Chapter 15: Problem 33
Find the circulation and flux of the field \(\mathbf{F}\) around and across the closed semicircular path that consists of the semicircular arch \(\mathbf{r}_{1}(t)=(a \cos t) \mathbf{i}+(a \sin t) \mathbf{j}, 0 \leq t \leq \pi,\) followed by the line segment \(\mathbf{r}_{2}(t)=t \mathbf{i},-a \leq t \leq a\) $$\mathbf{F}=-y \mathbf{i}+x \mathbf{j}$$
Short Answer
Step by step solution
Understand the Path
Determine the Circulation
Determine the Flux
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Line Integrals
To calculate the circulation using a line integral, we use the formula:
- \( \oint_C \mathbf{F} \cdot d\mathbf{r} \)
- For the semicircular part \( \mathbf{r}_1(t) \), the directional components cancel out, leading to a result of zero.
- The same principle applies to the straight line part on the x-axis \( \mathbf{r}_2(t) \), and it also results in zero circulation.
Flux Calculation
To find the flux, you need to understand two things:
- The curl of the vector field \( abla \times \mathbf{F} \), which tells how much the field 'rotates' around points.
- The region \( D \) defined by the path, which in this exercise is the top half of a circle.
- \( \iint_D abla \times \mathbf{F} \cdot \mathbf{k} \, dA \)
- The exercise finds \( abla \times \mathbf{F} = 2 \mathbf{k} \), which denotes a constant rotational effect across the region.
- Then, the area \( \frac{1}{2} \pi a^2 \) of the semicircle is used.
Curl of a Vector Field
Think of curl as small vortices in a fluid flow where, if the water swirls, the presence of a curl is implied. In solid terms, the curl is represented as:
- \( abla \times \mathbf{F} \)
- The formula requires calculating the partial derivatives: \( abla \times \mathbf{F} = \frac{\partial}{\partial x}(x) - \frac{\partial}{\partial y}(-y) \).
- A result of \( 2 \mathbf{k} \) shows a consistent rotational component across the plane.