Chapter 12: Problem 21
Show that if \(\mathbf{u}\) is a unit vector, then the are length parameter along the line \(\mathbf{r}(t)=P_{0}+t \mathbf{u}\) from the point \(P_{0}\left(x_{0}, y_{0}, z_{0}\right),\) where \(t=0,\) is \(t\) itself.
Short Answer
Expert verified
The arc length is parameterized by \( t \), as the unit vector keeps the scaling consistent with \( t \).
Step by step solution
01
Identify the Components of the Line Equation
The line is given by the vector equation \( \mathbf{r}(t) = P_0 + t \mathbf{u} \), where \( P_0 = (x_0, y_0, z_0) \) is a point on the line and \( \mathbf{u} \) is the direction vector. Since \( \mathbf{u} \) is a unit vector, its magnitude is 1.
02
Calculate the Distance Function
The distance from the starting point \( P_0 \) at \( t=0 \) to the point \( \mathbf{r}(t) \) is the length of the vector \( \mathbf{r}(t) - P_0 \), which simplifies to \( t \mathbf{u} \). The magnitude of this vector is \( \| t \mathbf{u} \| = |t| \times \| \mathbf{u} \| \).
03
Substitute Unit Vector Property
Since \( \mathbf{u} \) is a unit vector, \( \| \mathbf{u} \| = 1 \). Thus, the magnitude of \( t \mathbf{u} \) simplifies to \( |t| \). In this context, since \( t \) is a parameter we can assume it is positive, so \( |t| = t \).
04
Conclude the Parameterization
The arc length from the point \( P_0 \) along the line for a given \( t \) is simply \( t \), because the vector's magnitude over the unit vector's direction \( \mathbf{u} \) was not altered. Therefore, the arc length parameter along the line is \( t \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Unit Vector
A unit vector is a vector that has a magnitude (or length) of 1. It is often used to indicate direction without reference to magnitude. In mathematical terms, if a vector \( \mathbf{v} = (v_x, v_y, v_z) \), then it is a unit vector if \( \|\mathbf{v}\| = 1 \).
The unit vector in the direction of a non-zero vector \( \mathbf{v} \) can be found by dividing each component of the vector by its magnitude. The formula is:
\[ \mathbf{u} = \frac{\mathbf{v}}{\|\mathbf{v}\|} \]
Unit vectors are frequently used in physics and engineering to represent directions. Amongst the most commonly known unit vectors are the standard basis vectors \( \mathbf{i} = (1,0,0) \), \( \mathbf{j} = (0,1,0) \), and \( \mathbf{k} = (0,0,1) \), which represent directions along the x, y, and z axes, respectively.
The unit vector in the direction of a non-zero vector \( \mathbf{v} \) can be found by dividing each component of the vector by its magnitude. The formula is:
\[ \mathbf{u} = \frac{\mathbf{v}}{\|\mathbf{v}\|} \]
Unit vectors are frequently used in physics and engineering to represent directions. Amongst the most commonly known unit vectors are the standard basis vectors \( \mathbf{i} = (1,0,0) \), \( \mathbf{j} = (0,1,0) \), and \( \mathbf{k} = (0,0,1) \), which represent directions along the x, y, and z axes, respectively.
Vector Equation
The vector equation of a line provides a representation of the line in terms of vectors. For any line in a three-dimensional space, a common form of the vector equation is:
\[ \mathbf{r}(t) = \mathbf{P}_0 + t \mathbf{u} \]
Here:
As \( t \) changes, the vector equation traces out the line. The equation essentially describes how to start at \( \mathbf{P}_0 \) and move along the line in the direction of the vector \( \mathbf{u} \).
The vector equation approach is particularly useful because it allows problems involving lines to be handled with vector operations, simplifying calculations for intersections and other analyses.
\[ \mathbf{r}(t) = \mathbf{P}_0 + t \mathbf{u} \]
Here:
- \( \mathbf{P}_0 \) is a point on the line, given as a position vector \((x_0, y_0, z_0)\)
- \( t \) is a scalar parameter that varies over the real numbers
- \( \mathbf{u} \) is the direction vector of the line
As \( t \) changes, the vector equation traces out the line. The equation essentially describes how to start at \( \mathbf{P}_0 \) and move along the line in the direction of the vector \( \mathbf{u} \).
The vector equation approach is particularly useful because it allows problems involving lines to be handled with vector operations, simplifying calculations for intersections and other analyses.
Magnitude of a Vector
The magnitude of a vector, often referred to as the length or norm, measures how long the vector is, or the distance the vector extends in space from the origin. For a vector \( \mathbf{v} = (v_x, v_y, v_z) \), its magnitude is calculated using the formula:
\[ \|\mathbf{v}\| = \sqrt{v_x^2 + v_y^2 + v_z^2} \]
Magnitude is always a non-negative number because it is derived from squaring the vector components before summing them.
If you imagine a vector as an arrow pointing from the origin of a graph to the point \((v_x, v_y, v_z)\), then the magnitude is simply the length of that arrow.
The magnitude is important for another reason: it plays a critical role in normalizing vectors. Normalizing a vector refers to the process of converting it to a unit vector, by ensuring its magnitude is 1, while its direction remains the same.
\[ \|\mathbf{v}\| = \sqrt{v_x^2 + v_y^2 + v_z^2} \]
Magnitude is always a non-negative number because it is derived from squaring the vector components before summing them.
If you imagine a vector as an arrow pointing from the origin of a graph to the point \((v_x, v_y, v_z)\), then the magnitude is simply the length of that arrow.
The magnitude is important for another reason: it plays a critical role in normalizing vectors. Normalizing a vector refers to the process of converting it to a unit vector, by ensuring its magnitude is 1, while its direction remains the same.
Line Parameterization
Line parameterization involves expressing a line in terms of a parameter, often denoted as \( t \). In vector calculus, parametrizing a line simplifies working with curves and paths in space, as a single equation can represent an entire line.
Consider the vector equation \( \mathbf{r}(t) = \mathbf{P}_0 + t \mathbf{u} \):
The concept of parameterization is crucial when dealing with curves and paths because it translates the geometric idea of a line into an algebraic form that can be manipulated mathematically. Specifically, for arc length, having a unit vector as the direction simplifies calculations, transforming the parameter \( t \) into a direct measure of length along the line.
Consider the vector equation \( \mathbf{r}(t) = \mathbf{P}_0 + t \mathbf{u} \):
- \( \mathbf{P}_0 \) is the starting point of the line.
- \( \mathbf{u} \) is the direction vector, which indicates the direction in which the line extends.
- \( t \) is the parameter that allows you to "walk" along the line.
The concept of parameterization is crucial when dealing with curves and paths because it translates the geometric idea of a line into an algebraic form that can be manipulated mathematically. Specifically, for arc length, having a unit vector as the direction simplifies calculations, transforming the parameter \( t \) into a direct measure of length along the line.