Chapter 16: Problem 5
Solve the differential equations $$x \frac{d y}{d x}+2 y=1-\frac{1}{x}, \quad x>0$$
Short Answer
Expert verified
The solution is \( y = \frac{1}{2} - \frac{\ln |x|}{x^2} + \frac{C}{x^2} \).
Step by step solution
01
Identify the type of differential equation
The given differential equation is \( x \frac{dy}{dx} + 2y = 1 - \frac{1}{x} \). This is a linear first-order differential equation of the form \( P(x) \frac{dy}{dx} + Q(x)y = R(x) \). We can compare it to the standard linear form \( \frac{dy}{dx} + P(x)y = Q(x) \) to determine the best strategy for solving it.
02
Rewrite the equation in standard form
To bring the equation into standard form, divide every term by \( x \): \[ \frac{dy}{dx} + \frac{2}{x}y = \frac{1}{x} - \frac{1}{x^2}. \] Here, \( P(x) = \frac{2}{x} \) and \( Q(x) = \frac{1}{x} - \frac{1}{x^2} \).
03
Find the integrating factor
For a first-order linear differential equation, the integrating factor \( \mu(x) \) is given by \( e^{\int P(x) \, dx} \). So, calculate: \[ \mu(x) = e^{\int \frac{2}{x} \, dx} = e^{2 \ln|x|} = x^2. \]
04
Multiply through by the integrating factor
Multiply the entire equation by the integrating factor \( x^2 \): \[ x^2 \frac{dy}{dx} + 2xy = x - \frac{1}{x}. \] This simplifies using properties of logarithms and exponents.
05
Rewrite the left side as a derivative
Notice that the left side of the equation \( x^2 \frac{dy}{dx} + 2xy \) is the derivative of \( x^2 y \): \[ \frac{d}{dx}(x^2 y) = x - \frac{1}{x}. \] Rewrite the equation: \[ \frac{d}{dx}(x^2 y) = x - \frac{1}{x}. \]
06
Integrate both sides
Integrate both sides of the equation with respect to \( x \): \[ x^2 y = \int \left( x - \frac{1}{x} \right) \, dx. \] The integral is: \[ \int x \, dx - \int \frac{1}{x} \, dx = \frac{x^2}{2} - \ln |x| + C, \] where \( C \) is the constant of integration.
07
Solve for \( y \)
Substitute the result back to solve for \( y \): \[ x^2 y = \frac{x^2}{2} - \ln |x| + C. \] Divide everything by \( x^2 \) to find \( y \): \[ y = \frac{1}{2} - \frac{\ln |x|}{x^2} + \frac{C}{x^2}. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-Order Differential Equations
A first-order differential equation is an equation that involves the first derivative of a function. It has no higher derivatives, making it the simplest type of differential equations to solve. The general form helps us understand how these equations look:
Understanding the basic layout of these equations makes them easier to handle once we start using solution techniques like the integrating factor.
- General form: \( \frac{dy}{dx} = f(x,y) \)
- Linear form: \( \frac{dy}{dx} + P(x)y = Q(x) \)
Understanding the basic layout of these equations makes them easier to handle once we start using solution techniques like the integrating factor.
Integrating Factor
The integrating factor is a very effective tool for solving first-order linear differential equations. Its purpose is to make the equation easier to integrate, by transforming it into one that can be solved more directly. Here’s how it works:
This method is particularly powerful because it systematically reduces a differential equation to an integrable form, which is a cornerstone process in differential equation solutions.
- Given a linear differential equation: \( \frac{dy}{dx} + P(x)y = Q(x) \)
- The integrating factor \( \mu(x) \) is calculated as: \( e^{\int P(x)\, dx} \)
This method is particularly powerful because it systematically reduces a differential equation to an integrable form, which is a cornerstone process in differential equation solutions.
Linear Differential Equations
Linear differential equations, particularly first-order ones, are characterized by how their variables and derivatives are arranged in a linear manner. They can be recognized from their general form:
Linear differential equations are fundamental in many fields such as physics, engineering, and economics. They model a wide variety of phenomena due to their predictive power and straightforward methodology for solution. They help predict behaviors based on current states, represent starting points for more complex multi-variable models, and establish foundational principles in many disciplines.
- Form: \( \frac{dy}{dx} + P(x)y = Q(x) \)
Linear differential equations are fundamental in many fields such as physics, engineering, and economics. They model a wide variety of phenomena due to their predictive power and straightforward methodology for solution. They help predict behaviors based on current states, represent starting points for more complex multi-variable models, and establish foundational principles in many disciplines.