/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Find an equation for the level s... [FREE SOLUTION] | 91Ó°ÊÓ

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Find an equation for the level surface of the function through the given point. $$g(x, y, z)=\sqrt{x^{2}+y^{2}+z^{2}}, \quad(1,-1, \sqrt{2})$$

Short Answer

Expert verified
The level surface equation is \(x^2 + y^2 + z^2 = 4\).

Step by step solution

01

Understand the Level Surface

To find a level surface equation for the function \(g(x, y, z) = \sqrt{x^2 + y^2 + z^2}\) through the point \((1, -1, \sqrt{2})\), we need to evaluate the function at this point to determine the level.
02

Evaluate the Function at the Given Point

Substitute \((1, -1, \sqrt{2})\) into the function: \[ g(1, -1, \sqrt{2}) = \sqrt{1^2 + (-1)^2 + (\sqrt{2})^2} = \sqrt{1 + 1 + 2} = \sqrt{4} = 2 \]This means the level value \( c = 2 \).
03

Write the Equation for the Level Surface

A level surface is given by the equation \( g(x, y, z) = c \). Since \( c = 2 \), the level surface equation is:\[ \sqrt{x^2 + y^2 + z^2} = 2 \]
04

Simplify the Equation

To simplify, square both sides to remove the square root:\[ x^2 + y^2 + z^2 = 4 \]This equation represents a sphere centered at the origin with a radius 2, which is the level surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Level Surface
In multivariable calculus, a level surface is a three-dimensional analogue of a level curve. A level surface can be visualized as the set of all points that satisfy a given equation of a function at a particular constant value. For a function \( g(x, y, z) \), a level surface is formed by points \((x, y, z)\) where the function \( g(x, y, z) \) equals some constant \( c \).
In the original exercise, for the function \( g(x, y, z) = \sqrt{x^2 + y^2 + z^2} \), the level surface through the point \((1, -1, \sqrt{2})\) is determined by evaluating the function at the point to find the level constant \( c \). This gives the equation of a sphere, \( x^2 + y^2 + z^2 = 4 \), which represents the level surface satisfying \( g(x, y, z) = 2 \).
Level surfaces are useful in many fields such as physics, engineering, and geography, where they help describe phenomena like temperature and pressure distributions.
Evaluating Multivariable Functions
To evaluate a multivariable function at a specific point, substitute the coordinates of the point into the function and perform the operations indicated. This evaluates the function to a specific constant. It's a fundamental capability when dealing with functions of several variables.
For the exercise, the function given is \( g(x, y, z) = \sqrt{x^2 + y^2 + z^2} \). We substitute the point \((1, -1, \sqrt{2})\) into the function:
  • Replace \( x \) with 1
  • Replace \( y \) with -1
  • Replace \( z \) with \( \sqrt{2} \)
The function evaluates to \( \sqrt{4} \), which is \( 2 \).
This shows that the level constant \( c \) is 2, which is used to describe the level surface.
Spherical Coordinates
Spherical coordinates provide an alternative to Cartesian coordinates for describing locations in three-dimensional space. They are particularly useful in situations where symmetry about a point, like the origin, simplifies calculations. Points in 3D are represented using radial distance, polar angle, and azimuthal angle, typically denoted as \((\rho, \phi, \theta)\).
For the function \( g(x, y, z) = \sqrt{x^2 + y^2 + z^2} \), the level surface equation \( x^2 + y^2 + z^2 = 4 \) hints at a simple transformation into spherical coordinates, as \( \rho = 2 \) translates to a sphere with radius 2. This uses the geometric interpretation of \( \rho \) as the distance from the origin.
  • \( \rho \: = \: \sqrt{x^2 + y^2 + z^2} \)
  • The angle \( \phi \) (polar angle) measures elevation from the positive z-axis.
  • The angle \( \theta \) (azimuthal angle) measures the radial distance in the xy-plane from the x-axis.
Learning to switch between coordinate systems can offer powerful insights and simplify problem-solving in multivariable calculus.
Vector Functions
Vector functions, often represented as \( \mathbf{F}(t) = \langle x(t), y(t), z(t) \rangle \), describe the motion of points in space as the parameter \( t \) changes. Such functions are essential in understanding paths, velocity, and acceleration of objects.
Although the exercise centers on level surfaces, the idea of vector functions is closely related. Considering the sphere \( x^2 + y^2 + z^2 = 4 \), a simple parametric representation for points on this sphere can be formulated. For instance, using the parametric equations:
  • \( x = 2 \sin(\phi) \cos(\theta) \)
  • \( y = 2 \sin(\phi) \sin(\theta) \)
  • \( z = 2 \cos(\phi) \)
These equations describe a vector function that traces the sphere's surface as \( \theta \) and \( \phi \) vary.
Vector functions help visualize and compute different properties related to curves and surfaces in multivariable calculus. Understanding them is crucial for analyzing the dynamics of multidimensional movements.

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