions. $$y^{\prime \prime}+y=x, \quad y_{\mathrm{p}}=2 \sin x+x, \quad y(0)=0, y^{\prime}(0)=0$$
Short Answer
Step by step solution
Verify the Particular Solution
Solve the Homogeneous Equation
Write the General Solution
Apply Initial Conditions
Write the Specific Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nonhomogeneous Differential Equation
\[ y'' + y = x \]
Here, the "+ x" is what makes this equation nonhomogeneous. This is in contrast to a homogeneous differential equation, which would have a zero on the right side, like \( y'' + y = 0 \). Nonhomogeneous equations often arise in real-world applications where some external force or influence impacts the system. This external influence creates the non-zero terms on the right-hand side of the equation. To solve these types of equations, we often find both a particular solution and a complementary solution, which we combine to determine the general solution.
General Solution
\( y'' + y = x \),
the general solution is constructed as:
- The particular solution: A specific solution to the nonhomogeneous part of the equation, for instance, \( y_{\mathrm{p}} = 2 \sin x + x \).
- The homogeneous solution, or complementary function: A solution to the corresponding homogeneous equation \( y'' + y = 0 \).
\[ y(x) = y_h(x) + y_{\mathrm{p}}(x) = c_1 \cos x + (c_2 + 2) \sin x + x \]
This solution represents the total behavior of the system described by the differential equation.
Initial Conditions
\[ y(0) = 0 , \quad y'(0) = 0 \]
These initial conditions specify the values of the function \( y(x) \) and its first derivative at \( x = 0 \). They help us determine the values of the arbitrary constants in the general solution. By substituting these conditions into the general solution, we apply them:
- Ensure that the solution meets physical or practical requirements.
- Provide the specific instance or behavior of the system described by the differential equation.
Homogeneous Equation
\[ y'' + y = 0 \]
is homogeneous. The solution to the homogeneous equation is important as it forms the complementary part of the general solution for a nonhomogeneous differential equation. Solving homogeneous equations involves finding solutions for a corresponding characteristic equation. They typically yield solutions that include arbitrary constants, which are determined using initial conditions. Understanding homogeneous equations is key to tackling more complex, real-world nonhomogeneous problems.
Characteristic Equation
\[ y'' + y = 0 \],
the characteristic equation is:
\[ r^2 + 1 = 0 \]
Here, the roots are complex, \( r = \pm i \), indicating oscillatory behavior. The solutions to the characteristic equation guide us to the homogeneous solution in the form:
- For real roots: Solutions include combinations of exponential functions.
- For complex roots: Solutions involve sinusoidal functions, such as \( \cos x \) and \( \sin x \).