Chapter 17: Problem 24
Find the general solution to the given Euler equation. Assume \(x>0\) throughout. $$4 x^{2} y^{\prime \prime}-16 x y^{\prime}+25 y=0$$
Short Answer
Expert verified
The general solution is \(y(x) = x^2 (C_1 \cos\left(\frac{3}{2} \ln(x)\right) + C_2 \sin\left(\frac{3}{2} \ln(x)\right))\).
Step by step solution
01
Identify the Type of Differential Equation
The given equation is an Euler differential equation, specifically, a second-order linear homogeneous equation: \[4x^2y'' - 16xy' + 25y = 0\] In general, Euler's equations have the form: \[a x^2 y'' + b x y' + c y = 0\] with constant coefficients.
02
Substitute with a Power Function
For Euler equations, we make the assumption that the solution is of the form \(y = x^m\). Then, the derivatives become: \[y' = m x^{m-1}\]\[y'' = m(m-1)x^{m-2}\]
03
Substitute Derivatives into the Equation
Substitute \(y = x^m\), \(y' = m x^{m-1}\), and \(y'' = m(m-1)x^{m-2}\) into the differential equation: \[4x^2(m(m-1)x^{m-2}) - 16x(m x^{m-1}) + 25x^m = 0\]
04
Simplify the Equation
Simplify each term to align powers of \(x\): \[4m(m-1)x^m - 16mx^m + 25x^m = 0\]Combine like terms: \[(4m(m-1) - 16m + 25)x^m = 0\]
05
Solve the Characteristic Equation
Extract the characteristic equation from the coefficients of \(x^m\): \[4m(m-1) - 16m + 25 = 0\]This simplifies to: \[4m^2 - 4m - 25 = 0\] Solve this quadratic equation using the quadratic formula: \[m = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]where \(a = 4\), \(b = -16\), and \(c = 25\).
06
Calculate Characteristic Roots
Apply the quadratic formula to find the roots: \[m = \frac{-(-16) \pm \sqrt{(-16)^2 - 4 \cdot 4 \cdot 25}}{2 \cdot 4}\]Simplify under the square root: \[m = \frac{16 \pm \sqrt{256 - 400}}{8}\]\[m = \frac{16 \pm \sqrt{-144}}{8}\]The roots are complex: \[m = \frac{16 \pm 12i}{8}\] This gives two roots: \(m_1 = 2 + \frac{3}{2}i\) and \(m_2 = 2 - \frac{3}{2}i\).
07
Formulate the General Solution
The general solution for an Euler equation with complex roots \(m = \alpha \pm \beta i\) is: \[y(x) = x^\alpha (C_1 \cos(\beta \ln(x)) + C_2 \sin(\beta \ln(x)))\]For the roots \(m_1 = 2 + \frac{3}{2}i\) and \(m_2 = 2 - \frac{3}{2}i\), \(\alpha = 2\) and \(\beta = \frac{3}{2}\).Thus, the solution is:\[y(x) = x^2 (C_1 \cos\left(\frac{3}{2} \ln(x)\right) + C_2 \sin\left(\frac{3}{2} \ln(x)\right))\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Second-order linear homogeneous equation
An Euler differential equation is a type of second-order linear homogeneous equation. These equations typically involve each term being multiplied by a power of the independent variable. The general form is:
For Euler equations, a common approach is to assume a power function solution \(y = x^m\). This assumption transforms the differential equation into an algebraic equation, making it easier to find solutions. Stay mindful that Euler's equations are popular for modeling problems with power-law behavior.
- \(a x^2 y'' + b x y' + c y = 0\)
For Euler equations, a common approach is to assume a power function solution \(y = x^m\). This assumption transforms the differential equation into an algebraic equation, making it easier to find solutions. Stay mindful that Euler's equations are popular for modeling problems with power-law behavior.
Characteristic equation
The characteristic equation is a key step in solving second-order linear homogeneous differential equations. It is derived from substituting the assumed solution into the differential equation.
For Euler equations, by substituting \(y = x^m\), the derivatives \(y'\) and \(y''\) become functions of \(m\). The derivatives are:
For Euler equations, by substituting \(y = x^m\), the derivatives \(y'\) and \(y''\) become functions of \(m\). The derivatives are:
- \(y' = m x^{m-1}\)
- \(y'' = m(m-1) x^{m-2}\)
- \(4m(m-1) - 16m + 25 = 0\)
Complex roots
The roots of the characteristic equation may be real or complex. When solving Euler's equation, you arrive at the quadratic characteristic equation:
- \(4m^2 - 16m + 25 = 0\)
- \(m = \frac{-(-16) \pm \sqrt{(-16)^2 - 4 \cdot 4 \cdot 25}}{2 \cdot 4}\)
- \(m_1 = 2 + \frac{3}{2}i\)
- \(m_2 = 2 - \frac{3}{2}i\)
General solution formulation
Formulating the general solution for an Euler differential equation with complex roots involves recognizing patterns in the solutions of second-order differentials. When the roots \(m = \alpha \pm \beta i\) are complex, the general solution is:
- \(y(x) = x^\alpha (C_1 \cos(\beta \ln(x)) + C_2 \sin(\beta \ln(x)))\)
- \(y(x) = x^2 \left(C_1 \cos\left(\frac{3}{2} \ln(x)\right) + C_2 \sin\left(\frac{3}{2} \ln(x)\right)\right)\)