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Find a parametrization of the surface. (There are many correct ways to do these, so your answers may not be the same as those in the back of the text.) The paraboloid \(z=x^{2}+y^{2}, z \leq 4\)

Short Answer

Expert verified
The parametrization is \(\mathbf{r}(r, \theta) = (r\cos(\theta), r\sin(\theta), r^2)\) with \(0 \leq r \leq 2\) and \(0 \leq \theta \leq 2\pi\).

Step by step solution

01

Identify the Surface

The given surface is a paraboloid described by the equation \(z = x^2 + y^2\). We are also told that \(z \leq 4\). This suggests a paraboloid extending upwards along the z-axis and capping at \(z = 4\).
02

Switch to Cylindrical Coordinates

For parametrization, using cylindrical coordinates ([r, θ, z]) is convenient. We transform \(x = r\cos(\theta)\) and \(y = r\sin(\theta)\). The parameter \(r\) will range over the domain ensuring \(z = x^2 + y^2 \leq 4\), which implies \(r^2 \leq 4\) or \(0 \leq r \leq 2\). Meanwhile, \(\theta\) covers \([0, 2\pi]\).
03

Define the Parameters

We'll use \(r\) and \(\theta\) as parameters: set \(x(r, \theta) = r\cos(\theta)\), \(y(r, \theta) = r\sin(\theta)\), and \(z(r, \theta) = r^2\). The ranges for these parameters are \(0 \leq r \leq 2\) and \(0 \leq \theta \leq 2\pi\).
04

Combine to Parametrization Function

Combine the expressions into a parametrization: \[\mathbf{r}(r, \theta) = (r\cos(\theta), r\sin(\theta), r^2)\] where \(0 \leq r \leq 2\) and \(0 \leq \theta \leq 2\pi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cylindrical Coordinates
Cylindrical coordinates are a three-dimensional coordinate system that extends polar coordinates into three dimensions by incorporating height along an additional axis. These coordinates are denoted as \(r, \theta, z\). Here, \(r\) represents the radial distance from the origin in the xy-plane, \(\theta\) is the angular position measured from the positive x-axis, and \(z\) corresponds to the height above the xy-plane.

This system is particularly convenient for dealing with surfaces that exhibit rotational symmetry around one of the axes, like a paraboloid. In our given exercise, converting from Cartesian coordinates to cylindrical coordinates involves these transformations:
  • \(x = r\cos(\theta)\)
  • \(y = r\sin(\theta)\)
  • \(z = z\)
By using these transformations, we can express surfaces and solids more naturally when they are symmetrical around an axis. This simplification makes many integration and differentiation problems much easier to handle.
Paraboloid Surface
A paraboloid is a surface that can be generated by rotating a parabola around its axis of symmetry. In our scenario, we have a surface defined by \(z = x^2 + y^2\), which outlines a paraboloid opening upwards along the z-axis. Imagine a bowl shape that becomes wider as it extends outward from the z-axis.

The term 'paraboloid' indicates that the cross-sections parallel to the xy-plane are circles, while those parallel to any plane containing the z-axis are parabolas. For the paraboloid given, circular cross-sections get larger as z increases, until the limit \(z \leq 4\). At this boundary, the paraboloid stops extending as a solid shape and forms a circular edge.

Understanding how the paraboloid behaves at its limits and boundaries is crucial when you parameterize it. With cylindrical coordinates, we manipulate and handle these shapes in an intuitive manner.
Surface Equations
Surface equations describe how points in a 3D space come together to form a surface. For the paraboloid \(z = x^2 + y^2\), this equation dictates all the points \( (x, y, z) \) that lie on the surface.

By parameterizing the surface with cylindrical coordinates, we reformulate the original equation into a set of parametric equations, making it easy to handle. We have already translated points on this surface with expressions:
  • \(x = r\cos(\theta)\)
  • \(y = r\sin(\theta)\)
  • \(z = r^2\)
These parametric equations allow us to define any point on the surface using only two parameters, \(r\) and \(\theta\). The parameter \(r\) is limited to \([0, 2]\) because \(r^2 \leq 4\) aligns with \(z \leq 4\). Meanwhile, \(\theta\) spans from \([0, 2\pi]\) for a complete revolution in the xy-plane.

This approach leads to a clean and compact form, marking its elegance in expressing and mining the intricacies of the surface, beneficial in solving complex problems related to geometric shapes.

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Most popular questions from this chapter

A revealing experiment By experiment, you find that a force field \(\mathbf{F}\) performs only half as much work in moving an object along path \(C_{1}\) from \(A\) to \(B\) as it does in moving the object along path \(C_{2}\) from \(A\) to \(B .\) What can you conclude about F? Give reasons for your answer.

Let \(S\) be the portion of the cylinder \(y=\ln x\) in the first octant whose projection parallel to the \(y\) -axis onto the \(x z\) -plane is the rectangle \(R_{k}: 1 \leq x \leq e, 0 \leq z \leq 1 .\) Let \(n\) be the unit vector normal to \(S\) that points away from the \(x z\) -plane. Find the flux of \(\mathbf{F}=2 y \mathbf{j}+z \mathbf{k}\) through \(S\) in the direction of \(\mathbf{n}\)

Evaluating a work integral two ways Let \(\mathbf{F}=\nabla\left(x^{3} y^{2}\right)\) and let \(C\) be the path in the \(x y\) -plane from (-1,1) to (1,1) that consists of the line segment from (-1,1) to (0,0) followed by the line segment from (0,0) to (1,1) . Evaluate \(\int_{C} \mathbf{F} \cdot d \mathbf{r}\) in two ways. a. Find parametrizations for the segments that make up \(C\) and evaluate the integral. b. Use \(f(x, y)=x^{3} y^{2}\) as a potential function for \(\mathbf{F}\)

Use a CAS and Green's Theorem to find the counterclockwise circulation of the field \(\mathbf{F}\) around the simple closed curve C. Perform the following CAS steps. a. Plot \(C\) in the \(x y\) -plane. b. Determine the integrand (aN/ax) \(-(a M /\) ay ) for the tangential form of Green's Theorem. c. Determine the (double integral) limits of integration from your plot in part (a), and evaluate the curl integral for the circulation. $$\mathbf{F}=x e^{y} \mathbf{i}+\left(4 x^{2} \ln y\right) \mathbf{j}$$ C: The triangle with vertices \((0,0),(2,0),\) and (0,4)

Find the area of the surfaces. The surface cut from the bottom of the paraboloid \(z=x^{2}+y^{2}\) by the plane \(z=3\)

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